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Hydrogen peroxide is capable of oxidizing (a) hydrazine to \(\mathrm{N}_{2}\) and \(\mathrm{H}_{2} \mathrm{O},(\mathbf{b}) \mathrm{SO}_{2}\) to \(\mathrm{SO}_{4}^{2-},(\mathbf{c}) \mathrm{NO}_{2}^{-}\) to \(\mathrm{NO}_{3}^{-},(\mathbf{d}) \mathrm{H}_{2} \mathrm{S}(g)\) \(\mathrm{to} S(s),(\mathbf{e}) \mathrm{Fe}^{2+}\) to \(\mathrm{Fe}^{3+} .\) Write a balanced net ionic equation for each of these redox reactions.

Short Answer

Expert verified
Here's a summary of the balanced net ionic equations for each reaction: a) \(2 \mathrm{H}_{2} \mathrm{O}_{2} + \mathrm{N}_{2} \mathrm{H}_{4} \rightarrow \mathrm{N}_{2} + 4 \mathrm{H}_{2} \mathrm{O}\) b) \(2 \mathrm{H}_{2} \mathrm{O}_{2} + 2 \mathrm{SO}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} + \mathrm{SO}_{4}^{2-}\) c) \(\mathrm{H}_{2} \mathrm{O}_{2} + \mathrm{NO}_{2}^{-} \rightarrow \mathrm{NO}_{3}^{-} + \mathrm{H}_{2} \mathrm{O}\) d) \(2 \mathrm{H}_{2} \mathrm{O}_{2} + 2 \mathrm{H}_{2} \mathrm{S} \rightarrow 4 \mathrm{H}_{2} \mathrm{O} + 2 \mathrm{S}\) e) \(\mathrm{H}_{2} \mathrm{O}_{2} + \mathrm{Fe}^{2+} \rightarrow \mathrm{Fe}^{3+} + 2 \mathrm{H}_{2} \mathrm{O}\)

Step by step solution

01

a) H2O2 + H2O2 → N2 + H2O + H2O

Step 1: Determine the oxidation states - H2O2: H is +1, O is -1. - N2H4: N is -2, H is +1. - N2: N is 0. - H2O: H is +1, O is -2. Step 2: Identify oxidation and reduction - Hydrazine (N2H4) is oxidized (from -2 to 0). - Hydrogen peroxide (H2O2) is reduced (from -1 to -2). Step 3: Balance atoms and charge In order to balance the redox reaction, we need to balance the atoms and charge: \(2 \mathrm{H}_{2} \mathrm{O}_{2} + \mathrm{N}_{2} \mathrm{H}_{4} \rightarrow \mathrm{N}_{2} + 4 \mathrm{H}_{2} \mathrm{O} \)
02

b) H2O2 + 2SO2 → H2O + H2O + SO42-

Step 1: Determine the oxidation states - H2O2: H is +1, O is -1. - SO2: S is +4, O is -2. - SO42-: S is +6, O is -2. - H2O: H is +1, O is -2. Step 2: Identify oxidation and reduction - SO2 is oxidized (from +4 to +6). - H2O2 is reduced (from -1 to -2). Step 3: Balance atoms and charge - \(2 \mathrm{H}_{2} \mathrm{O}_{2} + 2 \mathrm{SO}_{2} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} + \mathrm{SO}_{4}^{2-} \)
03

c) H2O2 + NO2- → NO3- + H2O

Step 1: Determine the oxidation states - H2O2: H is +1, O is -1. - NO2-: N is +3, O is -2. - NO3-: N is +5, O is -2. - H2O: H is +1, O is -2. Step 2: Identify oxidation and reduction - NO2- is oxidized (from +3 to +5). - H2O2 is reduced (from -1 to -2). Step 3: Balance atoms and charge - \(\mathrm{H}_{2} \mathrm{O}_{2} + \mathrm{NO}_{2}^{-} \rightarrow \mathrm{NO}_{3}^{-} + \mathrm{H}_{2} \mathrm{O} \)
04

d) H2O2 + H2S -> H2O + H2O + S

Step 1: Determine the oxidation states - H2O2: H is +1, O is -1. - H2S: H is +1, S is -2. - H2O: H is +1, O is -2. - S: S is 0. Step 2: Identify oxidation and reduction - H2S is oxidized (from -2 to 0). - H2O2 is reduced (from -1 to -2). d) Step 3: Balance atoms and charge - \(2 \mathrm{H}_{2} \mathrm{O}_{2} + 2 \mathrm{H}_{2} \mathrm{S} \rightarrow 4 \mathrm{H}_{2} \mathrm{O} + 2 \mathrm{S} \)
05

e) H2O2 + Fe2+ → Fe3+ + H2O + H2O

Step 1: Determine the oxidation states - H2O2: H is +1, O is -1. - Fe2+: Fe is +2. - Fe3+: Fe is +3. - H2O: H is +1, O is -2. Step 2: Identify oxidation and reduction - Fe2+ is oxidized (from +2 to +3). - H2O2 is reduced (from -1 to -2). Step 3: Balance atoms and charge - \(\mathrm{H}_{2} \mathrm{O}_{2} + \mathrm{Fe}^{2+} \rightarrow \mathrm{Fe}^{3+} + 2 \mathrm{H}_{2} \mathrm{O} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balancing Redox Equations
Balancing redox equations is an essential skill in chemistry that ensures both the number of atoms and the charge are equal on both sides of a reaction. This is done by following three main steps: identifying oxidation states, recognizing which species are oxidized and reduced, and finally, balancing the equation by adding coefficients.

