Chapter 21: Problem 17
Balance the following skeleton reactions, and identify the oxidizing and reducing agents: (a) \(\mathrm{NO}_{2}(g) \longrightarrow \mathrm{NO}_{3}^{-}(a q)+\mathrm{NO}_{2}^{-}(a q)\) [basic] (b) \(\mathrm{Zn}(s)+\mathrm{NO}_{3}^{-}(a q) \longrightarrow \mathrm{Zn}(\mathrm{OH})_{4}^{2-}(a q)+\mathrm{NH}_{3}(g)[\mathrm{basic}]\) (c) \(\mathrm{H}_{2} \mathrm{~S}(g)+\mathrm{NO}_{3}^{-}(a q) \longrightarrow \mathrm{S}_{8}(s)+\mathrm{NO}(g)\) [acidic]
Short Answer
Step by step solution
Identify the oxidation states and half-reactions for (a)
Balance the half-reactions separately for (a)
Combine the balanced half-reactions for (a)
Identify oxidizing and reducing agents for (a)
Identify the oxidation states and half-reactions for (b)
Balance the half-reactions separately for (b)
Combine the balanced half-reactions for (b)
Identify oxidizing and reducing agents for (b)
Identify the oxidation states and half-reactions for (c)
Balance the half-reactions separately for (c)
Combine the balanced half-reactions for (c)
Identify oxidizing and reducing agents for (c)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
oxidation states
For instance, to identify the oxidation states in the reaction \(\text{NO}_2 \rightarrow \text{NO}_3^- + \text{NO}_2^-\), we assign oxidation numbers to nitrogen in all three species:
- In \(\text{NO}_2\), nitrogen has an oxidation state of +4.
- In \(\text{NO}_3^-\), nitrogen has an oxidation state of +5.
- In \(\text{NO}_2^-\), nitrogen has an oxidation state of +3.
- Oxidation: An increase in oxidation state (loss of electrons).
- Reduction: A decrease in oxidation state (gain of electrons).
half-reactions
Let's break down \(\text{NO}_2 \rightarrow \text{NO}_3^- + \text{NO}_2^-\) into half-reactions:
- Oxidation half-reaction: Nitrogen in \(\text{NO}_2\) is oxidized to form \(\text{NO}_3^-\), as its oxidation state changes from +4 to +5.
- Reduction half-reaction: Nitrogen in \(\text{NO}_2\) is reduced to form \(\text{NO}_2^-\), as its oxidation state changes from +4 to +3.
Combining these balanced half-reactions will give the complete, balanced redox reaction.
oxidizing agents
For example, in the redox reaction \(\text{H}_2\text{S} + \text{NO}_3^- \rightarrow \text{S}_8 + \text{NO}\) (under acidic conditions), nitrate ion \(\text{NO}_3^-\) acts as the oxidizing agent because it gains electrons and is reduced to \(\text{NO}\).
Identifying the oxidizing agent involves:
- Finding the substance that is reduced (a decrease in oxidation state).
- Recognizing that this substance accepts electrons.
reducing agents
For instance, in the reaction \(\text{Zn} + \text{NO}_3^- \rightarrow \text{Zn}(\text{OH})_4^{2-} + \text{NH}_3\) (under basic conditions), zinc metal \(\text{Zn}\) acts as the reducing agent because it loses electrons and is oxidized to \(\text{Zn}(\text{OH})_4^{2-}\).
Identifying the reducing agent involves:
- Finding the substance that is oxidized (an increase in oxidation state).
- Recognizing that this substance donates electrons.
acidic and basic conditions
In acidic conditions, balance redox reactions by:
- Adding \(\text{H}_2\text{O}\) molecules to balance oxygen atoms.
- Adding \(\text{H}^+\) ions to balance hydrogen atoms.
- Adding \(\text{e}^-\) to balance the charge.
- Adding \(\text{H}_2\text{O}\) molecules to balance oxygen atoms.
- Adding \(\text{OH}^-\) ions to balance hydrogen atoms.
- Adding \(\text{e}^-\) to balance the charge.