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Write the condensed electron configurations for the following atoms, using the appropriate noble-gas core abbreviations: (a) \(\mathrm{Cs},(\mathbf{b}) \mathrm{Ni},(\mathrm{c}) \mathrm{Se}\) (d) Cd, (e) \(\mathrm{U},(\mathbf{f}) \mathrm{Pb}\).

Short Answer

Expert verified
The condensed electron configurations using noble-gas core abbreviations for the given atoms are as follows: a) Cs: [\(Xe\)]6s鹿 b) Ni: [\(Ar\)]4s虏3d鈦 c) Se: [\(Ar\)]4s虏3d鹿鈦4p鈦 d) Cd: [\(Kr\)]5s虏4d鹿鈦 e) U: [\(Rn\)]7s虏5f鲁 f) Pb: [\(Xe\)]6s虏4f鹿鈦5d鹿鈦6p虏

Step by step solution

01

Identify the nearest noble gas with fewer electrons

For each element, find the noble gas with fewer electrons and atomic number closest to the given atom. Write down their element symbols and atomic numbers for reference. a) Cs (Cesium): Xe, 54 b) Ni (Nickel): Ar, 18 c) Se (Selenium): Ar, 18 d) Cd (Cadmium): Kr, 36 e) U (Uranium): Rn, 86 f) Pb (Lead): Xe, 54
02

Write the electron configuration from the noble gas core to the atom

Write the electron configuration from the atomic number of the noble gas core to the atomic number of the given atom. Use the periodic table to aid you in identifying the orbitals being filled. a) Cs: \(Xe\) -> 6s鹿 b) Ni: \(Ar\) -> 4s虏3d鈦 c) Se: \(Ar\) -> 4s虏3d鹿鈦4p鈦 d) Cd: \(Kr\) -> 5s虏4d鹿鈦 e) U: \(Rn\) -> 7s虏5f鲁 f) Pb: \(Xe\) -> 6s虏4f鹿鈦5d鹿鈦6p虏
03

Combine the noble gas core abbreviation with the electron configurations

Replace the noble gas symbols with their electron configuration abbreviations in brackets and combine them with the electron configurations found in Step 2. a) Cs: [\(Xe\)]6s鹿 b) Ni: [\(Ar\)]4s虏3d鈦 c) Se: [\(Ar\)]4s虏3d鹿鈦4p鈦 d) Cd: [\(Kr\)]5s虏4d鹿鈦 e) U: [\(Rn\)]7s虏5f鲁 f) Pb: [\(Xe\)]6s虏4f鹿鈦5d鹿鈦6p虏

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Noble Gas Core Abbreviation
The noble gas core abbreviation is a useful shorthand technique in writing electron configurations for elements. This approach involves using the electron configuration of a noble gas that comes right before the element in question, thereby simplifying the notation.
For example, rather than listing out the entire electron configuration from the first orbitals, you use the symbol of the nearest noble gas enclosed in square brackets to represent all the filled orbitals up to that noble gas.
Let's take Nickel (Ni) as an example:
- First, identify the noble gas preceding Nickel on the periodic table, which is Argon (Ar) with an atomic number of 18.
- So, the electron configuration of Nickel can start with [Ar], indicating that those inner-shell electrons are identical to Argon's.
The next step involves writing out the remaining electrons beyond Argon. Thus, the electron configuration for Nickel becomes [Ar]4s虏3d鈦. In this way, the condensed notation quickly conveys necessary information without overwhelming detail.
By using noble gas symbols in electron configurations, chemists save space and time while ensuring clarity.
Periodic Table
The periodic table is an essential tool in chemistry, acting as a comprehensive map of all known elements, including metals, nonmetals, and metalloids. Each element is placed in a unique position based on its atomic number, which denotes the number of protons in its nucleus.
The table is divided into rows, known as periods, and columns known as groups or families. Elements in the same group often share chemical properties, as they have the same number of electrons in their outer shell.
Using the periodic table to write electron configurations involves understanding the overall layout:
- **Periods (Rows):** Elements are arranged in increasing atomic number from left to right. Moving through a period fills successive electron shells.
- **Groups (Columns):** Vertical columns represent elements that typically have similar valence electron configurations. For instance, the noble gases, like Argon (Ar), Krypton (Kr), and Xenon (Xe) are all found in the same group because of their filled outer electron shells.
Utilizing this structure, you can efficiently locate the nearest noble gas to start your electron configuration. For example, if you are finding the configuration for Selenium (Se), which has an atomic number of 34, its nearest noble gas is Argon (Ar), with an atomic number of 18.
The periodic table also shows the order of orbital filling, guiding you to determine which orbitals are occupied in their sequence.
Electron Configuration Steps
Following a structured process to determine electron configurations allows you to correctly and efficiently assign electrons to an atom's orbitals. Here's a simple guide broken down into steps:
1. **Identify the Nearest Noble Gas:** Look at the periodic table and find the noble gas that comes just before your element of interest. Use this as your starting point.
2. **Count the Electrons Beyond the Noble Gas:** Subtract the atomic number of the noble gas from your element's atomic number. This gives you the number of additional electrons to consider. 3. **Determine Orbital Filling Order:** Use the layout of the periodic table and the Aufbau principle to fill orbitals from lowest to highest energy: following the sequence 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, etc.
4. **Write the Configuration:** Begin with the noble gas core abbreviation (e.g., [Ar]), then add the remaining orbitals until you've accounted for all the element's electrons.
For example, by methodically following these steps, the configuration for Cadmium (Cd), with an atomic number of 48, uses [Kr] as the noble gas core followed by the next orbitals to get [Kr]5s虏4d鹿鈦.
Through practice, these steps become second nature, empowering you to tackle diverse electron shells efficiently.

