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(a) Using Lewis symbols, diagram the reaction between magnesium and oxygen atoms to give the ionic substance MgO. (b) How many electrons are transferred? (c) Which atom loses electrons in the reaction?

Short Answer

Expert verified
(a) The Lewis symbols for the reaction between magnesium and oxygen are: Mg •• → Mg^(2+) + 2e^(-) O••• + 2e^(-) → O^(2-) •• The reaction forms magnesium oxide (MgO): Mg^(2+) + O^(2-) → MgO. (b) 2 electrons are transferred in this reaction. (c) The magnesium atom (Mg) loses electrons in the reaction.

Step by step solution

01

Determine the Lewis symbols of Magnesium and Oxygen atoms.

Recall that Lewis symbols represent the valence electrons of an atom as dots surrounding its chemical symbol. Magnesium is in group 2 of the periodic table and has 2 valence electrons, so its Lewis symbol is Mg with two dots around it. Oxygen is in group 16 (or 6A) and has 6 valence electrons, so its Lewis symbol is O with six dots (in 4 groups of lone pairs) surrounding it. Mg: •• O: ••• ••
02

Use Lewis symbols to show the electron transfer.

Ionic substances are formed when one atom transfers its valence electrons to another atom, creating a complete octet (8 valence electrons) for both atoms. In the reaction between magnesium and oxygen, magnesium will lose its 2 valence electrons to oxygen. The Lewis symbols for this reaction are: Mg •• → Mg^(2+) + 2e^(-) O••• + 2e^(-) → O^(2-) ••
03

Show the formation of the ionic substance MgO.

Now that the electron transfer has occurred, the magnesium ion (Mg^(2+)) and the oxygen ion (O^(2-)) are attracted to each other by electrostatic forces. This attraction forms the ionic substance magnesium oxide (MgO). Mg^(2+) + O^(2-) → MgO
04

Answer part (b) and (c) of the exercise.

(b) Count the number of electrons transferred during the reaction. In our case, magnesium transferred 2 electrons to oxygen. Therefore, 2 electrons were transferred. (c) Magnesium (Mg) loses its 2 valence electrons during the reaction, becoming positively charged (Mg^(2+)).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Transfer
Electron transfer is a fundamental concept in chemistry, particularly in the formation of ionic compounds. It refers to the movement of electrons from one atom to another during a chemical reaction, leading to the creation of ions.

For example, consider the reaction between magnesium and oxygen to form magnesium oxide (MgO). Magnesium has two electrons in its outermost energy level, also known as its valence shell. Oxygen, on the other hand, has six valence electrons, but it needs eight to achieve a stable electron configuration. During the reaction, magnesium donates its two valence electrons to oxygen, transforming into a positively charged magnesium ion (Mg^(2+)), while oxygen becomes a negatively charged oxide ion (O^(2-)).

Significance of Electron Transfer

The process of electron transfer has profound importance as it not only dictates the type of bond that forms between atoms but also affects the electrical conductivity, magnetic properties, and chemical reactivity of substances. Ultimately, electron transfer leads to the creation of ionic compounds, which are essential in various industries and biological systems.
Ionic Substances
Ionic substances are chemical compounds composed of positively and negatively charged ions held together by strong electrostatic forces known as ionic bonds. These substances usually form when metals react with nonmetals, with the metal atoms donating electrons to the nonmetal atoms.

Following electron transfer, the resulting ions—cations (positively charged) and anions (negatively charged)—are attracted to each other due to their opposite charges, creating a regular spatial arrangement known as a crystal lattice. This lattice is a defining property of ionic substances, contributing to their high melting and boiling points, solid state at room temperature, and ability to conduct electricity when dissolved in water or melted.

Properties of Ionic Substances

Ionic substances have distinctive characteristics: they tend to be hard and brittle, have high melting and boiling points, and can conduct electricity when in a liquid state or aqueous solution. The ionic substance magnesium oxide, formed by the reaction between magnesium and oxygen, showcases these properties, making it useful in refractory materials, electrical insulators, and more.
Valence Electrons
Valence electrons are the electrons located in an atom's outermost shell and are involved in chemical bonding. An atom's chemical behavior is primarily dictated by these electrons since they can be lost, gained, or shared during reactions to form molecules or ionic compounds.

