/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 Which statement concerning the v... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Which statement concerning the van der Waals constants \(a\) and \(b\) is true? (a) The magnitude of \(a\) relates to molecular volume, whereas \(b\) relates to attractions between molecules. (b) The magnitude of \(a\) relates to attractions between molecules, whereas \(b\) relates to molecular volume. (c) The magnitudes of \(a\) and \(b\) depend on pressure. (d) The magnitudes of \(a\) and \(b\) depend on temperature.

Short Answer

Expert verified
(b) The magnitude of \(a\) relates to attractions between molecules, whereas \(b\) relates to molecular volume.

Step by step solution

01

Understanding the van der Waals Equation

The van der Waals equation is \( \left( P + \frac{a}{V_m^2} \right) (V_m - b) = RT \), where \( P \) is pressure, \( V_m \) is molar volume, \( R \) is the gas constant, \( T \) is temperature, \( a \) accounts for intermolecular forces, and \( b \) accounts for the volume occupied by gas molecules.
02

Identifying the Role of Constant a

The constant \( a \) in the van der Waals equation corrects for the intermolecular attractions between gas molecules. Stronger attractions lead to a larger \( a \) value, thus it relates to attractions between molecules.
03

Identifying the Role of Constant b

The constant \( b \) corrects for the finite volume occupied by gas molecules, reducing the available volume for the molecules' motion. This means that \( b \) relates to the molecular volume, or the size of the gas molecules themselves.
04

Analyzing the Statements

Review the options: - (a) Incorrect: It incorrectly reverses the roles of \( a \) and \( b \).- (b) Correct: It correctly states \( a \) relates to attractions and \( b \) to molecular volume.- (c) Incorrect: Constants \( a \) and \( b \) are independent of pressure.- (d) Incorrect: Constants \( a \) and \( b \) are independent of temperature.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intermolecular Forces
Intermolecular forces are the forces that act between molecules and influence many physical properties of substances, including boiling points, melting points, and solubilities. In the context of the van der Waals equation, the constant \( a \) accounts for these forces. Unlike ideal gases, real gases have attractions between molecules that affect their behavior.Types of Intermolecular Forces
Differences in molecular interactions arise from types of intermolecular forces, such as:
  • Dipole-Dipole Interactions: These occur between molecules that have permanent dipoles, meaning they have a partial positive and partial negative charge.
  • London Dispersion Forces: All molecules exhibit these forces, arising due to temporary dipoles induced in molecules.
  • Hydrogen Bonds: A strong type of dipole interaction, present especially in molecules where hydrogen is bonded to more electronegative elements like nitrogen, oxygen, or fluorine.
The presence and strength of these forces can explain the non-ideal behavior of gases, and the need for correction in the van der Waals equation.
Molecular Volume
Molecular volume refers to the physical space that the molecules of a substance occupy. In the van der Waals equation, the constant \( b \) is used to account for the volume occupied by gas molecules, acknowledging that unlike ideal gas, these particles do take up a portion of the total volume in which they are contained.Understanding the Molecular Volume
When assessing real gases, it's important to consider:
  • Finite Volume of Molecules: Each molecule occupies a specific space, which reduces the volume available for gas molecule movement.
  • Proportional to Size: The value of \( b \) is related to the size of a molecule. Larger molecules will result in a higher \( b \) value because they occupy more space.
  • Correction in Gas Laws: Inaccuracies from ignoring molecular volume are rectified by the inclusion of \( b \) in the van der Waals equation.
Because of this, the concept of molecular volume is significant when working with gases at high pressures and low temperatures, where deviations from ideal behavior become more pronounced.
Gas Laws
Gas laws are mathematical relationships and equations that describe the behavior of gases. These laws include both ideal and non-ideal conditions. The importance of understanding these laws lies in their ability to predict how gases will respond to changes in pressure, volume, and temperature.From Ideal to Real Gases
Ideal gas laws, such as Charles’s Law, Boyle's Law, and Avogadro's Law, assume gases do not interact and occupy no space. These assumptions are accurate for ideal gases but do not hold for real gases as interactions and volume becomes apparent at extreme conditions.
  • Ideal Gas Law: This formula \( PV = nRT \) sets a basis for behavior under ideal conditions, where \( P \) is pressure, \( V \) is volume, \( n \) is the number of moles, \( R \) is the gas constant, and \( T \) is temperature.
  • Van der Waals Equation: Adjusts the ideal gas law by introducing constants \( a \) and \( b \), accounting for intermolecular forces and molecular volume, respectively.
  • Significance of Van der Waals Equation: It provides greater accuracy for real gas behavior, especially under high-pressure and low-temperature conditions.
Studying gas laws, including corrections from the van der Waals equation, is crucial for applications in chemistry and engineering that involve real gases.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The physical fitness of athletes is measured by \({ }^{4} V_{\mathrm{O}_{2}}\) max," which is the maximum volume of oxygen consumed by an individual during incremental exercise (for example, on a treadmill). An average male has a \(V_{\mathrm{O}_{2}}\) max of \(45 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}\) body mass/min, but a world-class male athlete can have a \(V_{\mathrm{O}_{2}}\) max reading of \(88.0 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}\) body mass \(/ \mathrm{min}\). (a) Calculate the volume of oxygen, in \(\mathrm{mL}\), consumed in \(1 \mathrm{hr}\) by an average man who weighs \(85 \mathrm{~kg}\) and has a \(V_{\mathrm{O}_{2}}\) max reading of \(47.5 \mathrm{~mL}\) \(\mathrm{O}_{2} / \mathrm{kg}\) body mass \(/ \mathrm{min} .(\mathbf{b})\) If this man lost \(10 \mathrm{~kg}\), exercised, and increased his \(V_{\mathrm{O}_{2}} \max\) to \(65.0 \mathrm{~mL} \mathrm{O}_{2} / \mathrm{kg}\) body mass \(/ \mathrm{min}\) how many \(\mathrm{mL}\) of oxygen would he consume in \(1 \mathrm{hr}\) ?

When a large evacuated flask is filled with argon gas, its mass increases by \(3.224 \mathrm{~g}\). When the same flask is again evacuated and then filled with a gas of unknown molar mass, the mass increase is \(8.102 \mathrm{~g}\). (a) Based on the molar mass of argon, estimate the molar mass of the unknown gas. (b) What assumptions did you make in arriving at your answer?

You have a gas at \(25^{\circ} \mathrm{C}\) confined to a cylinder with a movable piston. Which of the following actions would double the gas pressure? (a) Lifting up on the piston to double the volume while keeping the temperature constant; (b) Heating the gas so that its temperature rises from \(25^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\), while keeping the volume constant; (c) Pushing down on the piston to halve the volume while keeping the temperature constant.

An ideal gas at a pressure of \(152 \mathrm{kPa}\) is contained in a bulb of unknown volume. A stopcock is used to connect this bulb with a previously evacuated bulb that has a volume of \(0.800 \mathrm{~L}\) as shown here. When the stopcock is opened, the gas expands into the empty bulb. If the temperature is held constant during this process and the final pressure is \(92.66 \mathrm{kPa}\), what is the volume of the bulb that was originally filled with gas?

A mixture containing \(0.50 \mathrm{~mol} \mathrm{H}_{2}(g), 1.00 \mathrm{~mol} \mathrm{O}_{2}(g)\), and 3.50 \(\mathrm{mol} \mathrm{N}_{2}(g)\) is confined in a 25.0-L vessel at \(25^{\circ} \mathrm{C}\). (a) Calculate the total pressure of the mixture. (b) Calculate the partial pressure of each of the gases in the mixture.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.