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During the discharge of an alkaline battery, \(4.50 \mathrm{~g}\) of \(\mathrm{Zn}\) is consumed at the anode of the battery. (a) What mass of \(\mathrm{MnO}_{2}\) is reduced at the cathode during this discharge? (b) How many coulombs of electrical charge are transferred from \(\mathrm{Zn}\) to \(\mathrm{MnO}_{2}\) ?

Short Answer

Expert verified
(a) The mass of \(\mathrm{MnO}_{2}\) reduced at the cathode is approximately \(2.95\) g. (b) The charge transferred between \(\mathrm{Zn}\) and \(\mathrm{MnO}_{2}\) is approximately \(261000\) C.

Step by step solution

01

Calculate moles of Zinc

To find the moles of Zinc, we will use its molar mass, which is approximately \(65.38 \mathrm{~g/mol}\). We have: Moles of \(\mathrm{Zn} = \frac{\text{mass of Zn}}{\text{molar mass of Zn}}\) Moles of \(\mathrm{Zn} = \frac{4.50 \mathrm{~g}}{65.38 \mathrm{~g/mol}}\)
02

Moles of \(\mathrm{MnO}_{2}\) reduced

During the discharge of the battery, \(\mathrm{Zn}\) and \(\mathrm{MnO}_{2}\) react according to the following balanced equation: $$\mathrm{Zn} + 2 \mathrm{MnO}_{2} \rightarrow \mathrm{ZnO} + \mathrm{Mn}_{2}\mathrm{O}_{3}$$ From the stoichiometry of the reaction, we see that one mole of \(\mathrm{Zn}\) reacts with two moles of \(\mathrm{MnO}_{2}\). So, we can find the moles of \(\mathrm{MnO}_{2}\) reduced using: Moles of \(\mathrm{MnO}_{2} = 2 \times \text{moles of Zn}\)
03

Calculate mass of \(\mathrm{MnO}_{2}\)

To find the mass of \(\mathrm{MnO}_{2}\) reduced, we will use its molar mass, which is approximately \(86.94 \mathrm{~g/mol}\). We have: Mass of \(\mathrm{MnO}_{2} = \text{moles of MnO}_2 \times \text{molar mass of MnO}_2\) (a) The mass of \(\mathrm{MnO}_{2}\) reduced at the cathode can be calculated by plugging the values obtained in Step 1 and Step 2 into the above equation.
04

Calculate the charge transferred

The charge transferred between the two half-reactions can be calculated using Faraday's law: $$Q = n \times F$$ Where \(Q\) is the charge in coulombs, \(n\) is the total moles of electrons transferred, and \(F\) is Faraday's constant (\(96485 \mathrm{~C/mol}\)). For each mole of \(\mathrm{Zn}\) consumed, two moles of electrons are transferred, as shown by the balanced equation. Hence: \(n = 2 \times \text{moles of Zn}\) (b) The charge transferred can be calculated by plugging the values obtained in Step 1 and the value of \(F\) into the above equation. So, follow the steps to determine: (a) The mass of \(\mathrm{MnO}_{2}\) reduced at the cathode and (b) The charge transferred between \(\mathrm{Zn}\) and \(\mathrm{MnO}_{2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is the area of chemistry that involves calculating the quantities of reactants and products in a chemical reaction. It relies heavily on the balanced chemical equation, which provides the necessary ratios needed to perform these calculations.
In the exercise we're discussing, we see stoichiometry at work in several steps. First, it is used to calculate the moles of zinc (\( \mathrm{Zn} \)). Knowing the mass of zinc, and with its molar mass known as well, we can find how many moles of zinc are involved. The formula used is:
  • \( \text{Moles of Zn} = \frac{\text{mass of Zn}}{\text{molar mass of Zn}} \)
Next, stoichiometry helps to determine how much manganese dioxide (\( \mathrm{MnO}_2 \)) is reduced. The balanced chemical equation tells us that every mole of zinc reacts with two moles of \( \mathrm{MnO}_2 \). Therefore:
  • \( \text{Moles of MnO}_2 = 2 \times \text{moles of Zn} \)
Here, stoichiometry provides a clear path from reactants to products, ensuring that the calculations reflect the real chemical process happening in the battery.
Redox Reactions
Redox reactions, or oxidation-reduction reactions, are essential to electrochemistry as they involve the transfer of electrons between substances. In our alkaline battery example, zinc undergoes oxidation, while manganese dioxide undergoes reduction.
Oxidation is the loss of electrons. For zinc, this can be represented by the reaction:
  • \( \mathrm{Zn} \rightarrow \mathrm{Zn}^{2+} + 2\mathrm{e}^- \)
On the other hand, manganese dioxide (\( \mathrm{MnO}_2 \)) undergoes reduction, gaining electrons in the process. Its half-reaction is generally written as:
  • \( \mathrm{MnO}_2 + \mathrm{H}^+ + \mathrm{e}^- \rightarrow \mathrm{MnO(OH)} \)
These two half-reactions together drive the electric current in the battery by moving electrons from zinc, which is oxidized at the anode, to manganese dioxide, which is reduced at the cathode.
Being able to understand and balance these redox reactions is crucial in predicting the behavior of electrochemical cells.
Faraday's Law
Faraday's Law of Electrolysis is a key principle that allows chemists to link the amount of electric charge to the amount of substance converted at an electrode in an electrochemical cell. This law states that the amount of substance altered at an electrode during electrolysis is directly proportional to the quantity of electricity that passes through the circuit.
To put it simply, for zinc (\( \mathrm{Zn} \)) oxidized in our example, Faraday's law allows us to calculate the total charge in coulombs by using:
  • \( Q = n \times F \)
Here, \( Q \) is the charge, \( n \) is the number of moles of electrons transferred, and \( F \) is Faraday's constant (\( 96485 \mathrm{~C/mol} \)).
Given that for every mole of zinc consumed, two moles of electrons are transferred, the mole value \( n = 2 \times \text{moles of Zn} \) is used. This relationship is the backbone of calculations regarding charge transfer in electrochemistry, empowering us to quantify the electrical output or requirements of a chemical process.

