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In \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3},\) the \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) ion absorbs visible light in the blue-violet range, and the compound is yellow- orange. In \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right] \mathrm{Br}_{3}\), the \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) ion absorbs visible light in the red range, and the compound is blue-gray. Explain these differences in light absorbed and compound color.

Short Answer

Expert verified
Different ligand field strengths result in different absorbed wavelengths and observed colors.

Step by step solution

01

Identify the colors absorbed by each complex ion

Determine the colors of visible light absorbed by the given complex ions. For \([\mathrm{Cr}(\mathrm{NH}_{3})_{6}]^{3+}\), it absorbs light in the blue-violet range, while for \([\mathrm{Cr}(\mathrm{H}_{2} \mathrm{O})_{6}]^{3+}\), it absorbs light in the red range.
02

Determine the complementary colors

Understand that the color observed for a compound is the complementary color of the light absorbed. So, if \([\mathrm{Cr}(\mathrm{NH}_{3})_{6}]^{3+}\) absorbs blue-violet, it appears yellow-orange. If \([\mathrm{Cr}(\mathrm{H}_{2} \mathrm{O})_{6}]^{3+}\) absorbs red, it appears blue-gray.
03

Analyze the ligand field strength

Compare the field strengths of the ligands. NH3 is a stronger field ligand than H2O, which means it causes a larger splitting of the d-orbitals in \([\mathrm{Cr}(\mathrm{NH}_{3})_{6}]^{3+}\) compared to \([\mathrm{Cr}(\mathrm{H}_{2} \mathrm{O})_{6}]^{3+}\).
04

Relate field strength to color absorption

Stronger field ligands like NH3 result in the absorption of higher energy (shorter wavelength) light, which is blue-violet. Weaker field ligands like H2O result in the absorption of lower energy (longer wavelength) light, which is red.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Color Absorption
Color absorption in transition metal complexes is a result of the interaction between light and the electrons in the d-orbitals of the metal ion. When light hits these complexes, certain wavelengths are absorbed, promoting electrons from lower energy d-orbitals to higher energy d-orbitals. This process is known as d-d transitions. The specific wavelength that is absorbed depends on the difference in energy between these orbitals, which is influenced by the ligands surrounding the metal ion.

The term 'visible light' refers to the range of electromagnetic radiation that can be detected by the human eye, spanning wavelengths from about 400 to 700 nm. For example, in the complex \(\begin{bmatrix}Cr(NH_3)_6\begin{bmatrix} ^{3+}\begin{bmatrix}\right)\right\right\), blue-violet light is absorbed, which corresponds to higher energy. Meanwhile, in \(\begin{bmatrix}Cr(H_2O)_6\begin{bmatrix} ^{3+}\right)\right\), red light is absorbed, corresponding to lower energy.

This absorption of specific wavelengths directly influences the color we perceive, due to the phenomenon of complementary colors.
Complementary Colors
Complementary colors are pairs of colors that, when combined, cancel each other out. This means they produce a grayscale color like white or black. In the context of light absorption in complexes, the color we see is the complementary color of the light absorbed. For instance, if a complex absorbs blue-violet light, the color we see is yellow-orange.

To find the complementary color, one must look at a color wheel where opposite colors are complementary. For \(\begin{bmatrix}Cr(NH_3)_6\begin{bmatrix} ^{3+}\right)\right\), since it absorbs blue-violet light, its complementary color is yellow-orange, making the compound appear yellow-orange. Conversely, for \(\begin{bmatrix}Cr(H_2O)_6\begin{bmatrix} ^{3+}\right)\right\), absorbing red light means the complementary color is blue-gray, making the compound appear blue-gray.

Understanding complementary colors helps to predict and explain the colors observed in different chemical compounds.
Ligand Field Strength
The strength of the field created by ligands around a metal ion significantly influences the color absorption of metal complexes. Ligand Field Strength (also known as Ligand Field Splitting) refers to the difference in energy between the d-orbitals of the metal ion caused by the presence of ligands.

