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Write the Lewis symbol for atoms of each of the following elements: (a) Al, (b) Br, (c) Ar, (d) Sr.

Short Answer

Expert verified
(a) Al: \(\cdot \:\:Al\:\: \cdot \: \cdot \) (b) Br: \(\dot{\hspace{0.25ex}} \: \stackrel{..}{Br} \: \dot{\hspace{0.25ex}} \: {\hspace{0.25ex}..}\) (c) Ar: \(\stackrel{..}{Ar}\:({\hspace{0.25ex}..})\) (d) Sr: \(\stackrel{..}{Sr}\)

Step by step solution

01

Determine the number of valence electrons for each element.

Using the periodic table, we can find the group number for each element. Valence electrons are the outermost electrons of an atom and these determine the chemical properties of that element. The group number of an element in the periodic table, excluding transition metals, corresponds to the number of valence electrons. Let's find the group numbers for each of the given elements: (a) Al (aluminum) - Group 13 (b) Br (bromine) - Group 17 (c) Ar (argon) - Group 18 (d) Sr (strontium) - Group 2
02

Draw the Lewis symbols for each element.

Now that we know the number of valence electrons for each element, we can draw the Lewis symbols by placing the dots (representing valence electrons) around the element symbols. (a) Aluminum (Al) - Group 13 element, so it has 3 valence electrons: • Al •• (b) Bromine (Br) - Group 17 element, so it has 7 valence electrons: ••• Br ••• • (c) Argon (Ar) - Group 18 element, so it has 8 valence electrons: • • •Ar• • • (d) Strontium (Sr) - Group 2 element, so it has 2 valence electrons: • Sr• Here, we have drawn the Lewis symbols for each of the given elements with the valence electrons represented as dots surrounding the element symbol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Valence Electrons
Valence electrons are the electrons that reside in the outermost shell of an atom. These electrons are incredibly significant because they are involved in chemical bonding and reactions. In essence, the chemical properties of an element are largely determined by its valence electrons.

When drawing Lewis symbols, which are simple representations of an atom's valence electrons, we depict these electrons as dots surrounding the element's symbol. For example, aluminum (Al), with three valence electrons, would have its Lewis symbol shown as 'Al' with three dots around it. This visual aid is a powerful tool for quickly understanding how an atom might interact with other atoms.

It's crucial for students to grasp that the number of valence electrons can typically be inferred from an element's group number in the periodic table, making it easier to draw the correct Lewis symbol for a given element.
Periodic Table Groups
The periodic table is organized in such a way that elements with similar properties are aligned in columns called 'groups'. There are 18 groups in the periodic table, and the group number (for groups 1-18) can reveal a lot about an element's atomic structure, particularly its valence electrons.

For instance, elements in Group 1 have one valence electron, whereas those in Group 17 have seven. This pattern is crucial for predicting how elements will interact chemically. A profound understanding of this can help students draw logical connections between the position of an element in the periodic table and its chemical behavior.

Remember, transition metals (found in groups 3-12) are an exception as their valence electrons can be found in more than one shell, making their chemical properties a bit more complex to predict based solely on group number.
Atomic Structure
Understanding an element's atomic structure is essential for interpreting its chemical behavior. An atom consists of a nucleus containing protons and neutrons, surrounded by electrons in various shells or energy levels. The electrons in the furthest shell from the nucleus are what we call the valence electrons.

Knowing which shell these valence electrons occupy can help us comprehend how elements form bonds. Elements strive to achieve a stable electronic configuration, and this pursuit drives chemical reactions. For example, a noble gas like argon (Ar) has a complete outer shell, making it largely unreactive, while aluminum (Al), with only three valence electrons, is more reactive and willing to form compounds.

It's these intricacies of atomic structure that necessitate a deeper exploration beyond just memorizing facts, as it can unveil the reasoning behind the element's chemical nature.
Chemical Properties
Chemical properties describe how an element behaves during a chemical reaction, including tendencies to participate in certain chemical bonds and transformations. The key to understanding these properties lies within the valence electrons and the atomic structure of the element.

For instance, bromine (Br) tends to accept an electron due to its seven valence electrons, to achieve a stable octet structure, thus acting as a good oxidizing agent. On the other hand, strontium (Sr), with only two valence electrons, is more likely to lose them to achieve a stable electronic arrangement.

By studying an element's position in the periodic table, along with its group number, students can predict its chemical properties such as reactivity, acidity, and types of compounds it can form. Facilitating an understanding of these connections reinforces the practical implications of atomic theory in real-world chemistry.

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Most popular questions from this chapter

A carbene is a compound that has a carbon bonded to two atoms and a lone pair remaining on the carbon. Many carbenes are very reactive. (a) Draw the Lewis structure for the simplest carbene, \(\mathrm{H}_{2} \mathrm{C}\) . ( b) Predict the length of the carbon-carbon bond you would expect if two \(\mathrm{H}_{2} \mathrm{C}\) molecules reacted with each other by a combination reaction.

The substance chlorine monoxide, ClO(g), is important in atmospheric processes that lead to depletion of the ozone layer. The ClO molecule has an experimental dipole moment of \(1.24 \mathrm{D},\) and the \(\mathrm{Cl}-\) O bond length is 1.60 \(\mathrm{A}\) . (a) Determine the magnitude of the charges on the Cl and O atoms in units of the electronic charge, \(e\) (b) Based on the electronegativities of the elements, which atom would you expect to have a partial negative charge in the Clo molecule? (c) Using formal charges as a guide, propose the dominant Lewis structure for the molecule. (d) The anion \(\mathrm{ClO}^{-}\) exists. What is the formal charge on the Cl for the best Lewis structure for \(\mathrm{ClO}^{-}\) ?

Using only the periodic table as your guide, select the most electronegative atom in each of the following sets: (a) Na, \(\mathrm{Mg}, \mathrm{K}, \mathrm{Ca} ;(\mathbf{b}) \mathrm{P}, \mathrm{S},\) As, \(\mathrm{Se} ;(\mathbf{c}) \mathrm{Be}, \mathrm{B}, \mathrm{C}, \mathrm{Si} ;(\mathbf{d}) \mathrm{Zn}, \mathrm{Ge}, \mathrm{Ga}, \mathrm{Gs}\)

An ionic substance of formula MX has a lattice energy of \(6 \times 10^{3} \mathrm{k} / \mathrm{mol} .\) Is the charge on the ion M likely to be \(1+, 2+,\) or \(3+?\) Explain.

Write electron configurations for the following ions, and determine which have noble-gas configurations: (a) \(\mathrm{Cd}^{2+}\) , \((\mathbf{b}) \mathrm{P}^{3-},(\mathbf{c}) \mathrm{Zr}^{4+},(\mathbf{d}) \mathrm{Ru}^{3+},(\mathbf{e}) \mathrm{As}^{3-},(\mathbf{f}) \mathrm{Ag}^{+}\)

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