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What is the strongest type of intermolecular force between solute and solvent in each solution? (a) \(\mathrm{Cu}(s)\) in \(\mathrm{Ag}(s)\) (b) \(\mathrm{CH}_{3} \mathrm{Cl}(g)\) in \(\mathrm{CH}_{3} \mathrm{OCH}_{3}(g)\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{3}(g)\) in \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}(l)\)

Short Answer

Expert verified
(a) Metallic bonding, (b) Dipole-dipole interactions, (c) London dispersion forces

Step by step solution

01

- Understanding Intermolecular Forces

Intermolecular forces are forces of attraction or repulsion which act between neighboring particles. The main types of intermolecular forces include London dispersion forces, dipole-dipole interactions, and hydrogen bonding. The strongest type of intermolecular force is metallic bonding for metals, hydrogen bonding for molecules containing O-H, N-H, or F-H bonds, dipole-dipole interactions for polar molecules, and London dispersion forces for non-polar molecules.
02

- Identify Intermolecular Forces in (a)

In part (a), \(\text{Cu}(s)\) in \(\text{Ag}(s)\) are both metallic elements in their solid states. The strongest intermolecular force between them is metallic bonding.
03

- Identify Intermolecular Forces in (b)

In part (b), \(\text{CH}_{3} \text{Cl}(g)\) (methyl chloride) is a polar molecule due to the \(\text{C-Cl}\) bond, and \(\text{CH}_{3} \text{OCH}_{3}(g)\) (dimethyl ether) is also polar due to the \(\text{O}\) atom. The strongest intermolecular force between them is dipole-dipole interactions.
04

- Identify Intermolecular Forces in (c)

In part (c), \(\text{CH}_{3} \text{CH}_{3}(g)\) (ethane) is a nonpolar molecule, while \(\text{CH}_{3} \text{CH}_{2} \text{CH}_{2}\text{NH}_{2}(l)\) (propylamine) is polar due to the \(\text{N-H}\) bond, which can participate in hydrogen bonding. However, since ethane is nonpolar, the strongest intermolecular force with propylamine would be London dispersion forces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Metallic Bonding
Metallic bonding is a type of chemical bonding that arises from the electrostatic attraction between positively charged metal ions and the delocalized electrons that surround them. In this bond, electrons are free to move throughout the entire structure, which gives metals their characteristic properties such as electrical conductivity, malleability, and ductility. This bonding is particularly strong due to the extensive network of bonds formed.
For example, in the case of \(\text{Cu}(s)\) in \(\text{Ag}(s)\), both copper and silver atoms bond together through metallic bonding. These types of bonds result in the formation of a lattice structure where the electrons flow freely, holding the metal ions in place and making the metal strong and stable.
Dipole-Dipole Interactions
Dipole-dipole interactions occur between polar molecules, where there is an uneven distribution of electrons. This causes one end of the molecule to carry a partial positive charge while the other end carries a partial negative charge. These opposite charges attract each other, creating a dipole-dipole interaction.
In part (b) of the exercise, we see \(\text{CH}_3\text{Cl}(g)\) and \(\text{CH}_3\text{OCH}_3(g)\). Both of these molecules are polar. Methyl chloride has a polar \(\text{C-Cl}\) bond, and dimethyl ether contains an oxygen atom which makes it polar as well. The strongest intermolecular force between these two would be dipole-dipole interactions, as their polarities induce attraction between the molecules.
London Dispersion Forces
London dispersion forces are the weakest type of intermolecular force and occur in all molecules, whether polar or nonpolar. These forces arise from temporary shifts in the density of electrons in electron clouds, creating instantaneous dipoles that induce dipoles in neighboring molecules, resulting in an attraction between them.
In part (c) of the exercise, we consider \(\text{CH}_3\text{CH}_3(g)\) (ethane) and \(\text{CH}_3\text{CH}_2\text{CH}_2\text{NH}_2(l)\) (propylamine). Ethane is nonpolar, meaning it does not have dipole-dipole interactions or hydrogen bonding capabilities. Propylamine is a polar molecule, but since ethane is nonpolar, the strongest intermolecular force here would be London dispersion forces. These forces, while weaker than others, still play an essential role in the behavior of nonpolar molecules.

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Most popular questions from this chapter

A solution of \(1.50 \mathrm{~g}\) of solute dissolved in \(25.0 \mathrm{~mL}\) of \(\mathrm{H}_{2} \mathrm{O}\) at \(25^{\circ} \mathrm{C}\) has a boiling point of \(100.45^{\circ} \mathrm{C}\). (a) What is the molar mass of the solute if it is a nonvolatile nonelectrolyte and the solution behaves ideally \(\left(d\right.\) of \(\mathrm{H}_{2} \mathrm{O}\) at \(\left.25^{\circ} \mathrm{C}=0.997 \mathrm{~g} / \mathrm{mL}\right) ?\) (b) Conductivity measurements show that the solute is ionic with general formula \(\mathrm{AB}_{2}\) or \(\mathrm{A}_{2} \mathrm{~B}\). What is the molar mass if the solution behaves ideally? (c) Analysis indicates that the solute has an empirical formula of \(\mathrm{CaN}_{2} \mathrm{O}_{6}\). Explain the difference between the actual formula mass and that calculated from the boiling point elevation. (d) Find the van't Hoff factor ( \(i\) ) for this solution.

A chemist is studying small organic compounds to evaluate their potential for use as an antifreeze. When \(0.243 \mathrm{~g}\) of a compound is dissolved in \(25.0 \mathrm{~mL}\) of water, the freezing point of the solution is \(-0.201^{\circ} \mathrm{C}\). (a) Calculate the molar mass of the compound \((d\) of water \(=\) \(1.00 \mathrm{~g} / \mathrm{mL}\) ). (b) Analysis shows that the compound is 53.31 mass \(\% \mathrm{C}\) and 11.18 mass \(\% \mathrm{H},\) the remainder being \(\mathrm{O}\). Determine the empirical and molecular formulas of the compound. (c) Draw a Lewis structure for a compound with this formula that forms \(\mathrm{H}\) bonds and another for one that does not.

Pyridine (right) is an essential portion of many biologically active compounds, such as nicotine and vitamin \(\mathrm{B}_{6}\). Like ammonia, it has a nitrogen with a lone pair, which makes it act as a weak base. Because it is miscible in a wide range of solvents, from water to benzene, pyridine is one of the most important bases and solvents in organic syntheses. Account for its solubility behavior in terms of intermolecular forces.

Classify each substance as a strong electrolyte, weak electrolyte, or nonelectrolyte: (a) Sodium permanganate \(\left(\mathrm{NaMnO}_{4}\right)\) (b) Acetic acid \(\left(\mathrm{CH}_{3} \mathrm{COOH}\right)\) (c) Methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) (d) Calcium acetate \(\left[\mathrm{Ca}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}\right]\)

Hexane and methanol are miscible as gases but only slightly soluble in each other as liquids. Explain.

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