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Consider a mixture of two gases, \(A\) and \(B\), confined in a closed vessel. A quantity of a third gas, \(\mathrm{C}\), is added to the same vessel at the same temperature. How does the addition of gas \(C\) affect the following: (a) the partial pressure of gas \(\mathrm{A},(\mathbf{b})\) the total pressure in the vessel, (c) the mole fraction of gas B?

Short Answer

Expert verified
(a) Partial pressure of gas A remains unchanged. (b) Total pressure increases. (c) Mole fraction of gas B decreases.

Step by step solution

01

Understand Dalton's Law of Partial Pressures

Dalton's Law states that in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of the partial pressures of individual gases. The partial pressure of each gas is the pressure it would exert if it were alone in the container. Thus, initially, the partial pressure of gas A is determined only by its amount and the container's volume.
02

Consider Adding Gas C

When gas C is added to the vessel, it increases the total number of moles of gas in the vessel but does not change the individual moles of gases A and B. Therefore, according to Dalton's Law, the addition of gas C doesn't alter the partial pressures of gases A or B, since these depend solely on their respective amounts and the volume of the vessel.
03

Analyze Effect on Total Pressure

The addition of gas C increases the total number of moles of gas, thus increasing the total pressure in the vessel. Total pressure is the sum of all partial pressures, so with the added moles from gas C, the total pressure will increase even though the partial pressures of A and B remain unchanged.
04

Determine Effect on Mole Fraction of Gas B

The mole fraction of a gas is the ratio of the moles of that gas to the total moles of all gases in the mixture. Adding gas C increases the total number of moles in the vessel, thus decreasing the mole fraction of gas B since the denominator (total moles) increases while the numerator (moles of gas B) stays the same.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Pressure
The concept of partial pressure is central to understanding gas mixtures. Each gas in a mixture exerts a pressure independently of the others. This "partial pressure" is defined as the pressure a gas would exert if it occupied the container alone. For example, in our scenario with gases A and B, each has its own partial pressure based on its particular amount within the vessel's volume. These pressures are additive according to Dalton's Law. Even with the introduction of a third gas, C, into the vessel, the partial pressures of A and B remain unchanged. Each gas's partial pressure depends solely on its own quantity and the container's volume, not on the presence of other gases.
Total Pressure
Total pressure in a gas mixture is the sum of the partial pressures of all the individual gases present. In our case, when gas C is added, the total pressure is affected because more gas molecules are present in the same volume. According to Dalton's Law of Partial Pressures, the total pressure is calculated by adding up the partial pressures of all gases. So, if C is added to gases A and B, the total pressure increases due to the additional molecules. The partial pressures of A and B remain constant because they depend on the number of moles of each specific gas, not on the contribution of other gases.
Mole Fraction
The mole fraction is a way to express the concentration of a gas in a mixture relative to the total amount of gas. It is calculated by dividing the number of moles of a particular gas by the total number of moles of all gases in the mixture. For example, if gas B has 2 moles and the total moles of all gases is 10, the mole fraction of B is 0.2. When gas C is added, while the moles of B remain the same, the total moles increase. Hence, the mole fraction of B decreases because its ratio to the total moles has changed. Understanding how the mole fraction is influenced by the presence of other gases can help in various practical applications involving gas mixtures.
Gas Mixtures
Gas mixtures are common in both natural environments and industrial processes. Each gas in such a mixture contributes differently to the overall properties. Unlike a simple compound, where substances combine chemically, gases in a mixture retain their individual properties. The behavior of these gas mixtures is often described using Dalton’s Law, which helps us understand how partial and total pressures work together. In our exercise, adding gas C changes the overall properties of the gas mixture without affecting some individual components. Handling and manipulating gas mixtures effectively requires a clear understanding of these fundamental concepts. They are crucial for fields such as chemistry, environmental science, and chemical engineering.

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Most popular questions from this chapter

Which of the following statements best explains why a closed balloon filled with helium gas rises in air? (a) Helium is a monatomic gas, whereas nearly all the molecules that make up air, such as nitrogen and oxygen, are diatomic. (b) The average speed of helium atoms is greater than the average speed of air molecules, and the greater speed of collisions with the balloon walls propels the balloon upward. (c) Because the helium atoms are of lower mass than the average air molecule, the helium gas is less dense than air. The mass of the balloon is thus less than the mass of the air displaced by its volume. (d) Because helium has a lower molar mass than the average air molecule, the helium atoms are in faster motion. This means that the temperature of the helium is greater than the air temperature. Hot gases tend to rise.

Perform the following conversions: (a) 0.912 atm to torr, (b) 0.685 bar to kilopascals, (c) \(655 \mathrm{~mm}\) Hg to atmospheres, (d) \(1.323 \times 10^{5}\) Pa to atmospheres, (e) 2.50 atm to psi.

You have an evacuated container of fixed volume and known mass and introduce a known mass of a gas sample. Measuring the pressure at constant temperature over time, you are surprised to see it slowly dropping. You measure the mass of the gas-filled container and find that the mass is what it should be-gas plus container-and the mass does not change over time, so you do not have a leak. Suggest an explanation for your observations.

At an underwater depth of \(100 \mathrm{~m}\), the pressure is \(1.106 \mathrm{MPa}\). What should the partial pressure of oxygen be in the diving gas for the mole fraction of oxygen in the mixture to be 0.21 , the same as in air?

In an experiment reported in the scientific literature, male cockroaches were made to run at different speeds on a miniature treadmill while their oxygen consumption was measured. In 30 minutes the average cockroach (running at \(0.08 \mathrm{~km} / \mathrm{h})\) consumed \(1.0 \mathrm{~mL}\) of \(\mathrm{O}_{2}\) at \(101.33 \mathrm{kPa}\) pressure and \(20^{\circ} \mathrm{C}\) per gram of insect mass. (a) How many moles of \(\mathrm{O}_{2}\) would be consumed in 1 day by a 6.3 -g cockroach moving at this speed? (b) This same cockroach is caught by a child and placed in a 2.0-L fruit jar with a tight lid. Assuming the same level of continuous activity as in the research, how much of the available \(\mathrm{O}_{2}\) will the cockroach consume in 1 day? (Air is \(21 \mathrm{~mol} \% \mathrm{O}_{2}\).)

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