/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 (a) What is the general relation... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) What is the general relationship between the size of an atom and its first ionization energy? (b) Which element in the periodic table has the largest ionization energy? Which has the smallest?

Short Answer

Expert verified
(a) The general relationship between the size of an atom and its first ionization energy is inversely proportional: as the size of an atom increases, its ionization energy decreases. (b) Helium (He) has the largest ionization energy, while Francium (Fr) has the smallest ionization energy in the periodic table.

Step by step solution

01

Understanding Ionization Energy

Ionization energy is the energy required to remove an electron from an atom or ion. It can be classified into two categories: first ionization energy and successive ionization energy. The first ionization energy is the energy required to remove the first electron from the valence shell, while successive ionization energies correspond to the removal of subsequent electrons.
02

Relation between Atom Size and Ionization Energy

Ionization energy and atomic size are inversely proportional. As the size of an atom increases, the ionization energy decreases. This is because, in larger atoms, the valence electrons are further from the nucleus and experience weaker nuclear attraction. As a result, it becomes easier to remove electrons in larger atoms, reducing their ionization energy.
03

Variation of Ionization Energy Across the Periodic Table

Ionization energy generally increases across a period (from left to right) and decreases down a group (from top to bottom) in the periodic table. The explanation behind this behavior is that as we move across a period, the nuclear charge (number of protons) increases, so electrons are more strongly attracted to the nucleus. In contrast, electrons in a larger atom experience weaker nuclear forces and can be removed with less energy.
04

Identifying Elements with the Largest and Smallest Ionization Energies

(a) The general relationship between the size of an atom and its first ionization energy is that they are inversely proportional: Larger atoms have lower ionization energies, and smaller atoms have higher ionization energies. (b) To find the element with the largest ionization energy, we can look for the element with the smallest atomic size in the periodic table. Helium (He), being in the top right corner of the periodic table, has the smallest atomic size and the largest first ionization energy. For the element with the smallest ionization energy, we can look for the element with the largest atomic size. Francium (Fr), being in the bottom left corner of the periodic table, has the largest atomic size and the smallest first ionization energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Arrange the following atoms in order of increasing effective nuclear charge experienced by the electrons in the \(n=3\) electron shell: \(\mathrm{K}, \mathrm{Mg}, \mathrm{P}, \mathrm{Rh} , \mathrm{Ti}.\)

Little is known about the properties of astatine, At, because of its rarity and high radioactivity. Nevertheless, it is possible for us to make many predictions about its properties. (a) Do you expect the element to be a gas, liquid, or solid at room temperature? Explain. (b) Would you expect At to be a metal, nonmetal, or metalloid? Explain. (c) What is the chemical formula of the compound it forms with Na?

Which of the following statements about effective nuclear charge for the outermost valence electron of an atom is incorrect? (i) The effective nuclear charge can be thought of as the true nuclear charge minus a screening constant due to the other electrons in the atom. (ii) Effective nuclear charge increases going left to right across a row of the periodic table. (iii) Valence electrons screen the nuclear charge more effectively than do core electrons. (iv) The effective nuclear charge shows a sudden decrease when we go from the end of one row to the beginning of the next row of the periodic table. (v) The change in effective nuclear charge going down a column of the periodic table is generally less than that going across a row of the periodic table.

Discussing this chapter, a classmate says, "An element that commonly forms a cation is a metal." Do you agree or disagree?

Mercury in the environment can exist in oxidation states 0, +1, and +2. One major question in environmental chemistry research is how to best measure the oxidation state of mercury in natural systems; this is made more complicated by the fact that mercury can be reduced or oxidized on surfaces differently than it would be if it were free in solution. XPS, X-ray photoelectron spectroscopy, is a technique related to PES (see Exercise 7.111), but instead of using ultraviolet light to eject valence electrons, X rays are used to eject core electrons. The energies of the core electrons are different for different oxidation states of the element. In one set of experiments, researchers examined mercury contamination of minerals in water. They measured the XPS signals that corresponded to electrons ejected from mercury’s 4\(f\) orbitals at 105 eV, from an X-ray source that provided 1253.6 \(\mathrm{eV}\) of energy \(\left(1 \mathrm{ev}=1.602 \times 10^{-19} \mathrm{J}\right)\) The oxygen on the mineral surface gave emitted electron energies at \(531 \mathrm{eV},\) corresponding to the 1 \(\mathrm{s}\) orbital of oxygen. Overall the researchers concluded that oxidation states were \(+2\) for \(\mathrm{Hg}\) and \(-2\) for \(\mathrm{O}\) (a) Calculate the wavelength of the X rays used in this experiment. (b) Compare the energies of the 4f electrons in mercury and the 1s electrons in oxygen from these data to the first ionization energies of mercury and oxygen from the data in this chapter. (c) Write out the ground- state electron configurations for \(\mathrm{Hg}^{2+}\) and \(\mathrm{O}^{2-} ;\) which electrons are the valence electrons in each case?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.