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Explain why rate laws generally cannot be written from balanced equations. Under what circumstance is the rate law related directly to the balanced equation for a reaction?

Short Answer

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In summary, rate laws cannot be directly written from balanced equations as they involve reaction orders, which are not determined by stoichiometry. Instead, reaction mechanisms consisting of elementary reactions define the rate law. The rate law is directly related to the balanced equation only if the rate-determining step resembles the balanced equation, which rarely occurs. Understanding the reaction mechanism is crucial before assuming a direct relationship between the rate law and the balanced equation.

Step by step solution

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1. Elementary Reactions

Elementary reactions are single-step reactions that proceed via a single transition state, with the rate law being directly related to the balanced equation. The rate of an elementary reaction is directly proportional to the product of the concentrations of each reactant raised to the power of their stoichiometric coefficients.
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2. Non-Elementary Reactions

Non-elementary reactions consist of multiple elementary reactions, each with its own rate law and reaction order. The overall rate law of a non-elementary reaction cannot be determined directly from its balanced equation because the reaction involves multiple steps, each with different reaction orders. The overall rate of the reaction is usually determined by the slowest elementary reaction, or the rate-determining step.
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3. Reaction Mechanisms and Rate Laws

To construct the rate law for a non-elementary reaction, we need to establish the reaction mechanism, which consists of a series of elementary reactions that lead to the overall reaction. The rate law for each elementary reaction can be written based on its balanced equation, but the rate law for the overall reaction must be determined experimentally or through analyzing the reaction mechanism.
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4. Rate Law directly related to the Balanced Equation

Under certain circumstances, the overall rate law for a non-elementary reaction can be related to the balanced equation. If the rate-determining step (the slowest step) has a direct relation between its rate law and its balanced equation, then the overall rate law resembles the balanced equation for the reaction. However, such a situation is very rare, and it's important to remember that you cannot assume the rate law directly follows the balanced equation without understanding the reaction mechanism. In conclusion, rate laws generally cannot be written from balanced equations because the stoichiometry of the reaction does not necessarily define the reaction order, which depends on the reaction mechanism. The rate law is directly related to the balanced equation only under the specific circumstance where the rate-determining step within a reaction mechanism resembles the balanced equation, which is relatively rare.

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Most popular questions from this chapter

(a) What is meant by the term reaction rate? (b) Name three factors that can affect the rate of a chemical reaction. (c) What information is necessary to relate the rate of disappearance of reactants to the rate of appearance of products?

(a) For a second-order reaction, what quantity, when graphed versus time, will yield a straight line? (b) How do the half-lives of first-order and second- order reactions differ?

(a) Define the following symbols that are encountered in rate equations: \([\mathrm{A}]_{0}, t_{1 / 2}[\mathrm{~A}]_{t}, k\). (b) What quantity, when graphed versus time, will yield a straight line for a firstorder reaction?

The following mechanism has been proposed for the gas-phase reaction of chloroform \(\left(\mathrm{CHCl}_{3}\right)\) and chlorine: Step 1: \(\mathrm{Cl}_{2}(g) \underset{k_{-1}}{\stackrel{k_{1}}{\rightleftarrows}} 2 \mathrm{Cl}(g) \quad\) (fast) Step 2: \(\mathrm{Cl}(g)+\mathrm{CHCl}_{3}(g) \stackrel{k_{3}}{\longrightarrow} \mathrm{HCl}(g)+\mathrm{CCl}_{3}(g)\) (slow) Step 3: \(\mathrm{Cl}(g)+\mathrm{CCl}_{3}(g) \stackrel{k_{2}}{\longrightarrow} \mathrm{CCl}_{4}\) (fast) (a) What is the overall reaction? (b) What are the intermediates in the mechanism? (c) What is the molecularity of each of the elementary reactions? (d) What is the rate-determining step? (e) What is the rate law predicted by this mechanism? (Hint: The overall reaction order is not an integer.)

What is the molecularity of each of the following elementary reactions? Write the rate law for each. (a) \(\mathrm{Cl}_{2}(g) \stackrel{-\longrightarrow}{\longrightarrow} 2 \mathrm{Cl}(g)\) (b) \(\mathrm{OCl}^{-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{HOCl}(a q)+\mathrm{OH}^{-}(a q)\) (c) \(\mathrm{NO}(g)+\mathrm{Cl}_{2}(g) \longrightarrow \operatorname{NOCl}_{2}(g)\)

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