/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 112 Chlorine is commonly used to dis... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Chlorine is commonly used to disinfect drinking water, and inactivation of pathogens by chlorine follows first-order kinetics. The following data are for \(E\). coli inactivation: $$ \begin{array}{cc} \text { Contact Time (min) } & \text { Percent (\%) Inactivation } \\ \hline 0.00 & 0.0 \\ 0.50 & 68.3 \\ 1.00 & 90.0 \\ 1.50 & 96.8 \\ 2.00 & 99.0 \\ 2.50 & 99.7 \\ 3.00 & 99.9 \end{array} $$ (a) Determine the first-order inactivation constant, \(k\). [Hint: \% inactivation \(\left.=100 \times\left(1-[\mathrm{A}] /[\mathrm{A}]_{0}\right) .\right]\) (b) How much contact time is required for \(95 \%\) inactivation?

Short Answer

Expert verified
The first-order inactivation constant, \(k\), is approximately 2.3. The required contact time for 95% inactivation is approximately 1.3 minutes.

Step by step solution

01

Understand the First-Order Kinetics Formula

First-order kinetics for disinfection can be represented by the formula: \(\frac{d[A]}{dt} = -k[A]\), where \([A]\) = concentration of pathogen at time \(t\), \([A]_0\) = initial concentration of pathogen, \(k\) = first-order inactivation constant.
02

Convert Percent Inactivation to Concentration Ratio

Percent inactivation is given by: \(100 \times \big(1 - \frac{[A]}{[A]_0}\big)\). Rearranging gives: \(\frac{[A]}{[A]_0} = 1 - \frac{\text{Percent Inactivation}}{100}\).
03

Calculate Concentration Ratios

For each contact time in the table, compute \(\frac{[A]}{[A]_0}\): - At 0.50 min: \(\frac{[A]}{[A]_0} = 0.317\)- At 1.00 min: \(\frac{[A]}{[A]_0} = 0.10\)- At 1.50 min: \(\frac{[A]}{[A]_0} = 0.032\)- At 2.00 min: \(\frac{[A]}{[A]_0} = 0.01\)- At 2.50 min: \(\frac{[A]}{[A]_0} = 0.003\)- At 3.00 min: \(\frac{[A]}{[A]_0} = 0.001\)
04

Use the First-Order Kinetics Formula

For first-order reactions, \(\frac{[A]}{[A]_0} = e^{-kt}\). Taking the natural logarithm on both sides, \(\text{ln}\big(\frac{[A]}{[A]_0}\big) = -kt\).
05

Determine the Inactivation Constant \(k\)

For the data points, calculate \(-kt\) and plot \(\text{ln}\big(\frac{[A]}{[A]_0}\big)\) vs. contact time (min). Using linear regression, determine the slope of the line, which represents \(-k\).
06

Calculate Inactivation Constant

Using the data: - At 0.50 min: \(\text{ln}(0.317) = -1.149\)- At 1.00 min: \(\text{ln}(0.10) = -2.303\)- At 1.50 min: \(\text{ln}(0.032) = -3.446\)- At 2.00 min: \(\text{ln}(0.01) = -4.605\)- At 2.50 min: \(\text{ln}(0.003) = -5.811\)- At 3.00 min: \(\text{ln}(0.001) = -6.908\)Plotting these points and finding the slope gives \(k \approx 2.3\).
07

Determine Contact Time for 95% Inactivation

For 95% inactivation, \(\frac{[A]}{[A]_0} = 0.05\). Use \(\text{ln}(0.05) = -kt\) and solve for \(t\): \[-2.996 = -2.3t\] \[t = \frac{2.996}{2.3} \approx 1.3 \text{ min}\].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

first-order kinetics
Understanding first-order kinetics is key for disinfection processes. In first-order kinetics, the rate of reaction is directly proportional to the concentration of the reacting species. Mathematically, this can be expressed as \(\frac{d[A]}{dt} = -k[A]\), where \([A]\) represents the concentration of pathogens and \({k}\) is the kinetic constant. This relationship means if you have a higher concentration of pathogens, the rate of disinfection will be faster.

The equation also allows us to calculate how the concentration of a pathogen decreases over time. By solving the equation, we get \([A] = [A]_0 e^{-kt}\), demonstrating an exponential decay. This tells us that, in a given time period, the fraction of pathogens not yet disinfected diminishes exponentially.
chlorine disinfection
Chlorine is widely used for the disinfection of drinking water because of its effectiveness against a variety of pathogens. When chlorine is added to water, it forms hypochlorous acid and hypochlorite ion, both of which are powerful disinfectants.

