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Give the name and formula of the compound formed from each pair of elements: (a) sodium and nitrogen; (b) oxygen and strontium; (c) aluminum and chlorine.

Short Answer

Expert verified
(a) Sodium nitride (Na鈧僋); (b) Strontium oxide (SrO); (c) Aluminum chloride (AlCl鈧).

Step by step solution

01

- Identify the Elements and Their Symbols

List the symbols for the elements: (a) sodium (Na) and nitrogen (N); (b) oxygen (O) and strontium (Sr); (c) aluminum (Al) and chlorine (Cl).
02

- Determine the Valence or Charges of Each Element

Look up the common valences or charges for each element: (a) Na typically has a charge of +1 and N typically has a charge of -3; (b) O typically has a charge of -2 and Sr typically has a charge of +2; (c) Al typically has a charge of +3 and Cl typically has a charge of -1.
03

- Combine Elements in Neutral Compounds

Form compounds such that the overall charge is neutral: (a) Combine Na and N in a ratio that balances their charges. The compound will be Na鈧僋; (b) Combine O and Sr in a ratio that balances their charges. The compound will be SrO; (c) Combine Al and Cl in a ratio that balances their charges. The compound will be AlCl鈧.
04

- Name the Compounds

Use standard naming conventions for the compounds: (a) The compound formed by Na and N is called sodium nitride; (b) The compound formed by O and Sr is called strontium oxide; (c) The compound formed by Al and Cl is called aluminum chloride.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

ionic bonding
Ionic bonding occurs when atoms transfer electrons to achieve a full outer shell of electrons, leading to the formation of ions. These ions are charged particles that attract each other due to electrostatic forces.
This type of bond typically forms between metals, which lose electrons, and nonmetals, which gain electrons.
For example, in sodium nitride (Na鈧僋), sodium (Na) loses one electron to form a Na鈦 ion, while nitrogen (N) gains three electrons to form an N鲁鈦 ion. The resulting electrostatic attraction brings these ions together to form the ionic compound Na鈧僋.
We often see ionic bonding in everyday substances like table salt (NaCl), where sodium and chlorine bond ionically.
Remember, the goal of ionic bonding is to create a stable compound with a neutral overall charge by balancing the positive and negative charges of the constituent ions.
valence electrons
Valence electrons are the outermost electrons of an atom and play a crucial role in chemical bonding. These electrons are involved when atoms bond to form compounds.
For example, sodium (Na) has one valence electron, while nitrogen (N) has five valence electrons. During the formation of sodium nitride (Na鈧僋), each sodium atom donates its single valence electron, a total of three electrons, to one nitrogen atom.
The nitrogen atom then completes its valence shell by gaining these three electrons, achieving a stable octet.
By knowing the number of valence electrons, we can predict how atoms will interact. Metals often lose their valence electrons to become positively charged cations, while nonmetals gain electrons to become negatively charged anions.
chemical nomenclature
Chemical nomenclature is the systematic method of naming chemical compounds. It ensures that each compound has a unique name that reflects its composition.
For ionic compounds, the name is derived from the cation (positive ion) followed by the anion (negative ion).
For example, in sodium nitride (Na鈧僋), 'sodium' is the name of the cation Na鈦, and 'nitride' comes from the anion N鲁鈦.
In strontium oxide (SrO), 'strontium' is the cation Sr虏鈦, and 'oxide' is the anion O虏鈦.
This method provides a clear understanding of the elements involved and their proportions in the compound.
Let's take aluminum chloride (AlCl鈧) as another example: 'aluminum' indicates the Al鲁鈦 cation, and 'chloride' indicates the Cl鈦 anion. This logical system helps chemists communicate information about compounds efficiently.
element charges
Element charges, or oxidation states, indicate how many electrons an atom has lost or gained. This concept is vital for understanding how compounds form.
Metals, like sodium (Na) or aluminum (Al), often form positive charges (cations) by losing electrons. For instance, Na typically forms a +1 charge, and Al forms a +3 charge.
Nonmetals, like nitrogen (N) or chlorine (Cl), usually form negative charges (anions) by gaining electrons. For example, N typically forms a -3 charge, and Cl forms a -1 charge.
When forming ionic compounds, the total positive charge must balance the total negative charge, resulting in a compound with no overall charge.
For sodium nitride (Na鈧僋), three Na鈦 ions (totaling +3) balance one N鲁鈦 ion. In strontium oxide (SrO), one Sr虏鈦 ion balances one O虏鈦 ion.
For aluminum chloride (AlCl鈧), one Al鲁鈦 ion balances three Cl鈦 ions. Understanding element charges is essential for predicting how different elements will react to form stable compounds.

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Most popular questions from this chapter

Correct each of the following formulas: (a) Tetraphosphorus decoxide is \(\mathrm{P}_{4} \mathrm{O}_{6}\). (b) Diboron trioxide is \(\mathrm{B}_{3} \mathrm{O}_{2}\). (c) Phosphorus trifluoride is \(\mathrm{F}_{3} \mathrm{P}\).

Correct each of the following formulas: (a) Barium oxide is \(\mathrm{BaO}_{2}\). (b) Iron(II) nitrate is \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) (c) Magnesium sulfide is \(\mathrm{MnSO}_{3}\). (d) Potassium iodide is \(\mathrm{P}_{2} \mathrm{I}_{3}\).

Nitrogen forms more oxides than any other element. The percents by mass of \(\mathrm{N}\) in three different nitrogen oxides are (I) \(46.69 \%\), (II) \(36.85 \%\), and (III) \(25.94 \% .\) For each compound, determine (a) the simplest whole-number ratio of \(\mathrm{N}\) to \(\mathrm{O}\) and (b) the number of grams of oxygen per \(1.00 \mathrm{~g}\) of nitrogen.

Before the use of systematic names, many compounds had common names. Give the systematic name for each of the following: (a) Blue vitriol, \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\) (b) Slaked lime, \(\mathrm{Ca}(\mathrm{OH})_{2}\) (c) Oil of vitriol, \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (d) Washing soda, \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) (e) Muriatic acid, HCl (f) Epsom salt, \(\mathrm{MgSO}_{4} \cdot 7 \mathrm{H}_{2} \mathrm{O}\)

Boron trifluoride is used as a catalyst in the synthesis of organic compounds. When this compound is analyzed by mass spectrometry, several different \(1+\) ions form, including ions representing the whole molecule as well as molecular fragments formed by the loss of one, two, and three \(\mathrm{F}\) atoms. Given that boron has two naturally occurring isotopes, \({ }^{10} \mathrm{~B}\) and \({ }^{11} \mathrm{~B},\) and fluorine has one, \({ }^{19} \mathrm{~F}\), calculate the masses of all possible \(1+\) ions.

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