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Most popular questions from this chapter

Magnesium is obtained by electrolysis of molten \(\mathrm{MgCl}_{2}\). (a) Why is an aqueous solution of \(\mathrm{MgC}_{2}\) not used in the electrolysis? (b) Several cells are connected in parallel by very large copper bars that convey current to the cells. Assuming that the cells are \(96 \%\) efficient in producing the desired products in electrolysis, what mass of \(\mathrm{Mg}\) is formed by passing a current of \(97,000 \mathrm{~A}\) for a period of \(24 \mathrm{~h}\) ?

Complete and balance the following half-reactions. In each case indicate whether the half-reaction is an oxidation or a reduction. (a) \(\mathrm{Mo}^{3+}(a q) \longrightarrow \mathrm{Mo}(s)\) (acidic solution) (b) \(\mathrm{H}_{2} \mathrm{SO}_{3}(a q) \longrightarrow \mathrm{SO}_{4}^{2-}(a q)\) (acidic solution) (c) \(\mathrm{NO}_{3}^{-}(a q) \longrightarrow \mathrm{NO}(\mathrm{g})\) (acidic solution) (d) \(\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\) (acidic solution) (e) \(\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)\) (basic solution) (f) \(\mathrm{Mn}^{2+}(\) aq \() \longrightarrow \mathrm{MnO}_{2}(s)\) (basic solution) (g) \(\mathrm{Cr}(\mathrm{OH})_{3}(s) \longrightarrow \mathrm{CrO}_{4}^{2-}\) (aq) (basic solution)

(a) A voltaic cell is constructed with all reactants and products in their standard states. Will the concentration of the reactants increase, decrease, or remain the same as the cell operates? (b) What happens to the emf of a cell if the concentrations of the products are increased?

From each of the following pairs of substances, use data in Appendix E to choose the one that is the stronger reducing agent: (a) Fe(s) or \(\mathrm{Mg}(s)\) (b) \(\mathrm{Ca}(s)\) or \(\mathrm{Al}(s)\) (c) \(\mathrm{H}_{2}\) (g, acidic solution) or \(\mathrm{H}_{2} \mathrm{~S}(\mathrm{~g})\) (d) \(\mathrm{BrO}_{3}^{-}(a q)\) or \(\mathrm{lO}_{3}^{-}(a q)\) 20.44 From each of the following pairs of substances, use data in Appendix E to choose the one that is the stronger oxidizing agent: (a) \(\mathrm{Cl}_{2}(g)\) or \(\mathrm{Br}_{2}(l)\) (b) \(\mathrm{Zn}^{2+}(a q)\) or \(\operatorname{Cd}^{2+}(a q)\) (c) \(\mathrm{Cl}^{-}(a q)\) or \(\mathrm{ClO}_{3}^{-}(a q)\) (d) \(\mathrm{H}_{2} \mathrm{O}_{2}(a q)\) or \(\mathrm{O}_{2}(\mathrm{~g})\) 20.45 By using the data in Appendix E, determine whether each of the following substances is likely to serve as an exidant or a reductant: (a) \(\mathrm{Cl}_{2}\) (g), (b) \(\mathrm{MnO}_{4}^{-}\)(aq, acidic solution), (c) \(\mathrm{Ba}\) (s), (d) \(\mathrm{Zn}(\) s). 20.46 Is each of the following substances likely to serve as an oxidant or a reductant: (a) \(\mathrm{Ce}^{3+}(\mathrm{aq})\), (b) \(\mathrm{Ca}(\mathrm{s})\), (c) \(\mathrm{CO}_{3}^{-}(\mathrm{aq})\), (d) \(\mathrm{N}_{2} \mathrm{O}_{5}(g)\) ? \(20.47\) (a) Assuming standard conditions, arrange the following in order of increasing strength as oxidizing agents in acidic solution: \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{Cu}^{2+}, \mathrm{C}_{2}, \mathrm{O}_{2}\) (b) Arrange the following in order of increasing strength as reducing agents in acidic solution: \(\mathrm{Zn}, \mathrm{I}^{-}, \mathrm{Sn}^{2+}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{AL}\). 20.48 Based on the data in Appendix E, (a) which of the following is the strongest oxidizing agent and which is the weakest in acidic solution: \(\mathrm{Br}_{2}, \mathrm{H}_{2} \mathrm{O}_{2}, \mathrm{Zn}, \mathrm{Cr}_{2} \mathrm{O}_{7}{ }^{2-} ?\) (b) Which of the following is the strongest reducing agent, and which is the weaket in acidic solution: \(\mathrm{F}^{-}, \mathrm{Zn}, \mathrm{N}_{1}{ }^{+}\), \(\mathrm{I}_{\mathrm{n}} \mathrm{NO}\) ?

Consider a redox reaction for which \(E^{b}\) is a negative number. (a) What is the sign of \(\Delta G^{\text {e }}\) for the reaction? (b) Will the equilibrium constant for the reaction be larger or smaller than 1? (c) Can an electrochemical cell based on this reaction accomplish work on its surroundings? [Section 20.5]

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