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Predict whether each of the following oxides is ionic or molecular: \(\operatorname{Sn} \mathrm{O}_{2}, \mathrm{Al}_{2} \mathrm{O}_{3}, \mathrm{CO}_{2}, \mathrm{Li}_{2} \mathrm{O}, \mathrm{Fe}_{2} \mathrm{O}_{3}, \mathrm{H}_{2} \mathrm{O} .\)

Short Answer

Expert verified
Based on the analysis of each oxide, the predictions are as follows: - \( \operatorname{SnO}_{2} \): Ionic - \( \mathrm{Al}_{2} \mathrm{O}_{3} \): Ionic - \( \mathrm{CO}_{2} \): Molecular - \( \mathrm{Li}_{2} \mathrm{O} \): Ionic - \( \mathrm{Fe}_{2} \mathrm{O}_{3} \): Ionic - \( \mathrm{H}_{2} \mathrm{O} \): Molecular

Step by step solution

01

SnO2

Sn (Tin) is a metal and O (Oxygen) is a non-metal, we should expect this to be an ionic compound.
02

Al2O3

Al (Aluminum) is a metal and O (Oxygen) is a non-metal, we should expect this to be an ionic compound.
03

CO2

C (Carbon) and O (Oxygen) are both non-metals, we should expect this to be a molecular compound with covalent bonds.
04

Li2O

Li (Lithium) is a metal and O (Oxygen) is a non-metal, we should expect this to be an ionic compound.
05

Fe2O3

Fe (Iron) is a metal and O (Oxygen) is a non-metal, we should expect this to be an ionic compound.
06

H2O

H (Hydrogen) and O (Oxygen) are both non-metals, we should expect this to be a molecular compound with covalent bonds. In summary, according to the analysis, the following are the predictions for each oxide: - SnO2: Ionic - Al2O3: Ionic - CO2: Molecular - Li2O: Ionic - Fe2O3: Ionic - H2O: Molecular

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Bonding
Chemical bonding is the force that holds atoms together in compounds, and it comes in various types, primarily ionic and covalent bonds. In ionic bonding, atoms transfer electrons to achieve a full outer electron shell, leading to the formation of positively charged ions (cations) and negatively charged ions (anions). This electron transfer typically occurs between metallic and nonmetallic elements, such as in lithium oxide (Li_2O), where lithium (Li) donates electrons to oxygen (O). On the other hand, a covalent bond forms when two nonmetallic elements share electrons, as is the case with carbon dioxide (CO_2), where carbon and oxygen share electrons in a molecular compound.

Understanding the difference between these types of bonds is crucial for predicting the properties of a compound. For instance, ionic compounds typically have higher melting and boiling points and conduct electricity when dissolved in water or melted, while covalent compounds can be gases, liquids, or solids at room temperature, with lower melting points compared to ionic compounds and poor conductivity.
Metallic and Nonmetallic Elements
The distinction between metallic and nonmetallic elements is one of the most fundamental concepts in chemistry and plays a key role in the classification of compounds. Metals, found on the left side of the periodic table, readily lose electrons to form positive ions. Nonmetals, on the right side, tend to gain electrons to form negative ions.

In the exercise, we encounter a variety of elements: tin (Sn), aluminum (Al), lithium (Li), and iron (Fe) are classified as metals and tend to form cations, while carbon (C), hydrogen (H), and oxygen (O) are nonmetals and likely to form anions or share electrons in covalent bonds. Compounds made from metals and nonmetals like (Al_2O_3 and SnO_2) are typically ionic, whereas compounds composed entirely of nonmetals, such as water (H_2O) and carbon dioxide (CO_2), are molecular with covalent bonds.
Compound Classification
Classifying compounds as either ionic or molecular determines how we predict their behavior and properties. Ionic compounds are usually formed between metallic and nonmetallic elements where there is a transfer of electrons. This transfer leads to the formation of ions that are held together by the electrostatic attraction between oppositely charged particles. In our exercise, when predicting the nature of oxides like (Fe_2O_3 and Li_2O), the involvement of a metal indicates the compound is ionic.

Molecular compounds, however, result from the covalent bonding between nonmetallic elements and involve the sharing of electrons between atoms. These shared electrons result in the stable outer electron shells for each atom within the molecule. The oxides formed in this manner, such as CO_2 and H_2O, exhibit molecular characteristics.

Moreover, the classification of compounds guides us in understanding their physical states under normal conditions, reactivity, solubility, electrical conductivity, and other key properties that are essential for practical applications in daily life and various industries.

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Most popular questions from this chapter

Consider the isoelectronic ions \(\mathrm{Cl}^{-}\) and \(\mathrm{K}^{+}\) . (a) Which ion is smaller? (b) Using Equation 7.1 and assuming that core electrons contribute 1.00 and valence electrons contribute nothing to the screening constant, \(S\) , calculate \(Z_{\text { eff}}\) for these two ions. (c) Repeat this calculation using Slater's rules to estimate the screening constant, \(S.\) (d) For isoelectronic ions, how are effective nuclear charge and ionic radius related?

In the chemical process called electron transfer, an electron is transferred from one atom or molecule to another. (We will talk about electron transfer extensively in Chapter 20.) A simple electron transfer reaction is $$\mathrm{A}(g)+\mathrm{A}(g) \longrightarrow \mathrm{A}^{+}(g)+\mathrm{A}^{-}(g)$$ In terms of the ionization energy and electron afnity of atom A, what is the energy change for this reaction? For a representative nonmetal such as chlorine, is this process exothermic? For a representative metal such as sodium, is this process exothermic?

Write a balanced equation for the reaction that occurs in each of the following cases: (a) Chlorine reacts with water. (b) Barium metal is heated in an atmosphere of hydrogen gas. (c) Lithium reacts with sulfur. (d) Fluorine reacts with magnesium metal.

Write equations that show the processes that describe the first, second, and third ionization energies of an aluminum atom. Which process would require the least amount of energy?

Detailed calculations show that the value of \(Z_{\text { eff }}\) for the outermost electrons in Na and \(K\) atoms is \(2.51+\) and \(3.49+\) respectively. (a) What value do you estimate for \(Z_{\text { eff }}\) experienced by the outermost electron in both Na and K by assuming core electrons contribute 1.00 and valence electrons contribute 0.00 to the screening constant? (b) What values do you estimate for \(Z_{\text { eff }}\) using Slater's rules? (c) Which approach gives a more accurate estimate of \(Z_{\text { eff? }}\) (d) Does either method of approximation account for the gradual increase in \(Z_{\text { eff }}\) that occurs upon moving down a group? (e) Predict \(Z_{\text { eff }}\) for the outermost electrons in the Rb atom based on the calculations for Na and K.

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