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Most popular questions from this chapter

Bohr's model can be used for hydrogen-like ions -ions that have only one electron, such as \(\mathrm{He}^{+}\) and \(\mathrm{Li}^{2+}\). (a) Why is the Bohr model applicable to \(\mathrm{He}^{+}\) ions but not to neutral He atoms? (b) The ground-state energies of \(\mathrm{H}, \mathrm{He}^{+},\) and \(\mathrm{Li}^{2+}\) are tabulated as follows: By examining these numbers, propose a relationship between the ground-state energy of hydrogen-like systems and the nuclear charge, \(Z\). (c) Use the relationship you derive in part (b) to predict the ground-state energy of the \(\mathrm{C}^{5+}\) ion.

Explain how the existence of line spectra is consistent with Bohr's theory of quantized energies for the electron in the hydrogen atom.

Identify the group of elements that corresponds to each of the following generalized electron configurations and indicate the number of unpaired electrons for each: (a) \([\) noble gas \(] n s^{2} n p^{5}\) (b) \([\) noble gas \(] n s^{2}(n-1) d^{2}\) (c) \([\) noble gas \(] n s^{2}(n-1) d^{10} n p^{1}\) (d) \([\) noble gas \(] n s^{2}(n-2) f^{6}\)

The visible emission lines observed by Balmer all involved \(n_{f}=2 .\) (a) Explain why only the lines with \(n_{f}=2\) were observed in the visible region of the electromagnetic spectrum. (b) Calculate the wavelengths of the first three lines in the Balmer series - those for which \(n_{i}=3,4,\) and \(5-\) and identify these lines in the emission spectrum shown in Figure 6.11 .

Certain elements emit light of a specific wavelength when they are burned. Historically, chemists used such emission wavelengths to determine whether specific elements were present in a sample. Characteristic wavelengths for some of the elements are given in the following table: \(\begin{array}{llll}\mathrm{Ag} & 328.1 \mathrm{nm} & \mathrm{Fe} & 372.0 \mathrm{nm} \\ \mathrm{Au} & 267.6 \mathrm{nm} & \mathrm{K} & 404.7 \mathrm{nm} \\ \mathrm{Ba} & 455.4 \mathrm{nm} & \mathrm{Mg} & 285.2 \mathrm{nm} \\ \mathrm{Ca} & 422.7 \mathrm{nm} & \mathrm{Na} & 589.6 \mathrm{nm} \\ \mathrm{Cu} & 324.8 \mathrm{nm} & \mathrm{Ni} & 341.5 \mathrm{nm}\end{array}\) (a) Determine which elements emit radiation in the visible part of the spectrum. (b) Which element emits photons of highest energy? Of lowest energy? (c) When burned, a sample of an unknown substance is found to emit light of frequency \(6.59 \times 10^{14} \mathrm{~s}^{-1} .\) Which of these elements is probably in the sample?

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