/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Which ionic compound is expected... [FREE SOLUTION] | 91影视

91影视

Which ionic compound is expected to form from combining the following pairs of elements: (a) barium and fluorine, (b) cesium and chlorine, (c) lithium and nitrogen, (d) aluminum and oxygen?

Short Answer

Expert verified
The ionic compounds formed from the given pairs of elements are: (a) BaF鈧, (b) CsCl, (c) Li鈧僋, and (d) Al鈧侽鈧.

Step by step solution

01

Identify the charges of the ions

Barium (Ba) is in Group 2, so it tends to form a +2 ion (Ba虏鈦). Fluorine (F) is in Group 7 (also known as Group 17), so it tends to form a -1 ion (F鈦).
02

Combine the ions to form an ionic compound

To form a stable ionic compound, we need the charges to balance out. In this case, we will need two F鈦 ions to balance the charge of one Ba虏鈦 ion. The ionic compound formed will be BaF鈧. #b) Cesium and Chlorine#
03

Identify the charges of the ions

Cesium (Cs) is in Group 1, so it tends to form a +1 ion (Cs鈦). Chlorine (Cl) is also in Group 7 (Group 17), so it tends to form a -1 ion (Cl鈦).
04

Combine the ions to form an ionic compound

In this case, the charges of the ions are already balanced. We can directly combine one Cs鈦 ion with one Cl鈦 ion to form the ionic compound CsCl. #c) Lithium and Nitrogen#
05

Identify the charges of the ions

Lithium (Li) is in Group 1, so it tends to form a +1 ion (Li鈦). Nitrogen (N) is in Group 5 (Group 15), so it tends to form a -3 ion (N鲁鈦).
06

Combine the ions to form an ionic compound

We will need three Li鈦 ions to balance the charge of one N鲁鈦 ion. The ionic compound formed will be Li鈧僋. #d) Aluminum and Oxygen#
07

Identify the charges of the ions

Aluminum (Al) is in Group 13, so it tends to form a +3 ion (Al鲁鈦). Oxygen (O) is in Group 6 (Group 16), so it tends to form a -2 ion (O虏鈦).
08

Combine the ions to form an ionic compound

In this case, we will need two Al鲁鈦 ions to balance the charge of three O虏鈦 ions, giving us a compound ratio of 2:3. The ionic compound formed will be Al鈧侽鈧.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Bonding
When atoms come together, they engage in different forms of chemical bonding to achieve stability. Ionic bonding is a type of chemical bond that involves the transfer of electrons between atoms. In this process, one atom loses one or more electrons, becoming a positively charged ion, while another atom gains those electrons, becoming a negatively charged ion. The electrostatic attraction between these oppositely charged ions holds them together, creating an ionic compound.
The formation of ionic compounds is typically observed between metals and non-metals. Metals, which are located on the left side of the periodic table, tend to lose electrons and form positive ions (cations). Non-metals, found on the right side, tend to gain electrons, becoming negative ions (anions). By understanding the nature of ionic bonds, we can predict how specific elements will combine to form compounds, like those in everyday substances such as table salt (NaCl).
  • An ionic bond is formed by the transfer of electrons.
  • Metals form cations by losing electrons.
  • Non-metals form anions by gaining electrons.
  • The attraction between ions holds the compound together.
Ion Charges
Ion charges are critical in determining how ionic compounds are formed. Each element has a tendency to lose or gain a specific number of electrons, which corresponds to its ion charge. These charges are often predictable based on an element's position in the periodic table.
Elements in Group 1 typically form a +1 charge because they lose one electron. Group 2 elements form a +2 charge, losing two electrons. For non-metals, the ion charges are generally negative. For instance, Group 17 elements tend to have a -1 charge because they gain one electron to achieve a full outer shell. Understanding these predictable charges helps in determining the ratios of ions needed to form neutral compounds.
  • Group 1 elements form +1 ions.
  • Group 2 elements form +2 ions.
  • Group 17 elements typically form -1 ions.
  • Ion charges must balance to create a stable compound.
Periodic Table Groups
The periodic table is organized into columns known as groups, which reflect the number of electrons in the outer shell of an atom for the main-group elements. These outer electrons, also known as valence electrons, play a key role in chemical bonding and determining ion charges.
Elements within the same group typically exhibit similar chemical behaviors. For instance, elements of Group 1, the alkali metals, all have one valence electron. This uniformity lends them a tendency to lose one electron and form +1 ions. Similarly, Group 17 elements, known as the halogens, have seven valence electrons and often form -1 ions by gaining an electron.
By understanding an element's group, we can predict not only the type of ion it will form but also how it might react with other elements. This knowledge of periodic table groups facilitates the understanding of chemical properties and bonding behavior.
  • Group numbers indicate the number of valence electrons.
  • Elements in the same group exhibit similar chemical properties.
  • Group 1: Alkali metals - tend to form +1 ions.
  • Group 17: Halogens - tend to form -1 ions.
  • Understanding groups aids in predicting chemical reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain the following trends in lattice energy: (a) \(\mathrm{NaCl}>\mathrm{RbBr}>\mathrm{CsBr} ;\) (b) \(\mathrm{BaO}>\mathrm{KF}\) (c) \(\mathrm{SrO}>\mathrm{SrCl}_{2}\)

The substance chlorine monoxide, \(\mathrm{ClO}(g)\), is important in atmospheric processes that lead to depletion of the ozone layer. The ClO molecule has a dipole moment of \(1.24 \mathrm{D}\) and the (a) Determine the magnitude of \(\mathrm{Cl}-\mathrm{O}\) bond length is \(1.60 \mathrm{~A}\). the charges on the \(\mathrm{Cl}\) and \(\mathrm{O}\) atoms in units of the electronic charge, e. (b) Based on the electronegativities of the elements, which atom would you expect to have a negative charge in the ClO molecule? (c) By using formal charges as a guide, propose the dominant Lewis structure for the molecule. Are the formal charges consistent with your answers to parts (a) and (b)? Can you reconcile any differences you find?

Write electron configurations for the following ions, and determine which have noble-gas configurations: (a) \(\mathrm{Cd}^{2+}\) (b) \(\mathrm{P}^{3-}\) (c) \(Z r^{4+}\) (d) \(\mathrm{Ru}^{3+}\), (e) \(\mathrm{As}^{3-},(\mathrm{f}) \mathrm{Ag}^{+}\)

(a) Using average bond enthalpies, predict which of the following reactions will be most exothermic: (i) \(\mathrm{C}(g)+2 \mathrm{~F}_{2}(g) \longrightarrow \mathrm{CF}_{4}(g)\) (ii) \(\mathrm{CO}(g)+3 \mathrm{~F}_{2} \longrightarrow \mathrm{CF}_{4}(g)+\mathrm{OF}_{2}(g)\) (iii) \(\mathrm{CO}_{2}(g)+4 \mathrm{~F}_{2} \longrightarrow \mathrm{CF}_{4}(g)+2 \mathrm{OF}_{2}(g)\) (b) Explain the trend, if any, that exists between reaction exothermicity and the extent to which the carbon atom is bonded to oxygen.

(a) When talking about atoms in a Lewis structure, what is meant by the term formal charge? (b) Does the formal charge of an atom represent the actual charge on that atom? Explain. (c) How does the formal charge of an atom in a Lewis structure differ from the oxidation number of the atom?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.