/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 157 When gaseous \(\mathrm{F}_{2}\) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

When gaseous \(\mathrm{F}_{2}\) and solid \(\mathrm{I}_{2}\) are heated to high temperatures, the \(\mathrm{I}_{2}\) sublimes and gaseous iodine heptafluoride forms. If 350. torr of \(\mathrm{F}_{2}\) and \(2.50 \mathrm{~g}\) of solid \(\mathrm{I}_{2}\) are put into a 2.50 - \(\mathrm{L}\) container at \(250 . \mathrm{K}\) and the container is heated to \(550 . \mathrm{K},\) what is the final pressure (in torr)? What is the partial pressure of \(\mathrm{I}_{2}\) gas?

Short Answer

Expert verified
Final pressure is 485.4 torr. Partial pressure of \mathrm{I}_{2} is 135.4 torr.

Step by step solution

01

- Determine the number of moles of each gas

First, calculate the moles of \mathrm{I}_{2} using its molar mass (\ M_{I2} = 253.8 \ \text{g/mol}). $$n_{I2} = \frac{2.50 \ \text{g}}{253.8 \ \text{g/mol}} = 0.00985 \ \text{mol}$$
02

- Use Ideal Gas Law to find pressure of \mathrm{I}_{2} gas

Using the ideal gas law: $$P=nRT/V$$ at the heated condition (550 K), we calculate the partial pressure of \mathrm{I}_{2}$$P_{I2} = \frac{n_{I2}RT}{V}$$ where $$R = 0.0821 \ \text{Latm/Kmol}, T = 550 \ \text{K}, V = 2.50 \ \text{L}$$. Hence, $$P_{I2} = \frac{0.00985 \ \text{mol} \times 0.0821 \ \text{Latm/Kmol} \times 550 \ \text{K}}{2.50 \ \text{L}} = 0.178 \ \text{atm} = 135.4 \ \text{torr}$$ (converting to torr using 1 atm = 760 torr).
03

- Calculate final pressure

Add the initial pressure of \mathrm{F}_{2} (350 torr) to the partial pressure of \mathrm{I}_{2} (135.4 torr): $$P_{final} = 350 \ \text{torr} + 135.4 \ \text{torr} = 485.4 \ \text{torr}$$.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Gas Laws
Gas laws are essential for understanding the behavior of gases under different conditions. They help us predict how gases will respond to changes in pressure, volume, and temperature. The most important gas laws include Boyle's Law, Charles's Law, and the Ideal Gas Law.

Boyle's Law states that the pressure of a gas is inversely proportional to its volume when temperature is constant. Charles's Law tells us that the volume of a gas is directly proportional to its temperature when pressure is constant. The Ideal Gas Law combines these principles and is represented by the equation \[ PV = nRT \] where:
  • P is the pressure of the gas
  • V is the volume
  • n is the number of moles
  • R is the ideal gas constant
  • T is the temperature in Kelvin
In our exercise, we use the Ideal Gas Law to calculate the partial pressure of iodine gas ( \text{I}_{2}) after it has sublimed and vaporized.
Partial Pressure Concept
Partial pressure refers to the pressure that a single gas in a mixture of gases would exert if it occupied the entire volume by itself. It is an important concept when dealing with gas mixtures, like in our exercise with iodine ( \text{I}_{2}) and fluorine ( \text{F}_{2}) gases.

Dalton's Law of Partial Pressures states that the total pressure of a gas mixture is equal to the sum of the partial pressures of each individual gas in the mixture:\[ P_{total} = P_{1} + P_{2} + ... + P_{n} \]Using this concept, we first calculate the partial pressure of \text{I}_{2} gas at the elevated temperature using the Ideal Gas Law. After determining this, we add it to the initial pressure of \text{F}_{2} to find the final total pressure inside the container.
Moles Calculation and Its Importance
Moles calculation is crucial for understanding the quantity of a substance involved in a reaction. In chemistry, the mole is a basic unit used to measure the amount of a substance. It links the microscopic world of atoms and molecules to the macroscopic quantities we can observe and measure.

For our exercise, we start by calculating the moles of solid iodine (\text{I}_{2}) using its molar mass. The moles of a substance can be calculated using the equation:\[ n = \frac{mass}{molar \text{mass}} \]In our case, using the mass of \text{I}_{2} and its molar mass, we find the moles of iodine. These calculated moles are then used in the Ideal Gas Law to find the partial pressure of \text{I}_{2} gas. Accurate moles calculation is important as it influences the entire subsequent computation for pressure and partial pressure.

In summary, by mastering gas laws, understanding partial pressures, and accurately calculating moles, students can better solve and understand problems involving gas reactions and behaviors.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A gaseous organic compound containing only carbon, hydrogen, and nitrogen is burned in oxygen gas, and the volume of each reactant and product is measured under the same conditions of temperature and pressure. Reaction of four volumes of the compound produces 4 volumes of \(\mathrm{CO}_{2}, 2\) volumes of \(\mathrm{N}_{2},\) and 10 volumes of water vapor. (a) How many volumes of \(\mathrm{O}_{2}\) were required? (b) What is the empirical formula of the compound?

A mixture of gaseous disulfur difluoride, dinitrogen tetrafluoride, and sulfur tetrafluoride is placed in an effusion apparatus. (a) Rank the gases in order of increasing effusion rate. (b) Find the ratio of effusion rates of disulfur difluoride and dinitrogen tetrafluoride. (c) If gas \(\mathrm{X}\) is added, and it effuses at 0.935 times the rate of sulfur tetrafluoride, find the molar mass of X.

In the \(19^{\text {th }}\) century, \(\mathrm{J}\). \(\mathrm{B}\). A. Dumas devised a method for finding the molar mass of a volatile liquid from the volume, temperature, pressure, and mass of its vapor. He placed a sample of such a liquid in a flask that was closed with a stopper fitted with a narrow tube, immersed the flask in a hot water bath to vaporize the liquid, and then cooled the flask. Find the molar mass of a volatile liquid from the following: Mass of empty flask \(=65.347 \mathrm{~g}\) Mass of flask filled with water at \(25^{\circ} \mathrm{C}=327.4 \mathrm{~g}\) Density of water at \(25^{\circ} \mathrm{C}=\) \(0.997 \mathrm{~g} / \mathrm{mL}\) Mass of flask plus condensed unknown liquid \(=65.739 \mathrm{~g}\) Barometric pressure \(=101.2 \mathrm{kPa}\) Temperature of water bath \(=99.8^{\circ} \mathrm{C}\)

A sample of a liquid hydrocarbon known to consist of molecules with five carbon atoms is vaporized in a 0.204 -L flask by immersion in a water bath at \(101^{\circ} \mathrm{C}\). The barometric pressure is 767 torr, and the remaining gas weighs \(0.482 \mathrm{~g}\). What is the molecular formula of the hydrocarbon?

A weather balloon containing \(600 .\) L of He is released near the equator at 1.01 atm and \(305 \mathrm{~K}\). It rises to a point where conditions are 0.489 atm and \(218 \mathrm{~K}\) and eventually lands in the northern hemisphere under conditions of 1.01 atm and \(250 \mathrm{~K}\). If one-fourth of the helium leaked out during this journey, what is the volume (in L) of the balloon at landing?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.