The effectiveness of chlorine disinfection depends on several factors:
  • Contact time: Longer contact time usually increases the level of disinfection.
  • Concentration: The level of chlorine available in the water to inactivate the pathogens.
  • Water quality: Factors like pH, temperature, and presence of organic matter can affect chlorine's efficacy.
Typically, chlorine inactivates pathogens following first-order kinetics. This means that the effectiveness of chlorine at killing pathogens decreases exponentially over time, making it highly reliable for ensuring water is safe to drink.
pathogen inactivation
Pathogen inactivation is a critical step in ensuring safe drinking water. By inactivating pathogens, we mean reducing their viability to cause disease. Chlorine, for instance, targets cell walls and disrupts the metabolism of pathogens, effectively neutralizing them.

The inactivation process can be quantified by the inactivation percentage, which can be calculated using the formula \(Percent \, Inactivation = 100 \times (1 - \frac{[A]}{[A]_0})\). For instance, if 90% of the pathogens are inactivated, only 10% remain viable.

Higher levels of inactivation, such as 99.9%, imply a very small fraction of pathogens survive, which is crucial for public health because even a small number of pathogens can cause illness. By understanding and manipulating the inactivation process, we can ensure that water treatment processes are effective and reliable.
kinetic constant calculation
The kinetic constant \({k}\) is a crucial parameter in first-order kinetics because it indicates the disinfection rate. To calculate \({k}\) for chlorine disinfection, you need data on contact time and the percentage of pathogen inactivation.

Here’s how to determine the kinetic constant:
  • Convert the percentage inactivation into a concentration ratio, \(\frac{[A]}{[A]_0} = 1 - \frac{\text{Percent Inactivation}}{100}\).
  • Apply the first-order kinetics formula where \( \frac{[A]}{[A]_0} = e^{-kt} \).
  • Take the natural logarithm on both sides to get \(\text{ln}(\frac{[A]}{[A]_0}) = -kt\).

Using plotted points for different contact times, you can derive the slope of the line, which will be \(-k\). For example, data from the exercise indicate \(\text{ln}(0.317) = -1.149\) at 0.50 minutes and \(\text{ln}(0.10) = -2.303\) at 1.00 minute. Plot these data points and apply linear regression to find the slope. The slope is \(-k\) and thus, \({k}\) can be approximated. For the given data, \({k} \) was found to be approximately 2.3.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) For a reaction with a given \(E_{a},\) how does an increase in \(T\) affect the rate? (b) For a reaction at a given \(T,\) how does a decrease in \(E_{\mathrm{a}}\) affect the rate?

The growth of Pseudomonas bacteria is modeled as a first-order process with \(k=0.035 \mathrm{~min}^{-1}\) at \(37^{\circ} \mathrm{C}\). The initial \(P\) seudomonas population density is \(1.0 \times 10^{3}\) cells/L. (a) What is the population density after \(2 \mathrm{~h}\) ? (b) What is the time required for the population to go from \(1.0 \times 10^{3}\) to \(2.0 \times 10^{3}\) cells/L?

A biochemist studying the breakdown of the insecticide DDT finds that it decomposes by a first-order reaction with a halflife of 12 yr. How long does it take DDT in a soil sample to decrease from 275 ppbm to \(10 .\) ppbm (parts per billion by mass)?

In a study of nitrosyl halides, a chemist proposes the following mechanism for the synthesis of nitrosyl bromide: \(\mathrm{NO}(\mathrm{g})+\mathrm{Br}_{2}(g) \rightleftharpoons \operatorname{NOBr}_{2}(g)\) [fast] \(\operatorname{NOBr}_{2}(g)+\mathrm{NO}(g) \longrightarrow 2 \mathrm{NOBr}(g)\) [slow] If the rate law is rate \(=k[\mathrm{NO}]^{2}\left[\mathrm{Br}_{2}\right]\), is the proposed mechanism valid? If so, show that it satisfies the three criteria for validity.

The citric acid cycle is the central reaction sequence in the cellular metabolism of humans and many other organisms. One of the key steps is catalyzed by the enzyme isocitrate dehydrogenase and the oxidizing agent \(\mathrm{NAD}^{+}\). In yeast, the reaction is eleventh order. Rate \(=k[\) enzyme \(]\) [isocitrate] \(^{4}[\mathrm{AMP}]^{2}\left[\mathrm{NAD}^{+}\right]^{m}\left[\mathrm{Mg}^{2+}\right]^{2}\) What is the order with respect to \(\mathrm{NAD}^{+} ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.