Chapter 24: Problem 138
Determine the age of a rock containing \(0.065 \mathrm{~g}\) of uranium-238 \(\left(t_{1 / 2}=4.5 \times 10^{9} \mathrm{yr}\right)\) and \(0.023 \mathrm{~g}\) of lead-206. (Assume that all the lead- 206 came from \({ }^{238} \mathrm{U}\) decay.
Short Answer
Expert verified
The age of the rock is approximately 2.2 billion years.
Step by step solution
01
- Understand the decay process
Uranium-238 \text{(}^{238}\text{U}\text{)} decays into Lead-206 \text{(}^{206}\text{Pb}\text{)} through a series of steps. Given the half-life, we can use the decay formula: \[ N(t) = N_0 e^{-\frac{t}{\tau}} \] where \text{N(t)} is the quantity of \text{Uranium-238} at time \text{t}, \text{N}_0 is the original quantity, and \[ \tau = \frac{ t_{1/2}}{\text{ln}(2)} \] The number of moles will help us determine the original quantity.
02
- Convert amounts to moles
The molar mass of Uranium-238 is approximately 238 g/mol and that of Lead-206 is approximately 206 g/mol. Convert the given masses to moles: \(n_{U} = \frac{ 0.065~ \text{g}}{238~ \text{g/mol}} \approx 2.73 \times 10^{-4} \text{mol} \) \(n_{Pb} = \frac{0.023~ \text{g}}{206~ \text{g/mol}} \approx 1.12 \times 10^{-4} \text{mol} \)
03
- Determine initial amount of Uranium-238
Since all the Lead-206 \text{(}^{206}\text{Pb}\text{)} came from the Uranium-238 \text{(}^{238}\text{U}\text{)} decay, the initial amount of Uranium-238 can be determined by: \(n_{0} = n_{Pb} + n_{U} \approx 1.12 \times 10^{-4}\text{ mol} + 2.73 \times 10^{-4} \text{mol} \approx 3.85 \times 10^{-4} \text{mol} \)
04
- Use the decay formula to find time
Using the decay formula and solving for time: \( N(t) = N_{0} e^{-\frac{t}{\tau}} \implies \frac{n_{U}}{n_{0}} = e^{-\frac{t}{\tau}}\) \(\frac{2.73 \times 10^{-4}}{3.85 \times 10^{-4}} = e^{-\frac{t}{(4.5 \times 10^9)/\text{ln}(2)}}\)
05
- Solving for time
Isolate \text{t}: \(\text{ln} \frac{2.73 \times 10^{-4}}{3.85 \times 10^{-4}} = -\frac{t}{ \tau}\) \(\text{ln}(0.709)= -\frac{t}{(4.5 \times 10^9)/ \text{ln} 2} \approx -0.344\) \(t \approx -0.344 \times -6.49 \times 10^9 \approx 2.2 \times 10^{9} \text{ years}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Radioactive Decay
Understanding radioactive decay is essential for solving problems related to Uranium-Lead dating. Radioactive decay is a random process in which an unstable atomic nucleus loses energy by emitting radiation. In the context of this problem, Uranium-238 (\(^{238}\text{U}\)) decays into Lead-206 (\(^{206}\text{Pb}\)) through a series of steps.
This decay process can be expressed with the formula: \[ N(t) = N_0 e^{-\frac{t}{\tau}} \] Here, \( N(t) \)- is the quantity of Uranium-238 at time \( t \), \( N_0 \)- is the original quantity of Uranium-238, and \( \tau = \frac{t_{1/2}}{ \text{ln}(2)} \)- is the mean lifetime of Uranium-238. Understanding this concept helps in calculating how much of the original material has decayed over a given period.
This decay process can be expressed with the formula: \[ N(t) = N_0 e^{-\frac{t}{\tau}} \] Here, \( N(t) \)- is the quantity of Uranium-238 at time \( t \), \( N_0 \)- is the original quantity of Uranium-238, and \( \tau = \frac{t_{1/2}}{ \text{ln}(2)} \)- is the mean lifetime of Uranium-238. Understanding this concept helps in calculating how much of the original material has decayed over a given period.
- Radioactive isotopes transform into stable isotopes through decay.
- This transformation rate is predictable and is expressed through mathematical formulas.
Half-Life Calculation
Half-life is an important concept in radioactive decay. It is the time required for half of the radioactive nuclei in a sample to decay. For Uranium-238, the half-life (\( t_{1/2} \)) is 4.5 billion years.
The relationship between the half-life and decay constant is given by: \[ \tau = \frac{ t_{1/2}}{\text{ln}(2)} \] Where \ \text{ln} \ represents the natural logarithm.In this exercise:
The relationship between the half-life and decay constant is given by: \[ \tau = \frac{ t_{1/2}}{\text{ln}(2)} \] Where \ \text{ln} \ represents the natural logarithm.In this exercise:
- We will use the half-life of Uranium-238 to determine the age of the rock sample.
- By comparing the remaining amount of Uranium-238 to the initial quantity, we can estimate the time elapsed.
Isotope Geochemistry
Isotope geochemistry deals with the isotopic composition of elements within the Earth's crust. Uranium-238 decays to Lead-206, and this transformation serves as the basis for Uranium-Lead dating.
Isotope geochemistry provides insights into geological processes by examining isotopic ratios. In the given exercise:
Isotope geochemistry provides insights into geological processes by examining isotopic ratios. In the given exercise:
- We start by determining the amount of Lead-206 and Uranium-238 in the rock.
- The initial amount of Uranium-238 can be inferred by adding the present Uranium-238 and Lead-206 amounts, acknowledging that all Lead-206 came from Uranium-238 decay.
Molar Mass
Molar mass is the mass of one mole of a substance, usually expressed in grams per mole (g/mol). It is used to convert between the mass of a substance and the amount of substance in moles. In our exercise, we needed to convert the given masses of Uranium-238 and Lead-206 to moles.
For Uranium-238, the molar mass is 238 g/mol, and for Lead-206, it is 206 g/mol. Using these values, we can calculate the number of moles (\(n\)):\[ n_{U} = \frac{0.065\text{ g}}{238\text{ g/mol}} \approx 2.73 \times 10^{-4} \text{ mol} \]\[ n_{Pb} = \frac{ 0.023\text{ g}}{206\text{ g/mol}} \approx 1.12 \times 10^{-4} \text{ mol} \]This conversion is essential to determine the initial amount of Uranium-238 accurately.
For Uranium-238, the molar mass is 238 g/mol, and for Lead-206, it is 206 g/mol. Using these values, we can calculate the number of moles (\(n\)):\[ n_{U} = \frac{0.065\text{ g}}{238\text{ g/mol}} \approx 2.73 \times 10^{-4} \text{ mol} \]\[ n_{Pb} = \frac{ 0.023\text{ g}}{206\text{ g/mol}} \approx 1.12 \times 10^{-4} \text{ mol} \]This conversion is essential to determine the initial amount of Uranium-238 accurately.
- It allows calculation of chemical quantities from physical measurements.
- Essential for understanding reactions and transformations in geochemical processes.