/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 98 Consider a lake that is about \(... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider a lake that is about \(40 \mathrm{~m}\) deep. A gas bubble with a diameter of 1.0 mm originates at the bottom of a lake where the pressure is \(405.3 \mathrm{kPa}\). Calculate its volume when the bubble reaches the surface of the lake where the pressure is 98 kPa, assuming that the temperature does not change.

Short Answer

Expert verified
The volume of the bubble at the surface is approximately 4.14 times its initial volume.

Step by step solution

01

Understand the Problem

We have a gas bubble originating at the bottom of a lake. We need to calculate its new volume when it reaches the surface. We'll use the given pressures at the bottom and the surface and utilize Boyle's Law for this purpose.
02

Recall Boyle's Law

Boyle's Law states that for a given mass of gas at constant temperature, the product of pressure and volume is constant: \( P_1V_1 = P_2V_2 \). We'll use this relationship to find the volume of the bubble at the surface.
03

Identify Known Values

The known values are the initial diameter of the bubble, initial pressure, and final pressure. Specifically, the initial pressure \( P_1 \) is 405.3 kPa, the final pressure \( P_2 \) is 98 kPa, and the initial diameter of the bubble is 1.0 mm.
04

Calculate Initial Volume

First, find the initial volume \( V_1 \) using the formula for the volume of a sphere: \( V = \frac{4}{3} \pi r^3 \). The initial diameter is 1.0 mm, so the radius \( r \) is 0.5 mm (or 0.0005 m). Calculate \( V_1 \).
05

Setup and Solve Using Boyle's Law

Substitute the known values into Boyle's Law: \( P_1V_1 = P_2V_2 \). \( 405.3 \times V_1 = 98 \times V_2 \). Solve for \( V_2 \) to find the volume of the bubble at the surface.
06

Calculate the Final Volume

Use the initial volume \( V_1 \) calculated in Step 4 and the equation from Step 5 to determine \( V_2 \). Calculate \( V_2 \) and interpret the result.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pressure in Gases
In gases, pressure is an essential concept to understand. Pressure is the force applied per unit area, and it can vary due to changes in surrounding conditions. When you dive underwater, the pressure increases mainly because of the weight of the water above you, known as hydrostatic pressure. In the given exercise, a gas bubble starts at the bottom of a lake, where the pressure is significantly higher compared to the surface. This high pressure compresses the gas in the bubble, reducing its volume.
Understanding pressure helps us predict how the bubble behaves as it ascends. As the bubble rises, the weight of the water above it decreases, which reduces the pressure. This decrease allows the gas inside the bubble to expand, increasing its volume. This phenomena is a classic application of Boyle's Law, a fundamental gas law.
  • The pressure at greater depths is higher due to the water column above.
  • Pressure decreases as the bubble moves upwards to the surface.
  • Gas bubbles expand as pressure is relieved.
Volume Calculation
Calculating the volume of a gas bubble involves understanding the shape of the object. In science, bubbles are typically assumed to be spherical for simplicity, and to find the volume of a sphere, we use the formula:
\[ V = \frac{4}{3}\pi r^3 \]
where \(r\) is the radius of the sphere.
In the exercise, the bubble's initial diameter is given as 1.0 mm. First, we convert this measurement into meters for consistency with standard units, giving us a radius of 0.0005 m (since the radius is half of the diameter). We then substitute this radius into our formula to find the initial volume of the gas bubble.
  • The formula for spherical volume is essential for precise calculations.
  • Converting measurements to consistent units avoids calculation errors.
  • Understanding geometry aids in modeling physical scenarios.
Gas Laws
Gas laws describe how gases behave under different conditions of pressure, volume, and temperature. One of such laws is Boyle's Law, which specifically relates pressure and volume at a constant temperature.
Boyle's Law states that for a fixed mass of gas kept at a constant temperature, the product of pressure \(P\) and volume \(V\) is a constant. This can be mathematically described as:
\[ P_1V_1 = P_2V_2 \]
In our scenario, this relationship allows us to compute how the bubble's volume changes as it travels from the high-pressure environment at the lake bottom to the lower pressure one at the surface.
  • Boyle's Law is pivotal for predicting how gas volumes shift with pressures.
  • Does not require temperature changes if kept constant.
  • Simplifies complex real-world problems involving gases.

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Most popular questions from this chapter

A rigid vessel containing a \(3: 1 \mathrm{~mol}\) ratio of carbon dioxide and water vapor is held at \(200^{\circ} \mathrm{C}\) where it has a total pressure of \(202.7 \mathrm{kPa}\). If the vessel is cooled to \(10^{\circ} \mathrm{C}\) so that all of the water vapor condenses, what is the pressure of carbon dioxide? Neglect the volume of the liquid water that forms on cooling.

Magnesium can be used as a "getter" in evacuated enclosures to react with the last traces of oxygen. (The magnesium is usually heated by passing an electric current through a wire or ribbon of the metal.) If an enclosure of \(5.67 \mathrm{~L}\) has a partial pressure of \(\mathrm{O}_{2}\) of \(7.066 \mathrm{mPa}\) at \(30^{\circ} \mathrm{C},\) what mass of magnesium will react according to the following equation? $$ 2 \mathrm{Mg}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{MgO}(s) $$

A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required \(105 \mathrm{~s}\) for \(1.0 \mathrm{~L}\) of the gas to effuse. Under identical experimental conditions it required \(31 \mathrm{~s}\) for \(1.0 \mathrm{~L}\) of \(\mathrm{O}_{2}\) gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of \(1.0 \mathrm{~L} ; \mathrm{in}\) other words, rate is the amount that diffuses over the time it takes to diffuse.)

The temperature of a 5.00-L container of \(\mathrm{N}_{2}\) gas is increased from \(20^{\circ} \mathrm{C}\) to \(250^{\circ} \mathrm{C}\). If the volume is held constant, predict qualitatively how this change affects the following: (a) the average kinetic energy of the molecules; \((\mathbf{b})\) the rootmean- square speed of the molecules; (c) the strength of the impact of an average molecule with the container walls; d) the total number of collisions of molecules with walls per second.

Perform the following conversions: (a) 0.912 atm to torr, (b) 0.685 bar to kilopascals, (c) \(655 \mathrm{~mm}\) Hg to atmospheres, (d) \(1.323 \times 10^{5}\) Pa to atmospheres, (e) 2.50 atm to psi.

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