For example, in the oxidation of hydrazine to nitrogen gas using hydrogen peroxide, we start by determining the oxidation states. Hydrazine has nitrogen in the -2 state, which goes to 0 in nitrogen gas, indicating oxidation. Hydrogen peroxide, on the other hand, goes from having oxygen in the -1 state to -2 in water, indicating reduction.

Once we've identified these changes, we balance the atoms that have changed oxidation state, followed by ensuring that the overall charge is the same on both sides. Any imbalance is corrected by adding appropriate coefficients before the compounds in the equation. This balanced approach not only conserves mass but also charge, adhering to the foundational laws of chemistry.
Oxidation States
Understanding oxidation states is key to working with redox reactions. An oxidation state is a number assigned to an element in a chemical compound that represents the number of electrons lost or gained by an atom of that element in the compound. The rules for determining oxidation states include: elements in their elemental form have an oxidation state of 0, oxygen typically has an oxidation state of -2 (except in peroxides where it's -1 or when bonded to fluorine), and hydrogen is usually +1 (except when bonded to metals where it's -1).

Using hydrogen peroxide as an example, the oxygen has an unusual oxidation state of -1 because it's a peroxide. In the oxidation of sulfur dioxide to sulfate, the oxidation state of sulfur increases from +4 to +6, reflecting its loss of electrons and subsequent oxidation. These oxidation numbers are like the 'accounting system' of electrons in chemical reactions, providing invaluable insight into the transfer of electrons that occurs in redox processes.
Chemical Oxidizing Agents
In redox reactions, a chemical oxidizing agent is responsible for accepting electrons from another species, causing the other species to oxidize. The oxidizing agent itself gets reduced in the process. Hydrogen peroxide is a powerful oxidizing agent, which can take part in various redox reactions, as seen in the textbook examples.

In the case of the conversion of hydrazine to nitrogen, hydrogen peroxide receives electrons from hydrazine, allowing for the breakdown of the N-N bond to form nitrogen gas. The ability of an oxidizing agent to accept electrons is a key characteristic that determines its strength and usefulness in chemical reactions. A robust oxidizing agent like hydrogen peroxide is versatile and can be used to drive many different types of redox reactions, evidenced by its ability to oxidize a wide range of substances from sulfur dioxide to iron ions.

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Most popular questions from this chapter

One method proposed for removing SO \(_{2}\) from the flue gases of power plants involves reaction with aqueous \(\mathrm{H}_{2} \mathrm{S}\) . Elemental sulfur is the product. (a) Write a balanced chemical equation for the reaction. (b) What volume of \(\mathrm{H}_{2} \mathrm{S}\) at \(27^{\circ} \mathrm{C}\) and 760 torr would be required to remove the \(\mathrm{SO}_{2}\) formed by burning 2.0 tons of coal containing 3.5\(\% \mathrm{S}\) by mass? (\mathbf{c} ) What mass o f elemental sulfur is produced? Assume that all reactions are 100\(\%\) efficient.

Write the chemical formula for each of the following compounds, and indicate the oxidation state of nitrogen in each: (a) nitric oxide, (b) hydrazine, (c) potassium cyanide, (d) sodium nitrite, (e) ammonium chloride, (f) lithium nitride.

A sulfuric acid plant produces a considerable amount of heat. This heat is used to generate electricity, which helps reduce operating costs. The synthesis of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) consists of three main chemical processes: (a) oxidation of S to SO, (b) oxidation of \(\mathrm{SO}_{2}\) to \(\mathrm{SO}_{3},\) (c) the dissolving of \(\mathrm{SO}_{3}\) in \(\mathrm{H}_{2} \mathrm{SO}_{4}\) and the subsequent reaction with water to form \(\mathrm{H}_{2} \mathrm{SO}_{4}\) . If the third process produces \(130 \mathrm{kJ} / \mathrm{mol},\) how much heat is produced in preparing a mole of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) from a mole of S? How much heat is produced in preparing 5000 pounds of \(\mathrm{H}_{2} \mathrm{SO}_{4} ?\)

Indicate whether each of the following statements is true or false (a) \(\mathrm{H}_{2}(g)\) and \(\mathrm{D}_{2}(g)\) are allotropic forms of hydrogen. (b) \(\mathrm{ClF}_{3}\) is an interhalogen compound. (c) MgO(s) is an acidic anhydride. (d) \(\mathrm{SO}_{2}(g)\) is an acidic anhydride. (e) \(2 \mathrm{H}_{3} \mathrm{PO}_{4}(l) \rightarrow \mathrm{H}_{4} \mathrm{P}_{2} \mathrm{O}_{7}(l)+\mathrm{H}_{2} \mathrm{O}(g)\) is an example of a condensation reaction. (f) Tritium is an isotope of the element hydrogen. (g) \(2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{SO}_{3}(g)\) is an example of a disproportionation reaction.

Write a balanced equation for each of the following reactions: (a) Burning magnesium metal in a carbon dioxide atmosphere reduces the \(\mathrm{CO}_{2}\) to carbon. (b) In photosynthesis, solar energy is used to produce glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\) and \(\mathrm{O}_{2}\) from carbon dioxide and water. (c) When carbonate salts dissolve in water, they produce basic solutions.

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