The ability of a ligand to split the d-orbital energy levels of a metal ion is influenced by the nature of the ligand itself. Strong field ligands, such as NH3 (ammonia), cause a large energy splitting, resulting in the absorption of light at higher energy (shorter wavelengths, like blue-violet). On the other hand, weaker field ligands, such as H2O (water), cause smaller energy splitting, resulting in the absorption of light at lower energy (longer wavelengths, like red).

In summary, the field strength of ligands is a crucial factor in determining the specific light wavelength absorbed, and thus, the observed color of the metal complex.
Complex Ions
Complex ions are formed when a central metal ion is surrounded by molecules or ions called ligands. These ligands can either be neutral molecules like water and ammonia or ions like chloride or cyanide.

The nature of these ligands significantly affects the properties of the complex ion, including its color. For instance, in the complexes \(\begin{bmatrix}Cr(NH_3)_6\begin{bmatrix} ^{3+}\right)\right\) and \(\begin{bmatrix}Cr(H_2O)_6\begin{bmatrix} ^{3+}\right)\right\), NH3 and H2O act as ligands. The type of ligands and their arrangement around the central metal ion lead to different energy splittings in the d-orbitals, directly influencing which wavelengths of light are absorbed.

Complex ions are a fundamental concept in understanding the chemistry of transition metals and their interactions with light. By studying these ions, one can predict and explain a wide range of chemical behaviors and properties, especially related to color and spectroscopy.

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Most popular questions from this chapter

Give the electron configuration of (a) \(\mathrm{Pm} ;\) (b) \(\mathrm{Lu}^{3+} ;\) (c) \(\mathrm{Th}\) (d) \(\mathrm{Fm}^{3+}\).

(a) What behavior distinguishes paramagnetic and diamagnetic substances? (b) Why are paramagnetic ions common among transition elements but not main-group elements? (c) Why are colored solutions of metal ions common among transition elements but not main-group elements?

When neptunium (Np) and plutonium (Pu) were discovered, the periodic table did not include the actinides, so these elements were placed in Groups \(7 \mathrm{~B}(7)\) and \(8 \mathrm{~B}(8) .\) When americium (Am) and curium (Cm) were synthesized, they were placed in Groups \(8 \mathrm{~B}(9)\) and \(8 \mathrm{~B}(10) .\) However, during chemical isolation procedures, Glenn Seaborg and his colleagues, who had synthesized these elements, could not find their compounds among other compounds of members of the same groups, which led Seaborg to suggest they were part of a new inner transition series. (a) How do the electron configurations of these elements support Seaborg's suggestion? (b) The highest fluorides of \(\mathrm{Np}\) and \(\mathrm{Pu}\) are hexafluorides, and the highest fluoride of uranium is also the hexafluoride. How does this chemical evidence support the placement of \(\mathrm{Np}\) and \(\mathrm{Pu}\) as inner transition elements rather than transition elements?

When \(\mathrm{MCl}_{4}\left(\mathrm{NH}_{3}\right)_{2}\) is dissolved in water and treated with AgNO \(_{3}, 2\) mol of \(\mathrm{AgCl}\) precipitates immediately for each mole of \(\mathrm{MCl}_{4}\left(\mathrm{NH}_{3}\right)_{2} .\) Give the coordination number of \(\mathrm{M}\) in the complex.

A shortcut to finding optical isomers is to see if the complex has a plane of symmetry-a plane passing through the metal atom such that every atom on one side of the plane is matched by an identical one at the same distance from the plane on the other side. Any planar complex has a plane of symmetry, since all atoms lie in one plane. Use this approach to determine whether these exist as optical isomers: (a) \(\left[\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right]\) (tetrahedral); (b) \(\left[\mathrm{Pt}(\mathrm{en})_{2}\right]^{2+} ;\) (c) trans-[PtBr \(\left.\left._{4} \mathrm{Cl}_{2}\right]^{2-} ;\) (d) trans-[Co(en) \(\left._{2} \mathrm{~F}_{2}\right]^{+}\) (e) \(c i s-\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{~F}_{2}\right]^{+}\)

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