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The complexes \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) and \(\left[\mathrm{VF}_{6}\right]^{3-}\) are both known. (a) Draw the \(d\)-orbital energy-level diagram for V(III) octahedral complexes. (b) What gives rise to the colors of these complexes? (c) Which of the two complexes would you expect to absorb light of higher energy?

Short Answer

Expert verified
The d-orbital energy-level diagram for V(III) octahedral complexes shows 2 electrons in the lower energy \(t_{2g}\) orbitals and empty \(e_g\) orbitals. The colors of these complexes arise from the electron transitions between \(t_{2g}\) and \(e_g\) orbitals. The \(\mathrm{[VF_6]^3-}\) complex absorbs higher energy light, as F鈦 is a stronger ligand, causing a greater energy splitting between the d-orbitals than in the \(\mathrm{[V(H_2O)_6]^3+}\) complex.

Step by step solution

01

a. Drawing d-orbital energy-level diagram for V(III) octahedral complexes.

To draw the d-orbital energy-level diagram, we need to consider the position of Vanadium (V) in the periodic table. The electronic configuration of Vanadium is \([Ar]4s^23d^3\), which means V(III) has an electronic configuration of \([Ar]3d^2\). In an octahedral complex, the d-orbitals are split into two groups: \(t_{2g}\) (lower in energy) and \(e_g\) (higher in energy). So, for the V(III) ion, we will fill \(t_{2g}\) orbitals with 2 electrons in accordance with Hund's rule, leaving \(e_g\) orbitals empty. Now, we can draw the d-orbital energy-level diagram like this: e_g ___|___ | | | | ---------|--------- t_2g ___|___ | | | 鈫 鈫
02

b. Source of the colors of the complexes.

The colors of the complexes are due to the transition of electrons between d-orbitals. In the case of these octahedral complexes, the transition mainly occurs between the \(t_{2g}\) and \(e_g\) orbitals. When an electron is excited from a lower energy level (\(t_{2g}\)) to a higher energy level (\(e_g\)), they absorb a certain amount of energy, which corresponds to a specific wavelength, or color, of light. The complementary color of the absorbed light will be the observed color of the complex.
03

c. Identifying the complex that absorbs higher energy light and explaining the reason.

To determine which of the \(\mathrm{[V(H_2O)_6]^3+}\) and \(\mathrm{[VF_6]^3-}\) complexes absorb higher energy light, we need to look at the ligand field strengths. In general, the wavelength of absorbing light is inversely related to the energy difference between \(t_{2g}\) and \(e_g\) orbitals. In our case, F炉 is a stronger ligand than H鈧侽, meaning it creates a larger splitting of the d-orbitals, placing \(t_{2g}\) orbitals at lower energy and \(e_g\) orbitals at higher energy. Thus, in the \(\mathrm{[VF_6]^3-}\) complex, the energy difference between these orbitals is greater compared to the \(\mathrm{[V(H_2O)_6]^3+}\) complex. Consequently, the \(\mathrm{[VF_6]^3-}\) complex would absorb light of higher energy because of the larger energy gap between its d-orbitals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

D-Orbital Energy-Level Diagrams
D-orbital energy-level diagrams are visual representations used to show the distribution of electrons among the five d orbitals in transition metal ions. In an octahedral complex, the presence of six ligands symmetrically arranged around the central metal ion creates an electrostatic field that influences the energies of the d orbitals. The d orbitals split into two distinct energy levels: the lower-energy \(t_{2g}\) set and the higher-energy \(e_g\) set.

The \(t_{2g}\) orbitals consist of the dxy, dxz, and dyz orbitals, while the \(e_g\) orbitals are made up of the dx2-y2 and dz2 orbitals. Hund's rules govern how electrons occupy these orbitals: electrons fill the lower-energy \(t_{2g}\) orbitals first and are distributed to minimize electron-electron repulsions, leading to the maximum number of unpaired electrons. For example, Vanadium (III), which has three electrons in its d orbitals, would fill the \(t_{2g}\) orbitals with two electrons, one in each of two of the orbitals, in accordance with Hund's rule.

The diagram thus serves a dual purpose: it simplifies our understanding of the electron configurations in transition metal ions and assists in predicting magnetic properties and possible electronic transitions that give rise to colors in coordination compounds.
Ligand Field Theory
Ligand Field Theory (LFT) is an extension of crystal field theory that considers the covalent, as well as the ionic aspects of coordination. According to LFT, ligands are treated as point charges in the case of weak-field ligands, or as overlapping orbitals in the case of strong-field ligands, influencing their interaction with the metal d orbitals. The strength of the ligand, therefore, has a marked effect on the extent of the splitting of the d orbitals.

