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Given the following bond-dissociation energies, calculate the average bond enthalpy for the Ti-Cl bond. \begin{tabular}{ll} \hline & \(\Delta H(\mathbf{k J} /\) mol \()\) \\ \hline \(\mathrm{TiCl}_{4}(g) \longrightarrow \mathrm{TiCl}_{3}(g)+\mathrm{Cl}(g)\) & 335 \\ \(\mathrm{TiCl}_{3}(g) \longrightarrow \mathrm{TiCl}_{2}(g)+\mathrm{Cl}(g)\) & 423 \\ \(\mathrm{TiCl}_{2}(g) \longrightarrow \mathrm{TiCl}(g)+\mathrm{Cl}(g)\) & 444 \\\ \(\mathrm{TiCl}(g) \longrightarrow \mathrm{Ti}(g)+\mathrm{Cl}(g)\) & 519 \\ \hline \end{tabular}

Short Answer

Expert verified
The average bond enthalpy for the Ti-Cl bond is approximately \(430.25 kJ/mol\).

Step by step solution

01

Identify the number of Ti-Cl bonds broken in each reaction

We will determine the number of Ti-Cl bonds being broken in each reaction as follows: 1. TiCl4(g) → TiCl3(g) + Cl(g) - In this reaction, 1 Ti-Cl bond is being broken (4 bonds in TiCl4 to 3 bonds in TiCl3) 2. TiCl3(g) → TiCl2(g) + Cl(g) - In this reaction, 1 Ti-Cl bond is being broken (3 bonds in TiCl3 to 2 bonds in TiCl2) 3. TiCl2(g)→ TiCl(g) + Cl(g) - In this reaction, 1 Ti-Cl bond is being broken (2 bonds in TiCl2 to 1 bond in TiCl) 4. TiCl(g) → Ti(g) + Cl(g) - In this reaction, 1 Ti-Cl bond is being broken (1 bond in TiCl to 0 bonds in Ti)
02

Calculate the cumulative bond dissociation energies for all Ti-Cl bonds

To calculate the cumulative bond dissociation energies, we need to multiply the bond dissociation energy for each reaction by the number of Ti-Cl bonds broken in the corresponding reaction. Then we need to sum the values for each reaction to find the total energy. Total Energy = (1 x 335 kJ/mol) + (1 x 423 kJ/mol) + (1 x 444 kJ/mol) + (1 x 519 kJ/mol) Total Energy = 335 kJ/mol + 423 kJ/mol + 444 kJ/mol + 519 kJ/mol = 1721 kJ/mol
03

Calculate the average bond enthalpy for the Ti-Cl bond

To calculate the average bond enthalpy for the Ti-Cl bond, divide the total cumulative bond dissociation energy by the total number of Ti-Cl bonds broken in all reactions. Average Bond Enthalpy = Total Energy / Total Number of Ti-Cl Bonds Broken There are a total of 1 + 1 + 1 + 1 = 4 Ti-Cl bonds broken over the four reactions. So, Average Bond Enthalpy = 1721 kJ/mol / 4 Average Bond Enthalpy = 430.25 kJ/mol The average bond enthalpy for the Ti-Cl bond is approximately 430.25 kJ/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bond-Dissociation Energy
The bond-dissociation energy is a measure of the strength of a chemical bond. It represents the energy required to break a bond between two atoms in a molecule. This energy is expressed in kilojoules per mole (kJ/mol). Bond-dissociation energy is a crucial concept in understanding how strong a particular bond is.
In chemical reactions, bonds in reactants are broken to form new bonds in the products. The bond-dissociation energy helps predict the energy changes that occur during these transformations. A higher bond-dissociation energy indicates a stronger bond, requiring more energy to break. Understanding this concept is valuable in fields like chemistry and material science, where it aids in predicting reaction pathways and stability of compounds.
Ti-Cl Bond
The Ti-Cl bond is a type of chemical bond between titanium (Ti) and chlorine (Cl). These bonds are formed in compounds such as titanium tetrachloride (TiCl₄) and its lower chlorides, TiCl₃, TiCl₂, and TiCl.
In the context of the exercise, bonding is broken as you move from TiClâ‚„ all the way down to Ti and Cl individually. Each step involves breaking one Ti-Cl bond, demonstrating the sequential breakdown of a compound containing titanium and chlorine. This highlights the individual impact of each bond on the stability and energy requirements of the compound. Understanding the nature of the Ti-Cl bond assists in calculating energies needed for changes and predicting reaction behaviors.
Average Bond Enthalpy
The average bond enthalpy is the average amount of energy required to break one bond in a molecule in the gas phase. It's derived by averaging the bond-dissociation energies from several similar compounds or steps.
In the given exercise, calculating the average bond enthalpy for the Ti-Cl bond involves averaging the bond-dissociation energies for each distinct bond broken in the series of reactions transitioning from TiClâ‚„ to Ti. The overall cumulative energy calculated (1721 kJ/mol) was divided by the total number of bonds broken (four) to find the average, resulting in 430.25 kJ/mol. This average value provides an overall understanding of the energy involved in breaking the Ti-Cl bonds.
Chemical Reactions
Chemical reactions involve the rearrangement of atoms through the breaking and formation of bonds, converting reactants into products. Each reaction has an associated energy change, dominated by the bond-dissociation processes involved.
In the exercise, each step is a chemical reaction representing the breakdown of a compound with varying numbers of Ti-Cl bonds. Understanding these reactions is crucial as it showcases how energy is absorbed to overcome the bond energies during the transformation process. Knowledge of such reactions is important for studying reaction mechanics and kinetic behaviors of compounds.
Enthalpy Calculation
Enthalpy calculation is vital for understanding energy changes in a chemical system. It represents the total energy change, mainly the heat energy, involved when a reaction occurs at constant pressure.
In our exercise, different reactions break one Ti-Cl bond each, requiring a particular amount of energy stated as their bond-dissociation enthalpies. By adding these energies, we find the cumulative enthalpy change, which informs us about the total energy intake needed for these processes.
Calculating enthalpy changes helps in predicting reaction direction, feasibility, and energy efficiency in chemical processes. It forms the backbone of thermodynamics in the study of chemistry.

