/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 84 A pound of plain \(\mathrm{M\&am... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Problem 84

A pound of plain \(\mathrm{M\&M}\) candies contains \(96 \mathrm{~g}\) fat, \(320 \mathrm{~g}\) carbohydrate, and 21 g protein. What is the fuel value in \(\mathrm{kJ}\) in a \(42-\mathrm{g}\) (about 1.5 oz ) serving? How many Calories does it provide?

Short Answer

Expert verified
A 42-g serving of plain M&M's provides approximately \(899.4 \mathrm{~kJ}\) and 215 Calories.

Step by step solution

01

Calculate the energy provided by fat, carbohydrate, and protein in one pound of M&M's

Each macro has a different energy contribution: Fat has 37 kJ/g, carbohydrates have 17 kJ/g, and protein has 17 kJ/g. So, for one pound of M&M's: Energy from fat = \(96 \mathrm{~g}\) x \(37 \mathrm{~kJ/g}\) = \(3552 \mathrm{~kJ}\) Energy from carbohydrates = \(320 \mathrm{~g}\) x \(17 \mathrm{~kJ/g}\) = \(5440 \mathrm{~kJ}\) Energy from protein = \( 21 \mathrm{~g}\) x \(17 \mathrm{~kJ/g}\) = \(357 \mathrm{~kJ}\) Total energy = Energy from fat + Energy from carbohydrates + Energy from protein Total energy = \(3552 + 5440 + 357 \mathrm{~kJ}\) = \(9349 \mathrm{~kJ}\)
02

Calculate the total energy per gram

To find out the energy provided by one gram of plain M&M's, we need to divide the total energy by the weight of the candy. Total energy per gram = Total energy 梅 Total weight Total energy per gram = \(9349 \mathrm{~kJ}\) 梅 \(437 \mathrm{~g}\) = \(21.40 \mathrm{~kJ/g}\)
03

Calculate the energy in a 42-g serving

Now we can calculate the fuel value in a 42-g serving by multiplying the energy per gram by the serving size. Energy in a 42-g serving = Total energy per gram 脳 Serving size Energy in a 42-g serving = \(21.40 \mathrm{~kJ/g}\) 脳 \(42 \mathrm{~g}\) = \(899.4 \mathrm{~kJ}\)
04

Calculate the energy value in Calories

To convert the energy value to Calories (dietary/caloric), we need to know that 1 Calorie is equal to 4.184 kJ. Energy in a 42-g serving (Calories) = Energy in a 42-g serving (kJ) 梅 4.184 Energy in a 42-g serving (Calories) = \(899.4 \mathrm{~kJ}\) 梅 4.184 = 215 Calories So, a 42-g serving of plain M&M鈥檚 provides approximately 899.4 kJ and 215 Calories.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fuel Value Calculation
Understanding the fuel value of food is akin to assessing the energy that a specific quantity of that food provides when consumed. This concept is crucial for determining caloric intake and managing dietary needs.

Let's begin by considering a real-world example - a serving of M&M candies. The fuel value can be calculated by multiplying the amount of each nutrient (fat, carbohydrates, and protein) in a serving by the energy that each of those nutrients contributes. For instance, fats are generally more energy-dense, with a standard fuel value of approximately 37 kJ/g. Carbohydrates and proteins offer less, about 17 kJ/g each.

To calculate the fuel value for a serving, we would follow these steps:
Energy Content of Nutrients
Fuel values for nutrients are based on the amount of energy they provide, typically measured in kilojoules per gram (kJ/g) or Calories per gram. The three primary macronutrients have standard energy values:
  • Fat: 37 kJ/g (about 9 Calories/g)
  • Carbohydrates: 17 kJ/g (about 4 Calories/g)
  • Protein: 17 kJ/g (also approximately 4 Calories/g)
These values are average estimates and can differ slightly based on the exact composition of a particular food item. In our M&M example, the total energy content is calculated by combining the individual contributions from fats, carbohydrates, and proteins. It is the sum of these components that provides the overall caloric content of the food.
Dietary Calories
In the context of nutrition, Calories (with a capital 'C') refer to kilocalories, which are units used to measure the energy in food. One dietary Calorie is equal to 4.184 kilojoules (kJ). This conversion is vital when reading nutritional information and in calculating energy intake for dietary planning.

When evaluating the calorie content of a serving of M&M's, we convert the measured energy from kilojoules to Calories to align with common dietary standards. This allows individuals to relate the energy content to dietary recommendations and daily calorie allowances.

Remember that counting Calories can help with managing weight and ensuring a balanced diet, but it is also essential to consider the quality and nutritional value of the foods consumed, not just the caloric content.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In what two ways can an object possess energy? How do these two ways differ from one another?

A 200 -lb man decides to add to his exercise routine by walking up three flights of stairs \((45 \mathrm{ft}) 20\) times per day. He figures that the work required to increase his potential energy in this way will permit him to eat an extra order of French fries, at 245 Cal, without adding to his weight. Is he correct in this assumption?

Consider the decomposition of liquid benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}(l),\) to gaseous acetylene, \(\mathrm{C}_{2} \mathrm{H}_{2}(g):\) $$ \mathrm{C}_{6} \mathrm{H}_{6}(l) \longrightarrow 3 \mathrm{C}_{2} \mathrm{H}_{2}(g) \quad \Delta H=+630 \mathrm{~kJ} $$ (a) What is the enthalpy change for the reverse reaction? (b) What is \(\Delta H\) for the formation of 1 mol of acetylene? (c) Which is more likely to be thermodynamically favored, the forward reaction or the reverse reaction? (d) If \(\mathrm{C}_{6} \mathrm{H}_{6}(g)\) were consumed instead of \(\mathrm{C}_{6} \mathrm{H}_{6}(l),\) would you expect the magnitude of \(\Delta H\) to increase, decrease, or stay the same? Explain.

The gas-phase reaction shown, between \(\mathrm{N}_{2}\) and \(\mathrm{O}_{2}\), was run in an apparatus designed to maintain a constant pressure. (a) Write a balanced chemical equation for the reaction depicted and predict whether \(w\) is positive, negative, or zero. (b) Using data from Appendix \(\mathrm{C}\), determine \(\Delta H\) for the formation of one mole of the product. Why is this enthalpy change called the enthalpy of formation of the involved product? [Sections 5.3 and 5.7\(]\)

The decomposition of slaked lime, \(\mathrm{Ca}(\mathrm{OH})_{2}(s),\) into lime, \(\mathrm{CaO}(s),\) and \(\mathrm{H}_{2} \mathrm{O}(g)\) at constant pressure requires the addition of \(109 \mathrm{~kJ}\) of heat per mole of \(\mathrm{Ca}(\mathrm{OH})_{2}\). (a) Write a balanced thermochemical equation for the reaction. (b) Draw an enthalpy diagram for the reaction.
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Kinetics

Read Explanation

Chemistry Branches

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemical Analysis

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.