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Consider a redox reaction for which \(E^{b}\) is a negative number. (a) What is the sign of \(\Delta G^{\text {e }}\) for the reaction? (b) Will the equilibrium constant for the reaction be larger or smaller than 1? (c) Can an electrochemical cell based on this reaction accomplish work on its surroundings? [Section 20.5]

Short Answer

Expert verified
(a) The sign of ΔG is positive, as ΔG = -nFE and E is negative. (b) The equilibrium constant (K) for the reaction is smaller than 1 since ln(K) < 0 when ΔG > 0. (c) No, an electrochemical cell based on this reaction cannot accomplish work on its surroundings, as it has a negative cell potential (E).

Step by step solution

01

Determine the sign of ΔG based on E

The relationship between Gibbs free energy (ΔG) and cell potential (E) is given by the formula: ΔG = -nFE where n is the number of moles of electrons transferred, F is the Faraday constant (96,485 C/mol), and E is the cell potential. If E is a negative number, the product of -nFE will be positive. So: ΔG > 0 (a) The sign of ΔG is positive.
02

Determine the relationship between equilibrium constant (K) and ΔG

We can use the relationship between ΔG and the equilibrium constant (K) to determine whether K is larger or smaller than 1. That relationship is given by the formula: ΔG = -RTln(K) where R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin, and K is the equilibrium constant. Since we already know that ΔG is positive: 0 < -RTln(K) Therefore, ln(K) < 0 which implies: K < 1 (b) The equilibrium constant for the reaction is smaller than 1.
03

Determine if the cell can accomplish work on its surroundings

An electrochemical cell can accomplish work on its surroundings when it has a positive cell potential (E). Since E is given to be negative in this problem, the cell cannot accomplish work on its surroundings. (c) No, an electrochemical cell based on this reaction cannot accomplish work on its surroundings.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy
Gibbs Free Energy (\(\Delta G\)) is a crucial thermodynamic quantity used to determine the spontaneity of a chemical reaction. Simply put, it tells us whether a reaction can occur by itself. For a reaction to be spontaneous, \(\Delta G\) must be negative, indicating that the process can release free energy and proceed without any external input.
In contrast, when \(\Delta G\) is positive, as derived from \(\Delta G = -nFE\), the reaction is non-spontaneous under standard conditions. Here, the negative sign before the equation suggests that when the cell potential \((E)\) is negative, \(\Delta G\) becomes positive. Hence, the reaction requires energy input to proceed, making it less favorable. Understanding Gibbs Free Energy helps predict the direction and feasibility of chemical processes.
Equilibrium Constant
The Equilibrium Constant (\(K\)) plays a fundamental role in predicting the extent of a reaction at equilibrium. It is a ratio that compares the concentrations of products to reactants for a reaction at equilibrium. A key equation linking Gibbs Free Energy to \(K\) is \(\Delta G = -RT\ln(K)\), where \(R\) is the gas constant and \(T\) is temperature in Kelvin.
When \(\Delta G\) is positive, as discovered, this leads to \(\ln(K) < 0\), implying that \(K < 1\). Meaning, at equilibrium, reactant concentrations are higher than those of the products. This tells us that the reaction does not go significantly towards the products, aligning with its non-spontaneous nature. The equilibrium constant thus provides valuable insight into the equilibrium position and overall reaction tendencies.
Cell Potential
Cell Potential (\(E\)), measured in volts, is a measure of the electromotive force of an electrochemical cell. It determines the ability of a redox reaction to push electrons through a circuit, doing useful work. The expression \(\Delta G = -nFE\) links cell potential with Gibbs Free Energy, showing how a positive or negative \(E\) influences the reaction's spontaneity.
A negative cell potential, as given, implies that the reaction is not self-sustaining—the system must receive energy input rather than providing energy. Consequently, this contributes to a positive \(\Delta G\), further affirming that the cell cannot effectively perform its intended task of generating electricity or doing mechanical work. Understanding cell potential helps in designing and predicting the performance of electrochemical cells.
Electrochemical Cell
An Electrochemical Cell is a device that converts chemical energy into electrical energy through redox reactions. It consists of two half-cells connected by a salt bridge and an external circuit. The cell potential (\(E\)) is crucial for determining the cell's ability to perform work.
Naturally, when \(E\) is positive, the electrochemical cell can perform work, such as powering electronic devices or triggering chemical reactions. However, with a negative cell potential as given in this exercise, it is concluded that the cell is inefficient in producing work. Instead, it might require energy input to function, highlighting its limitation in this particular reaction. Understanding the workings of electrochemical cells is essential for applications in batteries and fuel cells.
Thermodynamics
Thermodynamics is the branch of chemistry that deals with energy changes, particularly focusing on heat and work involved during chemical reactions and physical processes. It is built upon laws that predict the direction and feasibility of a process.
The link between thermodynamics and Gibbs Free Energy in electrochemical cells is central. The relationship expressed in \(\Delta G = -nFE\) provides a thermodynamic view of how energy transformations occur in electrochemical reactions. When cell potential is negative—and thus thermodynamically unfavorable—a deeper thermo understanding sheds light on why such cells need an external energy source.
  • First Law: Energy can't be created or destroyed.
  • Second Law: Every energy transfer leads to increased entropy.
These laws among others guide the study and application of electrochemical cells and their energy-related behaviors.