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Most popular questions from this chapter

(a) What is the trend in electronegativity going from left to right in a row of the periodic table? (b) How do electronegativity values generally vary going down a column in the periodic table? (c) How do periodic trends in electronegativity relate to those for ionization energy and electron affinity?

(a) Determine the formal charge on the chlorine atom in the hypochlorite ion, \(\mathrm{ClO}^{-},\) and the perchlorate ion, \(\mathrm{ClO}_{4}^{-},\) using resonance structures where the \(\mathrm{Cl}\) atom has an octet. (b) What are the oxidation numbers of chlorine in \(\mathrm{ClO}^{-}\) and in \(\mathrm{ClO}_{4}^{-} ?\) (c) Is it uncommon for the formal charge and the oxidation state to be different? Explain. (d) Perchlorate is a much stronger oxidizing agent than hypochlorite. Would you expect there to be any relationship between the oxidizing power of the oxyanion and either the oxidation state or the formal charge of chlorine?

Under special conditions, sulfur reacts with anhydrous liquid ammonia to form a binary compound of sulfur and nitrogen. The compound is found to consist of \(69.6 \% \mathrm{~S}\) and \(30.4 \% \mathrm{~N}\). Measurements of its molecular mass yield a value of \(184.3 \mathrm{~g} \mathrm{~mol}^{-1}\). The compound occasionally detonates on being struck or when heated rapidly. The sulfur and nitrogen atoms of the molecule are joined in a ring. All the bonds in the ring are of the same length. (a) Calculate the empirical and molecular formulas for the substance. (b) Write Lewis structures for the molecule, based on the information you are given. (Hint: You should find a relatively small number of dominant Lewis structures.) (c) Predict the bond distances between the atoms in the ring. (Note: The \(\mathrm{S}-\mathrm{S}\) distance in the \(\mathrm{S}_{8}\) ring is \(2.05 \AA\). \()\) (d) The enthalpy of formation of the compound is estimated to be \(480 \mathrm{~kJ} \mathrm{~mol}^{-1} . \Delta H_{f}^{\circ}\) of \(\mathrm{S}(g)\) is \(222.8 \mathrm{~kJ} \mathrm{~mol}^{-1}\). Estimate the average bond enthalpy in the compound.

Average bond enthalpies are generally defined for gas-phase molecules. Many substances are liquids in their standard state. coo (Section 5.7) By using appropriate thermochemical data from Appendix C, calculate average bond enthalpies in the liquid state for the following bonds, and compare these values to the gas-phase values given in Table 8.4: (a) \(\mathrm{Br}-\mathrm{Br}\), from \(\mathrm{Br}_{2}(l) ;\) (b) \(\mathrm{C}-\mathrm{Cl},\) from \(\mathrm{CCl}_{4}(l) ;\) (c) \(\mathrm{O}-\mathrm{O},\) from \(\mathrm{H}_{2} \mathrm{O}_{2}(I)\) (assume that the \(\mathrm{O}-\mathrm{H}\) bond enthalpy is the same as in the gas phase). (d) What can you conclude about the process of breaking bonds in the liquid as compared to the gas phase? Explain the difference in the \(\Delta H\) values between the two phases.

Based on Lewis structures, predict the ordering of \(\mathrm{N}-\mathrm{O}\) bond lengths in \(\mathrm{NO}^{+}, \mathrm{NO}_{2}^{-},\) and \(\mathrm{NO}_{3}^{-}\).

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