/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 The decomposition of hydrogen pe... [FREE SOLUTION] | 91影视

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The decomposition of hydrogen peroxide is catalyzed by iodide ion. The catalyzed reaction is thought to proceed by a two-step mechanism: $$ \begin{aligned} \mathrm{H}_{2} \mathrm{O}_{2}(a q)+\mathrm{I}^{-}(a q) & \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{IO}^{-}(a q) & \text { (slow) } \\ \mathrm{IO}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}_{2}(a q) & \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{O}_{2}(g)+\mathrm{I}^{-}(a q) & \text { (fast) } \end{aligned} $$ (a) Write the rate law for each of the elementary reactions of the mechanism. (b) Write the chemical equation for the overall process. (c) Identify the intermediate, if any, in the mechanism. (d) Assuming that the first step of the mechanism is rate determining, predict the rate law for the overall process.

Short Answer

Expert verified
(a) The rate laws for the elementary reactions are: Rate1 = k1 [H鈧侽鈧俔 [I鈦籡 Rate2 = k2 [IO鈦籡 [H鈧侽鈧俔 (b) The overall process is: 2 H鈧侽鈧 (aq) 鈫 2 H鈧侽 (l) + O鈧 (g) (c) The intermediate in the mechanism is IO鈦. (d) The rate law for the overall process, assuming the first step is rate-determining, is: Rate = k [H鈧侽鈧俔 [I鈦籡

Step by step solution

01

a) Write the rate law for each of the elementary reactions.

For each elementary reaction, the rate depends on the concentration of the reactants. We can represent the rate of a reaction as follows: Rate = k [Reactant 1]^m [Reactant 2]^n Here, k is the rate constant, and m and n are the reaction orders with respect to Reactant 1 and Reactant 2, respectively. For an elementary reaction, the reaction orders are equal to the stoichiometric coefficients of the molecules involved in the reaction. For the first elementary reaction: Rate1 = k1 [H鈧侽鈧俔 [I鈦籡 For the second elementary reaction: Rate2 = k2 [IO鈦籡 [H鈧侽鈧俔 where Rate1 and Rate2 are the rates of the first and second reactions, and k1 and k2 are their respective rate constants.
02

b) Write the chemical equation for the overall process.

To find the overall chemical equation, we need to add the chemical equations of the elementary reactions, taking into account the cancellation of intermediates from the two reactions. First reaction: H鈧侽鈧 (aq) + I鈦 (aq) 鈫 H鈧侽 (l) + IO鈦 (aq) (slow) Second reaction: IO鈦 (aq) + H鈧侽鈧 (aq) 鈫 H鈧侽 (l) + O鈧 (g) + I鈦 (aq) (fast) Now, we can add these two equations and cancel the intermediates: H鈧侽鈧 (aq) + I鈦 (aq) 鈫 H鈧侽 (l) + IO鈦 (aq) + IO鈦 (aq) + H鈧侽鈧 (aq) 鈫 H鈧侽 (l) + O鈧 (g) + I鈦 (aq) Overall process: 2 H鈧侽鈧 (aq) 鈫 2 H鈧侽 (l) + O鈧 (g)
03

c) Identify the intermediate, if any, in the mechanism.

An intermediate is a species that is produced in one elementary reaction and consumed in another elementary reaction. In this case, the intermediate is the IO鈦 species, as it is produced in the first elementary reaction and consumed in the second elementary reaction.
04

d) Predict the rate law for the overall process, assuming the first step is rate-determining.

Since the first step is the rate-determining (slow) step, the overall rate of the reaction is determined by the first elementary reaction. Therefore, the rate law for the overall process is the same as the rate law for the first elementary reaction: Rate = k [H鈧侽鈧俔 [I鈦籡 This rate law states that the rate of the overall decomposition of hydrogen peroxide catalyzed by iodide ions depends on the concentration of hydrogen peroxide and iodide ions and the rate constant k.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
Understanding the rate law in chemical reactions is crucial for predicting how quickly a reaction will occur. The rate law expresses the relationship between the rate of a chemical reaction and the concentration of its reactants. To write a rate law, we must know the order of the reaction with respect to each reactant, which tells us how the rate is affected by changes in that reactant's concentration.

In the example of the catalyzed decomposition of hydrogen peroxide by iodide ion, the rate law for each step in the mechanism is derived from the stoichiometry of the elementary reactions. If we consider the first step as rate-determining, the rate law would be: \[ \text{Rate} = k[H_2O_2][I^-] \] Here, the rate is directly proportional to the concentrations of hydrogen peroxide and iodide ion. This means the reaction is first order with respect to each reactant, leading us to a second order overall rate law for the initial, rate-determining step.
Chemical Kinetics
Chemical kinetics deals with the speeds, or rates, of chemical reactions and the factors that affect these rates. Key concepts within kinetics include the idea of reaction rates, the nature of the reactants, the concentration of reactants, and the presence of a catalyst. These factors, alongside temperature and surface area, can significantly change how fast a reaction proceeds.

