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Predict the chemical formulas of the ionic compound formed by (a) \(\mathrm{Fe}^{3+}\) and \(\mathrm{OH}^{-}\), (b) \(\mathrm{Cs}^{+}\) and \(\mathrm{NO}_{3}^{-},(\mathbf{c}) \mathrm{V}^{2+}\) and (e) \(\mathrm{In}^{3+}\) and \(\mathrm{O}^{2-}\). \(\mathrm{CH}_{3} \mathrm{COO}^{-},(\mathbf{d}) \mathrm{Li}^{+}\) and \(\mathrm{PO}_{4}^{3-}\),

Short Answer

Expert verified
The chemical formulas of the ionic compounds formed by the given ions are: (a) Fe(OH)鈧, (b) CsNO鈧, (c) V(CH鈧僀OO)鈧, (d) Li鈧働O鈧, and (e) In鈧侽鈧.

Step by step solution

01

(a) Fe鲁鈦 and OH鈦

To make the compound neutral, we need to have equal positive and negative charges. Here, we have Fe鲁鈦 with a charge of +3 and OH鈦 with a charge of -1. We can balance the charges by having three OH鈦 ions for each Fe鲁鈦 ion. Therefore, the chemical formula for the ionic compound formed by Fe鲁鈦 and OH鈦 will be Fe(OH)鈧.
02

(b) Cs鈦 and NO鈧冣伝

In this case, both the ions have a single charge, with Cs鈦 having a charge of +1 and NO鈧冣伝 having a charge of -1. Since they have equal and opposite charges, the chemical formula for the ionic compound formed by Cs鈦 and NO鈧冣伝 will be CsNO鈧.
03

(c) V虏鈦 and CH鈧僀OO鈦

Here, we have V虏鈦 with a charge of +2 and CH鈧僀OO鈦 with a charge of -1. To balance the charges, we need two CH鈧僀OO鈦 ions for each V虏鈦 ion. Therefore, the chemical formula for the ionic compound formed by V虏鈦 and CH鈧僀OO鈦 will be V(CH鈧僀OO)鈧.
04

(d) Li鈦 and PO鈧劼斥伝

In this case, we have Li鈦 with a charge of +1 and PO鈧劼斥伝 with a charge of -3. To balance the charges, we need three Li鈦 ions for each PO鈧劼斥伝 ion. Therefore, the chemical formula for the ionic compound formed by Li鈦 and PO鈧劼斥伝 will be Li鈧働O鈧.
05

(e) In鲁鈦 and O虏鈦

Here, we have In鲁鈦 with a charge of +3 and O虏鈦 with a charge of -2. To balance the charges, we can use the lowest common multiple (LCM) of 3 and 2, which is 6. We need two In鲁鈦 ions (each with a charge of +3, for a total charge of +6) and three O虏鈦 ions (each with a charge of -2, for a total charge of -6) to balance the charges. Therefore, the chemical formula for the ionic compound formed by In鲁鈦 and O虏鈦 will be In鈧侽鈧.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Formula Prediction
Predicting the chemical formula of an ionic compound involves understanding how ions combine to form a neutral compound. The key is to balance the charges of the cations and anions involved. When ions combine, their charges must add up to zero, ensuring the compound is electrically neutral.

For instance, when forming a compound from Fe鲁鈦 and OH鈦, we note that Fe鲁鈦 has a charge of +3 and OH鈦 has a charge of -1. We need three OH鈦 ions to balance the charge of one Fe鲁鈦 ion. This results in the formula Fe(OH)鈧.

Keep in mind that each situation may be different, but the underlying principle remains the same: adjust the ratio of ions to achieve a net zero charge.
Charge Balancing
Charge balancing is crucial in forming stable ionic compounds. Each ion carries a specific charge depending on the number of electrons lost or gained. In a compound, the total positive charge from cations must equal the total negative charge from anions.

For example, when combining Cs鈦 and NO鈧冣伝 ions, both have charges of +1 and -1, respectively. The charges naturally balance, so only one of each ion is needed, resulting in the formula CsNO鈧. However, if V虏鈦 is paired with CH鈧僀OO鈦, the charge on V is +2, and on CH鈧僀OO鈦 is -1. We need two acetate ions to balance one vanadium ion, giving us V(CH鈧僀OO)鈧.

