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Is each of the following statements true or false? (a) All strong acids contain one or more \(\mathrm{H}\) atoms. (b) A strong acid is a strong electrolyte. (c) A 1.0-M solution of a strong acid will have \(\mathrm{pH}=1.0\)

Short Answer

Expert verified
(a) True, (b) True, (c) False.

Step by step solution

01

Understanding Strong Acids

Strong acids are acids that completely dissociate in water. Common strong acids include HCl, HBr, HI, HNO鈧, HClO鈧, H鈧係O鈧 (only the first dissociation is strong), and HClO鈧. Notice that all of these acids have hydrogen atoms.
02

Evaluating Statement (a)

Statement (a) claims that all strong acids contain one or more H atoms. Since an acid is defined by its ability to donate protons (H鈦 ions), having at least one H atom is essential for any compound to act as an acid. Therefore, all strong acids do contain H atoms.
03

Conclusion for Statement (a)

Statement (a) is true. All strong acids do contain one or more H atoms as they dissociate to release H鈦 ions in solution.
04

Understanding Strong Electrolytes

Strong acids are strong electrolytes because they completely dissociate in water, meaning they release ions fully and conduct electricity well in aqueous solution.
05

Evaluating Statement (b)

Statement (b) claims that a strong acid is a strong electrolyte. Since strong acids fully dissociate in solution, they release ions efficiently and conduct electricity, fitting the definition of a strong electrolyte.
06

Conclusion for Statement (b)

Statement (b) is true. A strong acid dissociates completely in solution, making it a strong electrolyte.
07

Understanding pH of Strong Acids

The pH of a solution is calculated using the formula: \( \text{pH} = -\log_{10}[H^+] \). For a 1.0 M solution of a strong acid, the concentration of \([H^+]\) ions released into the solution by the complete dissociation of the acid is 1.0 M.
08

Calculating pH for Statement (c)

Plug the 1.0 M concentration into the formula: \[ \text{pH} = -\log_{10}(1.0) = 0 \]. Thus, a 1.0-M solution of a strong acid will have a pH of 0, not 1.
09

Conclusion for Statement (c)

Statement (c) is false. A 1.0-M solution of a strong acid will have a pH of 0 because \( \text{pH} = -\log_{10}(1.0) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrolytes
When we talk about electrolytes in chemistry, we refer to substances that can dissolve in water and dissociate into ions. These ions allow the solution to conduct electricity. Electrolytes are classified into two categories: strong and weak.
Strong electrolytes dissociate completely in water. This means that every single molecule of the substance breaks apart into ions, enabling the solution to conduct electricity very effectively. On the other hand, weak electrolytes only dissociate partially, resulting in fewer ions, and thus poorer conductivity.
Strong acids are classic examples of strong electrolytes. When placed in water, they break apart completely, producing highly conductive solutions. For example, if you dissolve hydrochloric acid (HCl) in water, it completely separates into H鈦 and Cl鈦 ions. Since they release many ions into the solution, strong acids are considered strong electrolytes. Recognizing that strong acids are strong electrolytes helps us better understand their comprehensive dissociation and conductivity abilities.
pH Calculation
The pH calculation is an essential topic when discussing acids and their strengths. To put it simply, pH is a measure of how acidic or basic a solution is. It is found using the formula: \[ \text{pH} = -\log_{10}[H^+] \]
This formula calculates the pH based on the concentration of hydrogen ions \(H^+\) present in the solution.
Let's say we have a 1.0 M solution of a strong acid. In this case, the concentration of \(H^+\) ions released is also 1.0 M due to complete ionization. Using our formula: \[ \text{pH} = -\log_{10}(1.0) = 0 \]
This tells us that the solution is highly acidic with a pH of 0.
It's critical to understand that the lower the pH, the more acidic the solution; conversely, higher pH values indicate more basic solutions. This concept is pivotal in assessing the behavior and reactivity of substances in various chemical reactions.
Acid Dissociation
Acid dissociation is the process by which an acid separates into its constituent ions when dissolved in water. This is especially important for understanding the behavior of strong acids.
Strong acids, by definition, dissociate completely in aqueous solutions. They release a high concentration of hydrogen ions \(H^+\), making the solution quite acidic. This is different from weak acids, which only partially dissociate in water, releasing fewer hydrogen ions and resulting in higher pH values.
To visualize this, consider the acid HCl. In water, it separates fully into H鈦 and Cl鈦 ions, demonstrating complete dissociation. The extent of dissociation helps us determine the strength of an acid, the resulting conductivity of the solution, and make sense of the pH levels derived from it. Understanding acid dissociation is crucial for chemical reactions, predicting product formation, and even in real-world applications like titration and buffering solutions.

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Most popular questions from this chapter

Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the reaction arrow: (a) \(\mathrm{NH}_{4}^{+}(a q)+\mathrm{OH}^{-}(a q) \rightleftharpoons\) (b) \(\mathrm{CH}_{3} \mathrm{COO}^{-}(a q)+\mathrm{H}_{3} \mathrm{O}^{+}(a q) \rightleftharpoons\) (c) \(\mathrm{HCO}_{3}^{-}(a q)+\mathrm{F}^{-}(a q) \rightleftharpoons\)

Indicate whether each of the following statements is correct or incorrect. (a) Every Br酶nsted-Lowry acid is also a Lewis acid. (b) Every Lewis acid is also a Br酶nsted-Lowry acid. (c) Conjugate acids of weak bases produce more acidic solutions than conjugate acids of strong bases. (d) \(\mathrm{K}^{+}\) ion is acidic in water because it causes hydrating water molecules to become more acidic. (e) The percent ionization of a weak acid in water increases as the concentration of acid decreases.

Predict whether aqueous solutions of the following compounds are acidic, basic, or neutral: (a) \(\mathrm{NH}_{4} \mathrm{Br},(\mathbf{b}) \mathrm{FeCl}_{3}\), (c) \(\mathrm{Na}_{2} \mathrm{CO}_{3},\) (d) \(\mathrm{KClO}_{4},\) (e) \(\mathrm{NaHC}_{2} \mathrm{O}_{4}\)

Calculate the pH of each of the following solutions \(\left(K_{a}\right.\) and \(K_{b}\) values are given in Appendix D): (a) \(0.150 \mathrm{M}\) propionic acid \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{COOH}\right)\) (b) \(0.250 \mathrm{M}\) hydrogen chromate ion \(\left(\mathrm{HCrO}_{4}^{-}\right),(\mathbf{c}) 0.750 \mathrm{M}\) pyridine \(\left(\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{~N}\right)\)

Succinic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{4}\right),\) which we will denote \(\mathrm{H}_{2} \mathrm{Suc},\) is a biologically relevant diprotic acid with the structure shown below. At \(25^{\circ} \mathrm{C}\), the acid-dissociation constants for succinic acid are \(K_{a 1}=6.9 \times 10^{-5}\) and \(K_{a 2}=2.5 \times 10^{-6}\) (a) Determine the pH of a \(0.32 \mathrm{M}\) solution of \(\mathrm{H}_{2} \mathrm{Suc}\) at \(25^{\circ} \mathrm{C}\), assuming that only the first dissociation is relevant. (b) Determine the molar concentration of \(\mathrm{Suc}^{2-}\) in the solution in part (a). (c) Is the assumption you made in part (a) justified by the result from part (b)? (d) Will a solution of the salt NaHSuc be acidic, neutral, or basic?

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