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(a) Does the percent by mass of each element in a compound depend on the amount of compound? Explain. (b) Does the mass of each element in a compound depend on the amount of compound? Explain.

Short Answer

Expert verified
a) No, percent by mass is independent of amount. b) Yes, mass of each element depends on the compound amount.

Step by step solution

01

Understanding Percent by Mass

Percent by mass of an element in a compound is calculated using the formula: \[ \text{Percent by mass} = \frac{\text{Mass of the element}}{\text{Total mass of the compound}} \times 100 \text{%} \] This is a ratio and depends on the proportion of the element's mass to the total mass of the compound.
02

Analyzing Dependence on Amount for Percent by Mass

The percent by mass is a ratio. Ratios are dimensionless and independent of the amount of material. Therefore, the percent by mass of each element in a compound does not change with varying amounts of the compound.
03

Understanding Mass of Each Element

The mass of each element in a given amount of compound can be found by multiplying the percent by mass by the total mass of the compound: \[ \text{Mass of the element} = \frac{\text{Percent by mass}}{100} \times \text{Total mass of the compound} \]
04

Analyzing Dependence on Amount for Mass of Each Element

The mass of each element directly depends on the total mass of the compound. If the amount of the compound increases, the total mass increases, and so does the mass of each element in the compound.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

mass of elements in compounds
In chemistry, the concept of mass of elements in compounds is foundational. Every compound is made up of elements, and the mass of each element within a compound can be calculated.
For example, if you have a compound like water (Hâ‚‚O), you would find that the mass of hydrogen and oxygen contributes to the total mass. The mass of the elements can be determined using their atomic masses from the periodic table and the number of each type of atom in the compound.

Consider the formula for calculating percent by mass: \(\text{Percent by mass} = \frac{\text{Mass of the element}}{\text{Total mass of the compound}} \times 100 \text{%} \). Using this, you can figure out what fraction of the total mass comes from each constituent element.
  • For water, the atomic mass of hydrogen is approximately 1 amu (atomic mass unit) each, and oxygen is about 16 amu.
  • Since water has two hydrogen atoms and one oxygen atom, the total mass is 2(1 amu) + 16 amu = 18 amu.
It shows how individual atoms contribute to the mass of the compound.
ratios in chemistry
Ratios are crucial in chemistry since they help compare quantities. When analyzing compounds, chemists often focus on the ratios between the masses of different elements.
For example, the percent by mass of an element in a compound is essentially a ratio. It tells you how much of the compound's mass comes from a particular element, relative to the entire mass of the compound.
  • This is always the same, no matter how much of the compound you have.
Hence, if you have a small or large sample of the compound, the percent by mass ratio remains unchanged.
Imagine breaking a chocolate bar in half. Each piece has the same ratio of the ingredients as the whole bar. Similarly, in a pure chemical compound, the ratio of the masses of its elements stays constant regardless of quantity.
It's crucial to remember ratios are dimensionless, which means they don't change just because you change the size of the sample.
dependence on amount
Understanding dependence on amount is key to mastering chemistry concepts. Let's see how it impacts the mass of elements in a compound.
The mass of each element in a compound changes with the amount of the compound you have.
  • If you double the amount of the compound, you double the mass of each element in it.
  • This is because the elements' masses are directly proportional to the total mass of the compound.
For instance, think of water again. If you have 18 grams of water, it contains approximately 2 grams of hydrogen and 16 grams of oxygen. If you now take 36 grams of water (double the amount), it will hence contain 4 grams of hydrogen and 32 grams of oxygen.
Here, the percent by mass remains constant, but the actual masses of the elements increase with the increase in total mass of the compound. This direct proportionality is an important concept to grasp when dealing with quantities in chemistry.

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Most popular questions from this chapter

Give the systematic names for the formulas or the formulas for the names: (a) \(\mathrm{CoO}\); (b) mercury(I) chloride; (c) chromic oxide; (d) \(\mathrm{CuBr}_{2}\).

You are working in the laboratory, preparing sodium chloride. Consider the following results for three preparations of the compound: Case \(1: 39.34 \mathrm{~g} \mathrm{Na}+60.66 \mathrm{~g} \mathrm{Cl}_{2} \longrightarrow 100.00 \mathrm{~g} \mathrm{NaCl}\) Case \(2: 39.34 \mathrm{~g} \mathrm{Na}+70.00 \mathrm{~g} \mathrm{Cl}_{2} \longrightarrow\) $$ 100.00 \mathrm{~g} \mathrm{NaCl}+9.34 \mathrm{~g} \mathrm{Cl}_{2} $$ Case \(3: 50.00 \mathrm{~g} \mathrm{Na}+50.00 \mathrm{~g} \mathrm{Cl}_{2} \longrightarrow\) $$ 82.43 \mathrm{~g} \mathrm{NaCl}+17.57 \mathrm{~g} \mathrm{Na} $$ Explain these results in terms of the laws of conservation of mass and definite composition.

The seven most abundant ions in seawater make up more than \(99 \%\) by mass of the dissolved compounds. Here are their abundances in units of \(\mathrm{mg}\) ion/kg seawater: chloride 18,\(980 ;\) sodium 10,\(560 ;\) sulfate 2650 ; magnesium \(1270 ;\) calcium \(400 ;\) potassium 380 ; hydrogen carbonate 140 . (a) What is the mass \(\%\) of each ion in seawater? (b) What percent of the total mass of ions is represented by sodium ions? (c) How does the total mass \(\%\) of alkaline earth metal ions compare with the total mass \(\%\) of alkali metal ions? (d) Which make up the larger mass fraction of dissolved components, anions or cations?

What monatomic ions would you expect radium \((Z=88)\) and selenium \((Z=34)\) to form?

What class of elements lies along the "staircase" line in the periodic table? How do the properties of these elements compare with those of metals and nonmetals?

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