Chapter 17: Problem 3
If there is no change in concentrations, why is the equilibrium state considered dynamic?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 17: Problem 3
If there is no change in concentrations, why is the equilibrium state considered dynamic?
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
What is the difference between the equilibrium position and the equilibrium constant of a reaction? Which changes as a result of a change in reactant concentration?
When a chemical company employs a new reaction to manufacture a product, the chemists consider its rate (kinetics) and yield (equilibrium). How does each of these affect the usefulness of a manufacturing process?
Sodium bicarbonate undergoes thermal decomposition according to the reaction $$ 2 \mathrm{NaHCO}_{3}(s) \Longrightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g) $$ How does the equilibrium position shift as a result of each of the following disturbances? (a) 0.20 atm of argon gas is added. (b) \(\mathrm{NaHCO}_{3}(s)\) is added. (c) \(\mathrm{Mg}\left(\mathrm{ClO}_{4}\right)_{2}(s)\) is added as a drying agent to remove \(\mathrm{H}_{2} \mathrm{O}\). (d) Dry ice is added at constant \(T\)
A sealed 2.0 -L container initially contains 0.12 mol each of \(\mathrm{H}_{2} \mathrm{O}(g), \mathrm{Cl}_{2} \mathrm{O}(g),\) and \(\mathrm{HClO}(g) ;\) the reaction mixture is allowed to come to equilibrium according to the reaction $$ \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{Cl}_{2} \mathrm{O}(g) \rightleftharpoons 2 \mathrm{HClO}(g) \quad K_{\mathrm{c}}=0.090 $$ Calculate the equilibrium concentrations of all three compounds.
A change in reaction conditions increases the rate of a certain forward reaction more than that of the reverse reaction. What is the effect on the equilibrium constant and on the concentrations of reactants and products at equilibrium?
What do you think about this solution?
We value your feedback to improve our textbook solutions.