In the context of the hydrogen peroxide decomposition, kinetics explains how the presence of the iodide ion speeds up the reaction. A catalyst like the iodide ion provides an alternative reaction pathway with a lower activation energy, allowing the reaction to proceed faster at a given temperature. Chemical kinetics is also fundamentally intertwined with thermodynamics, which provides a broader picture of whether a reaction is favored to occur, while kinetics specifically describes how quickly it can happen when it is favored.
Reaction Mechanism
The reaction mechanism provides a detailed description of the steps through which reactants are transformed into products. This includes specifying which bonds are broken and formed and in what sequence, the transition states and intermediates involved, and which step of the process is the slowest or rate-determining.

In the decomposition of hydrogen peroxide, the proposed two-step mechanism highlights a slow initial step followed by a fast subsequent step. The presence of an intermediate, IO鈦, which is produced in the first step and consumed in the second, is characteristic of reaction mechanisms in which multiple steps are linked together. Students should note that reaction mechanisms cannot be determined solely by looking at the overall chemical equation; they must be deduced from experimental evidence and often involve intermediates that do not appear in the final equation for the reaction.
Elementary Reactions
Elementary reactions are the simplest steps in a reaction mechanism which occur in a single event or collision. In other words, their rate laws can be written based on the stoichiometric coefficients of the reactants involved in the reaction. These reactions are critical to understanding overall reaction mechanisms because they represent the actual sequence of events at the molecular level.

An example of an elementary reaction is the initial interaction between hydrogen peroxide and iodide ion in the catalysis of hydrogen peroxide decomposition. The assumption that this first step is the rate-determining step means that it is slower than any subsequent steps and thus sets the pace for the overall reaction. This highlights the importance of elementary reactions in determining the kinetics of a complex reaction.

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Most popular questions from this chapter

Zinc metal dissolves in hydrochloric acid according to the reaction $$ \mathrm{Zn}(\mathrm{s})+2 \mathrm{HCl}(a q)--\rightarrow \operatorname{ZnCl}_{2}(a q)+\mathrm{H}_{2}(g) $$ Suppose you are asked to study the kinetics of this reaction by monitoring the rate of production of \(\mathrm{H}_{2}(g)\). (a) By using a reaction flask, a manometer, and any other common laboratory equipment, design an experimental apparatus that would allow you to monitor the partial pressure of \(\mathrm{H}_{2}(g)\) produced as a function of time. (b) Explain how you would use the apparatus to determine the rate law of the reaction. (c) Explain how you would use the apparatus to determine the reaction order for \(\left[\mathrm{H}^{+}\right]\) for the reaction. (d) How could you use the apparatus to determine the activation energy of the reaction? (e) Explain how you would use the apparatus to determine the effects of changing the form of \(\mathrm{Zn}(s)\) from metal strips to granules.

One of the many remarkable enzymes in the human body is carbonic anhydrase, which catalyzes the interconversion of carbonic acid with carbon dioxide and water. If it were not for this enzyme, the body could not rid itself rapidly enough of the \(\mathrm{CO}_{2}\) accumulated by cell metabolism. The enzyme catalyzes the dehydration (release to air) of up to \(10^{7} \mathrm{CO}_{2}\) molecules per second. Which components of this description correspond to the terms enzyme, substrate, and turnover number?

Explain why rate laws generally cannot be written from balanced equations. Under what circumstance is the rate law related directly to the balanced equation for a reaction?

The reaction between ethyl iodide and hydroxide ion in ethanol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\) solution, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}(a l c)+\mathrm{OH}^{-}(a l c)\) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{I}^{-}(a l c)\), has an activation energy of \(86.8 \mathrm{~kJ} / \mathrm{mol}\) and a frequency factor of \(2.10 \times 10^{11} \mathrm{M}^{-1} \mathrm{~s}^{-1}\). (a) Predict the rate constant for the reaction at \(35^{\circ} \mathrm{C} .\) (b) \(\mathrm{A}\) solution of KOH in ethanol is made up by dissolving \(0.335\) g KOH in ethanol to form \(250.0 \mathrm{~mL}\) of solution. Similarly, \(1.453 \mathrm{~g}\) of \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}\) is dissolved in ethanol to form \(250.0 \mathrm{~mL}\) of solution. Equal volumes of the two solutions are mixed. Assuming the reaction is first order in each reactant, what is the initial rate at \(35^{\circ} \mathrm{C} ?(\mathrm{c})\) Which reagent in the reaction is limiting, assuming the reaction proceeds to completion?

The decomposition of \(\mathrm{N}_{2} \mathrm{O}_{5}\) in carbon tetrachloride proceeds as follows: \(2 \mathrm{~N}_{2} \mathrm{O}_{5} \longrightarrow 4 \mathrm{NO}_{2}+\mathrm{O}_{2} .\) The rate law is first order in \(\mathrm{N}_{2} \mathrm{O}_{5}\). At \(64{ }^{\circ} \mathrm{C}\) the rate constant is \(4.82 \times 10^{-3} \mathrm{~s}^{-1}\). (a) Write the rate law for the reaction. (b) What is the rate of reaction when \(\left[\mathrm{N}_{2} \mathrm{O}_{5}\right]=0.0240 \mathrm{M} ?(\mathrm{c})\) What happens to the rate when the concentration of \(\mathrm{N}_{2} \mathrm{O}_{5}\) is doubled to \(0.0480 \mathrm{M} ?\)

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