91Ó°ÊÓ

We can use Hess's law to calculate enthalpy changes that cannot be measured. One such reaction is the conversion of methane to ethylene: $$2 \mathrm{CH}_{4}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g)$$ Calculate the \(\Delta H^{\circ}\) for this reaction using the following thermochemical data: $$\begin{array}{ll}{\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)} & {\Delta H^{\circ}=-890.3 \mathrm{kJ}} \\ {\mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6}(g)} & {\Delta H^{\circ}=-136.3 \mathrm{kJ}} \\ {2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(l)} & {\Delta H^{\circ}=-571.6 \mathrm{kJ}} \\ {2 \mathrm{C}_{2} \mathrm{H}_{6}(g)+7 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(l)} & {\Delta H^{\circ}=-3120.8 \mathrm{kJ}}\end{array}$$

Step by step solution

01

Analyze the given reactions

We have the following reactions and their enthalpy changes: 1. \(CH_4(g) + 2 O_2(g) \longrightarrow CO_2(g) + 2 H_2O(l)\), \(\Delta H_1^\circ = -890.3 kJ\) 2. \(C_2H_4(g) + H_2(g) \longrightarrow C_2H_6(g)\), \(\Delta H_2^\circ = -136.3 kJ\) 3. \(2 H_2(g) + O_2(g) \longrightarrow 2 H_2O(l)\), \(\Delta H_3^\circ = -571.6 kJ\) 4. \(2 C_2H_6(g) + 7 O_2(g) \longrightarrow 4 CO_2(g) + 6 H_2O(l)\), \(\Delta H_4^\circ = -3120.8 kJ\)

02

Manipulate reactions to form the target reaction

We want to form the reaction: \[2 CH_4(g) \longrightarrow C_2H_4(g) + H_2(g) \] Manipulate the given reactions as follows: - Multiply reaction 1 by 2: \[2 CH_4(g) + 4 O_2(g) \longrightarrow 2 CO_2(g) + 4 H_2O(l), \Delta H_{1'}^\circ = -1780.6 kJ\] - Reverse reaction 2: \[C_2H_6(g) \longrightarrow C_2H_4(g) + H_2(g), \Delta H_{2'}^\circ = 136.3 kJ\] - Multiply reaction 3 by 1/2 and reverse it: \[H_2O(l) \longrightarrow H_2(g) + 1/2 O_2(g), \Delta H_{3'}^\circ = 285.8 kJ\] - Use reaction 4 as it is: \[2 C_2H_6(g) + 7 O_2(g) \longrightarrow 4 CO_2(g) + 6 H_2O(l), \Delta H_4^\circ = -3120.8 kJ\]

03

Add the manipulated reactions to obtain the target reaction

Now, add the manipulated reactions together: 1. \(2 CH_4(g) + 4 O_2(g) \longrightarrow 2 CO_2(g) + 4 H_2O(l)\) 2. \(C_2H_6(g) \longrightarrow C_2H_4(g) + H_2(g) \) 3. \(H_2O(l) \longrightarrow H_2(g) + 1/2 O_2(g) \) 4. \(2 C_2H_6(g) + 7 O_2(g) \longrightarrow 4 CO_2(g) + 6 H_2O(l)\) Sum: \(2 CH_4(g) + 4 CO_2(g) + 4 H_2O(l) \longrightarrow C_2H_4(g) + H_2(g) + 2 CO_2(g) + 6 H_2O(l) + 4 CO_2(g) \) Simplify: \(2 CH_4(g) \longrightarrow C_2H_4(g) + H_2(g)\)

04

Calculate the enthalpy change for the target reaction

Now, sum the \(\Delta H^\circ\) values of the manipulated reactions: \[\Delta H = \Delta H_{1'}^\circ + \Delta H_{2'}^\circ + \Delta H_{3'}^\circ + \Delta H_{4}^\circ\] \[\Delta H = (-1780.6 kJ) + (136.3 kJ) + (285.8 kJ) + (-3120.8 kJ)\] \[\Delta H = -3479.3 kJ\] So, the enthalpy change for the reaction \(2 CH_4(g) \longrightarrow C_2H_4(g) + H_2(g)\) is \(\Delta H^\circ = -3479.3 kJ\).

Unlock Step-by-Step Solutions & Ace Your Exams!

• Full Textbook Solutions

  Get detailed explanations and key concepts

• Unlimited Al creation

  Al flashcards, explanations, exams and more...

• Ads-free access

  To over 500 millions flashcards

• Money-back guarantee

  We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy Change

Enthalpy change is an essential concept in chemistry that helps measure the heat absorbed or released during a chemical reaction. It is symbolized as \(\Delta H\). When a reaction occurs at constant pressure, the change in enthalpy represents the heat exchange with the surroundings.Several factors can influence the enthalpy change of a reaction:

• The nature of reactants and products
• The conditions under which the reaction occurs, such as pressure and temperature
• The states of the substances involved (solid, liquid, gas)

The enthalpy change of a reaction can be either positive or negative:

• A positive \(\Delta H\) indicates an endothermic reaction where heat is absorbed.
• A negative \(\Delta H\) indicates an exothermic reaction where heat is released.

Understanding the enthalpy change helps in predicting whether a reaction requires energy input or releases energy, which is crucial for various industrial and laboratory processes.

Reaction Manipulation

Reaction manipulation involves adjusting chemical equations to help calculate unknown enthalpy changes using known data. According to Hess's Law, the total enthalpy change for a reaction is the sum of the enthalpy changes for each step in the reaction pathway.Here are some common manipulation strategies:

• Reversing reactions: Changing the direction of a reaction will change the sign of \(\Delta H\). For example, if a reaction is exothermic with \(\Delta H = -100 \, \text{kJ}\), the reverse reaction will be endothermic with \(\Delta H = +100 \, \text{kJ}\).
• Multiplying reactions: If a reaction is multiplied by a coefficient, \(\Delta H\) is also multiplied by the same factor.
• Adding reactions: Reactions can be added together, and their enthalpy changes are summed to find the overall \(\Delta H\).

By strategically manipulating known reactions, you can derive the enthalpy change of a target reaction that might be otherwise difficult to measure directly.

Thermochemical Equations

Thermochemical equations are balanced chemical equations that include the enthalpy change. They are a powerful way to represent the energy changes associated with chemical reactions, providing insight into whether energy is absorbed or released.Key features of thermochemical equations:

• The balanced chemical equation shows the stoichiometry of the reactants and products.
• The enthalpy change \(\Delta H\) is included, usually in kilojoules (\(\text{kJ}\)), and gives a thermodynamic perspective of the reaction.
• States of matter (solid, liquid, gas) for each component are often specified, which is important as enthalpy changes can depend on these states.

When writing or interpreting thermochemical equations, it is crucial to remember:

• Ensure the equation is balanced for both mass and charge.
• The specified \(\Delta H\) is accurate under the given conditions.
• Consider how changes in conditions (such as temperature or pressure) might affect the \(\Delta H\).

Thermochemical equations are a foundational tool in thermodynamics, helping chemists and engineers predict reaction behaviors and design energy-efficient processes.