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Most popular questions from this chapter

A voltaic cell consists of a strip of cadmium metal in a solution of \(\mathrm{Cd}\left(\mathrm{NO}_{3}\right)_{2}\) in one beaker, and in the other beaker a platinum electrode is immersed in a \(\mathrm{NaCl}\) solution, with \(\mathrm{C}_{2}\) gas bubbled around the electrode. A salt bridge connects the two beakers. (a) Which electrode serves as the anode and which as the cathode? (b) Does the Cd electrode gain or lose mass as the cell reaction proceeds? (c) Write the equation for the overall cell reaction. (d) What is the emf generated by the cell under standard conditions? Strengths of Oxidizing and Reducing Agents (Section 20.4)

The crude copper that is subjected to electrorefining contains tellurium as an impurity. The standard reduction potential between tellurium and its lowest common oxidation state, \(\mathrm{Te}^{4+}\), is $$ \mathrm{Te}^{4+}(a q)+4 e^{-} \longrightarrow \mathrm{Te}(s) \quad E_{\text {iod }}^{s}=0.57 \mathrm{~V} $$ Given this information, describe the probable fate of tellurium impurities during electrorefining. Do the impurities fall to the bottom of the refining bath, unchanged, as copper is oxidized, or do they go into solution as ions? If they go into solution, do they plate out on the cathode?

In a Li-ion battery the composition of the cathode is \(\mathrm{LiCoO}_{2}\) when completely discharged. On charging approximately \(50 \%\) of the \(\mathrm{Li}^{+}\)ions can be extracted from the cathode and transported to the graphite anode where they intercalate between the layers. (a) What is the composition of the cathode when the battery is fully charged? (b) If the \(\mathrm{LiCoO} 2\) cathode has a mass of \(10 \mathrm{~g}\) (when fully discharged), how many coulombs of electricity can be delivered on completely discharging a fully charged battery?

A \(1 \mathrm{M}\) solution of \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\) is placed in a beaker with a strip of \(\mathrm{Cu}\) metal. A \(1 \mathrm{M}\) solution of \(\mathrm{SnSO}_{4}\) is placed in a second beaker with a strip of \(\mathrm{Sn}\) metal. A salt bridge connects the two beakers, and wires to a voltmeter link the two metal electrodes. (a) Which electrode serves as the anode and which as the cathode? (b) Which electrode gains mass and which loses mass as the cell reaction proceeds? (c) Write the equation for the overall cell reaction. (d) What is the emf generated by the cell under standard conditions?

(a) Based on standard reduction potentials, would you expect copper metal to oxidize under standard conditions in the presence of oxygen and hydrogen ions? (b) When the Statue of Liberty was refurbished, Teflon spacers were placed between the iron skeleton and the copper metal on the surface of the statue. What role do these spacers play?

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