When we consider an octahedral complex, the ligands approach along the axes, directly interacting with the \(e_g\) orbitals, which are oriented along the x, y, and z axes. The \(t_{2g}\) orbitals, having a lobed structure positioned between these axes, are less affected. Strong-field ligands, such as F鈦 in the \(\mathrm{[VF_6]^{3-}}\) complex, exert a greater splitting effect than weak-field ligands like H2O in the \(\mathrm{[V(H_2O)_6]^{3+}}\) complex. This difference in splitting can dictate the color of the complex, its magnetic properties, and the absorbance of light at certain energies, making it a crucial concept in inorganic chemistry.
Electronic Transitions in Coordination Compounds
The vibrant colors exhibited by coordination compounds, such as \(\mathrm{[V(H_2O)_6]^{3+}}\) and \(\mathrm{[VF_6]^{3-}}\), are a result of electronic transitions within the d orbitals induced by light energy. When a complex absorbs light, it gains energy that allows electrons to transition from a lower-energy state (typically the \(t_{2g}\) orbitals) to a higher-energy state (the \(e_g\) orbitals). This jump in energy levels falls within the visible spectrum and corresponds to a specific color. The energy gap between \(t_{2g}\) and \(e_g\) dictates the wavelength of light absorbed, which follows the equation \(\Delta E = hu\), where \(\Delta E\) is the difference in energy between the two orbitals, \(h\) is Planck's constant, and \(u\) is the frequency of light.

As ligands like F鈦 produce a larger gap between the \(t_{2g}\) and \(e_g\) orbitals compared to H2O, the \(\mathrm{[VF_6]^{3-}}\) complex absorbs light of higher energy (shorter wavelength) and thus displays a color corresponding to the complementary color of the absorbed light. Understanding electronic transitions is crucial for explaining the color and spectral properties of coordination compounds and is fundamental to fields such as spectroscopy and photochemistry.

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Most popular questions from this chapter

Which of the complexes shown here are chiral? [Section 23.4] $$ \mathrm{Cr} \quad \mathrm{Cr}=\mathrm{NH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2} \quad \Theta=\mathrm{Cl} \quad \theta=\mathrm{NH}_{3} $$ (1) ( (3) (4)

Which of the following objects is chiral: (a) a left shoe, (b) a slice of bread, (c) a wood screw, (d) a molecular model of \(\mathrm{Zn}(\mathrm{en}) \mathrm{Cl}_{2}\), (e) a typical golf club?

In crystal-field theory, ligands are modeled as if they are point negative charges. What is the basis of this assumption, and how does it relate to the nature of metal-ligand bonds?

Oxyhemoglobin, with an \(\mathrm{O}_{2}\) bound to iron, is a low-spin \(\mathrm{Fe}\) (II) complex; deoxyhemoglobin, without the \(\mathrm{O}_{2}\) molecule, is a high-spin complex. (a) Assuming that the coordination environment about the metal is octahedral, how many unpaired electrons are centered on the metal ion in each case? (b) What ligand is coordinated to the iron in place of \(\mathrm{O}_{2}\) in deoxyhemoglobin? (c) Explain in a general way why the two forms of hemoglobin have different colors (hemoglobin is red, whereas deoxyhemoglobin has a bluish cast). (d) A 15 -minute exposure to air containing \(400 \mathrm{ppm}\) of CO causes about \(10 \%\) of the hemoglobin in the blood to be converted into the carbon monoxide complex, called carboxyhemoglobin. What does this suggest about the relative equilibrium constants for binding of carbon monoxide and \(\mathrm{O}_{2}\) to hemoglobin? (e) \(\mathrm{CO}\) is a strong-field ligand. What color might you expect carboxyhemoglobin to be?

(c) When the coordinated water to the \(\mathrm{Zn}(\mathrm{II})\) center in carbonic anhydrase is deprotonated, what ligands are bound to the Zn(II) center? Assume the three nitrogen ligands are unaffected. (d) The \(\mathrm{F} K_{a}\) of \(\left[\mathrm{Zn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{d}\right]^{2+}\) is 10 . Suggest an explanation for the difference between this \(\mathrm{pK} \mathrm{K}_{\text {and }}\) that of carbonic anhydrase. (e) Would you expect carbonic anhydrase to have a decp color, like hemoglobin and other metalion containing proteins do? Explain. Two different compounds have the formulation \(\mathrm{CoBr}\left(\mathrm{SO}_{4}\right) \cdot 5 \mathrm{NH}_{3}\). Compound \(\mathrm{A}\) is dark violet, and compound B is red-violet. When compound \(A\) is treated with \(\mathrm{AgNO}_{3}(\mathrm{Gq})\), no reaction occurs, whereas compound \(\mathrm{B}\)

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