The number of valence electrons in an atom is determined by its position in the periodic table. For instance, magnesium (Mg), a group 2 element, has two valence electrons, which are easily lost to become a Mg^(2+) ion. Oxygen (O), on the other hand, is in group 16, meaning it has six valence electrons, and tends to gain two electrons to achieve a full octet.

Octet Rule

Understanding valence electrons is crucial because of the octet rule, which postulates that atoms tend to bond in a way that leaves them with eight valence electrons, resembling the electron configuration of a noble gas. This quest for electronic stability leads to the diverse range of chemical compounds seen in nature and is a cornerstone of predicting an atom's reactivity and the types of bonds it can form.

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Most popular questions from this chapter

The hypochlorite ion, \(\mathrm{ClO}^{-},\) is the active ingredient in bleach. The perchlorate ion, \(\mathrm{ClO}_{4}^{-},\) is a main component of rocket propellants. Draw Lewis structures for both ions (a) What is the formal charge of Cl in the hypochlorite ion? (b) What is the formal charge of Cl in the perchlorate ion, assuming the Cl-O bonds are all single bonds? (c) What is the oxidation number of Cl in the hypochlorite ion? (d) What is the oxidation number of \(C l\) in the perchlorate ion, assuming the \(C l-O\) bonds are all single bonds? (e) In a redox reaction, which ion would you expect to be more easily reduced?

Ammonium chloride, \(\mathrm{NH}_{4} \mathrm{Cl},\) is a very soluble salt in water. (a) Draw the Lewis structures of the ammonium and chloride ions. (b) Is there an \(\mathrm{N}-\) Cl bond in solid ammonium chloride? (c) If you dissolve 14 gof ammonium chloride in 500.0 \(\mathrm{mL}\) of water, what is the molar concentration of the solution? (d) How many grams of silver nitrate do you need to add to the solution in part (c) to precipitate all of the chloride as silver chloride?

The substance chlorine monoxide, ClO(g), is important in atmospheric processes that lead to depletion of the ozone layer. The ClO molecule has an experimental dipole moment of \(1.24 \mathrm{D},\) and the \(\mathrm{Cl}-\) O bond length is 1.60 \(\mathrm{A}\) . (a) Determine the magnitude of the charges on the Cl and O atoms in units of the electronic charge, \(e\) (b) Based on the electronegativities of the elements, which atom would you expect to have a partial negative charge in the Clo molecule? (c) Using formal charges as a guide, propose the dominant Lewis structure for the molecule. (d) The anion \(\mathrm{ClO}^{-}\) exists. What is the formal charge on the Cl for the best Lewis structure for \(\mathrm{ClO}^{-}\) ?

Although \(\mathrm{I}_{3}\) is a known ion, \(\mathrm{F}_{3}^{-}\) is not. (a) Draw the Lewis structure for \(\mathrm{I}_{3}^{-}\) (it is linear, not a triangle). (b) One of your classmates says that \(\mathrm{F}_{3}^{-}\) does not exist because \(\mathrm{Fis}\) too electronegative to make bonds with another atom. Give an example that proves your classmate is wrong. (c) Another classmate says \(\mathrm{F}_{3}^{-}\) does not exist because it would violate the octet rule. Is this classmate possibly correct? (d) Yet another classmate says \(\mathrm{F}_{3}^{-}\) does not exist because \(\mathrm{F}\) is too small to make bonds to more than one atom. Is this classmate possibly correct?

Draw the Lewis structures for each of the following molecules or ions. Identify instances where the octet rule is not obeyed; state which atom in each compound does not follow the octet rule; and state how many electrons surround these atoms: (a) \(\mathrm{NO},(\mathbf{b}) \mathrm{BF}_{3},(\mathbf{c}) \mathrm{ICl}_{2}^{-},(\mathbf{d}) \mathrm{OPBr}_{3}(\) the \(\mathrm{P}\) is the central atom), (e) XeF.

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