Balancing charges is often a straightforward process but requires careful attention to each ion's specific charge.
Valency in Ions
Valency refers to the ability of an ion to combine with others and is directly linked to its charge. The valency of an ion indicates how many bonds it can form with ions of opposite charge.

For example, Li鈦 has a valency of +1, while PO鈧劼斥伝 has a valency of -3. To balance these ions, three Li鈦 ions are needed for every one PO鈧劼斥伝 ion, resulting in the formula Li鈧働O鈧. Understanding valency is crucial for predicting how ions will pair and what the resulting formula will be.

Valency isn't limited to single atoms; it also applies to groups of atoms acting as a unit, such as polyatomic ions.
Polyatomic Ions
Polyatomic ions are clusters of atoms that behave as a unit and carry a charge. They are an essential part of ionic compound formation. Common examples include NO鈧冣伝 (nitrate) and CH鈧僀OO鈦 (acetate).

Let's take the example of In鲁鈦 and O虏鈦. Here, In鲁鈦 has a charge of +3, and combining with O虏鈦, we need to consider the amounts that will balance total charges. We will need two indium ions and three oxide ions to make the charges equal zero, forming the compound In鈧侽鈧.

Polyatomic ions often appear in various combinations, so familiarizing yourself with their names and charges can simplify predicting chemical formulas.

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Most popular questions from this chapter

Because many ions and compounds have very similar names, there is great potential for confusing them. Write the correct chemical formulas to distinguish between (a) sodium carbonate and sodium bicarbonate, (b) potassium peroxide and potassium oxide, \((\mathbf{c})\) calcium sulfide and calcium sulfate, \((\mathbf{d})\) manganese (II) oxide and manganese (III) oxide, (e) hydride ion and hydroxide ion, \((\mathbf{f})\) magnesium nitride and magnesium nitrite, \((\mathbf{g})\) silver nitrate and silver nitrite, \((\mathbf{h})\) cuprous oxide and cupric oxide.

Complete the table by filling in the formula for the ionic compound formed by each pair of cations and anions, as shown for the first pair. $$ \begin{array}{c|c|c|c|c} \hline \text { Ion } & \mathrm{Na}^{+} & \mathrm{Ca}^{2+} & \mathrm{Fe}^{2+} & \mathrm{Al}^{3+} \\ \hline \mathrm{O}^{2-} & \mathrm{Na}_{2} \mathrm{O} & & & \\ \mathrm{NO}_{3}^{-} & & & & \\ \mathrm{SO}_{4}^{2-} & & & & \\ \mathrm{AsO}_{4}{ }^{3-} & & & & \\ \hline \end{array} $$

Fill in the blanks in the following table: $$ \begin{array}{l|l|l|l|} \hline \text { Cation } & \text { Anion } & \text { Formula } & \text { Name } \\\ \hline \mathrm{Ni}^{2+} & \mathrm{CH}_{3} \mathrm{COO} & & \text { Sodium carbonate } \\ & & & \\ \mathrm{Ca}^{2+} & \mathrm{F}^{-} & & \\ & & \mathrm{Cu}\left(\mathrm{ClO}_{4}\right)_{2} & \\ & & & \\ & & & \\ \hline \end{array} $$

The oxides of nitrogen are very important components in urban air pollution. Name each of the following compounds: (a) \(\mathrm{N}_{2} \mathrm{O}\) \(,(\mathbf{b}) \mathrm{NO}\) (c) \(\mathrm{NO}_{2}\) (d) \(\mathrm{N}_{2} \mathrm{O}_{5}\) (e) \(\mathrm{N}_{2} \mathrm{O}_{4}\)

Selenium, an element required nutritionally in trace quantities, forms compounds analogous to sulfur. Name the following ions: (a) \(\mathrm{SeO}_{4}^{2-}\), (b) \(\mathrm{Se}^{2-}\), (c) \(\mathrm{HSe}^{-}\), (d) \(\mathrm{HSeO}_{3}^{-}\).

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