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What is an amphiprotic species? Name one and write balanced equations that show why it is amphiprotic.

Short Answer

Expert verified
An amphiprotic species can donate and accept a proton. HCO鈧冣伝 is an example: \( \text{HCO}_3^- \to \text{CO}_3^{2-} + \text{H}^+ \) and \( \text{HCO}_3^- + \text{H}^+ \to \text{H}_2\text{CO}_3 \).

Step by step solution

01

Define an Amphiprotic Species

An amphiprotic species is a molecule or ion that can both donate and accept a proton (H鈦), meaning it can act as both an acid and a base.
02

Identify an Example

A common example of an amphiprotic species is the hydrogen carbonate ion (HCO鈧冣伝).
03

Write the Reaction as an Acid

As an acid, the hydrogen carbonate ion (HCO鈧冣伝) can donate a proton to form carbonate (CO鈧兟测伝): \( \text{HCO}_3^- \to \text{CO}_3^{2-} + \text{H}^+ \)
04

Write the Reaction as a Base

As a base, the hydrogen carbonate ion (HCO鈧冣伝) can accept a proton to form carbonic acid (H鈧侰O鈧): \( \text{HCO}_3^- + \text{H}^+ \to \text{H}_2\text{CO}_3 \)
05

Confirm Amphiprotic Nature

These equations show that HCO鈧冣伝 can both donate a proton (acting as an acid) and accept a proton (acting as a base), confirming its amphiprotic nature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

acid-base chemistry
Acid-base chemistry is a branch of chemistry that studies acids, bases, and their reactions. It's central to many processes in both nature and industry.
Acids are substances that can donate a proton (H鈦). Bases, on the other hand, are substances that can accept a proton.
The behavior of acids and bases is crucial to understanding various chemical reactions.
In acid-base chemistry, we often talk about conjugate acid-base pairs. When an acid donates a proton, it becomes its conjugate base. Conversely, when a base accepts a proton, it becomes its conjugate acid.
Amphiprotic species are unique because they can act as both acids and bases. This dual ability makes them fascinating and versatile in reactions.
hydrogen carbonate
Hydrogen carbonate, commonly known as bicarbonate, is an important amphiprotic species in chemistry. Its formula is HCO鈧冣伝.
Bicarbonate plays a significant role in maintaining pH levels in biological systems, such as the human blood. It acts as a buffer, preventing drastic pH changes.
Bicarbonate can donate a proton, behaving like an acid. When it loses a proton, it forms carbonate (CO鈧兟测伝):
\( \text{HCO}_3^- \rightarrow \text{CO}_3^{2-} + \text{H}^+ \).
Similarly, bicarbonate can accept a proton, behaving like a base. When it gains a proton, it forms carbonic acid (H鈧侰O鈧):
\( \text{HCO}_3^- + \text{H}^+ \rightarrow \text{H}_2\text{CO}_3 \).
These reactions highlight the dual nature of bicarbonate, proving it can act as both an acid and a base.
proton donation and acceptance
Proton donation and acceptance are key concepts in understanding acid-base chemistry. It revolves around the transfer of protons between molecules or ions.
When a substance donates a proton, it acts as an acid. This process is called proton donation.
For example, hydrogen carbonate (HCO鈧冣伝) can donate a proton:
\( \text{HCO}_3^- \rightarrow \text{CO}_3^{2-} + \text{H}^+ \).
Conversely, when a substance accepts a proton, it acts as a base. This process is called proton acceptance.
For instance, hydrogen carbonate can accept a proton:
\( \text{HCO}_3^- + \text{H}^+ \rightarrow \text{H}_2\text{CO}_3 \).
Amphiprotic species like HCO鈧冣伝 are special because they can both donate and accept protons, making them both acids and bases.
This dual functionality makes amphiprotic species important in many chemical processes and reactions.

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Most popular questions from this chapter

The Group \(5 \mathrm{~A}(15)\) hydrides react with boron trihalides in a reversible Lewis acid-base reaction. When \(0.15 \mathrm{~mol}\) of \(\mathrm{PH}_{3} \mathrm{BCl}_{3}(s)\) is introduced into a \(3.0-\mathrm{L}\) container at a certain temperature, \(8.4 \times 10^{-3} \mathrm{~mol}\) of \(\mathrm{PH}_{3}\) is present at equilibrium: $$ \mathrm{PH}_{3} \mathrm{BCl}_{3}(s) \rightleftharpoons \mathrm{PH}_{3}(g)+\mathrm{BCl}_{3}(g) $$ (a) Find \(K_{c}\) for the reaction at this temperature. (b) Draw a Lewis structure for the reactant.

A chemist makes four successive 10 -fold dilutions of \(1.0 \times 10^{-5} M \mathrm{HCl} .\) Calculate the \(\mathrm{pH}\) of the original solution and of each diluted solution (through \(1.0 \times 10^{-9} \mathrm{M} \mathrm{HCl}\) ).

(a) What are \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right],\left[\mathrm{OH}^{-}\right],\) and \(\mathrm{pOH}\) in a solution with a \(\mathrm{pH}\) of \(8.97 ?\) (b) What are \(\left[\mathrm{H}_{3} \mathrm{O}^{+} \mathrm{J},\left[\mathrm{OH}^{-}\right],\right.\) and \(\mathrm{pH}\) in a solution with a pOH of \(11.27 ?\)

Explain with equations and calculations, when necessary, whether an aqueous solution of each of these salts is acidic, basic, or neutral: (a) \(\mathrm{Pb}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} ;\) (b) \(\mathrm{Cr}\left(\mathrm{NO}_{2}\right)_{3}:\) (c) CsI.

(a) What are \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right],\left[\mathrm{OH}^{-}\right],\) and \(\mathrm{pOH}\) in a solution with a (18.32 \(\mathrm{pH}\) of \(9.85 ?\) (b) What are \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right],\left[\mathrm{OH}^{-}\right],\) and \(\mathrm{pH}\) in a solution with a pOH of \(9.43 ?\)

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