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Specify what ions are present upon dissolving each of the following substances in water: (a) \(\mathrm{MgI}_{2}\), (b) \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3},\) (c) \(\mathrm{HClO}_{4}\), (d) \(\mathrm{NaCH}_{3} \mathrm{COO}\)

Short Answer

Expert verified
Upon dissolving the given substances in water, the following ions are present: (a) \(\mathrm{MgI}_{2}\): Magnesium ions (\(\mathrm{Mg}^{2+}\)) and iodide ions (I鈦) (b) \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\): Aluminum ions (\(\mathrm{Al}^{3+}\)) and nitrate ions (NO鈧冣伝) (c) \(\mathrm{HClO}_{4}\): Hydrogen ions (\(\mathrm{H}^{+}\)) and perchlorate ions (ClO鈧勨伝) (d) \(\mathrm{NaCH}_{3} \mathrm{COO}\): Sodium ions (\(\mathrm{Na}^{+}\)) and acetate ions (CH鈧僀OO鈦)

Step by step solution

01

(a) Dissociating MgI鈧

When magnesium iodide (\(\mathrm{MgI}_{2}\)) is dissolved in water, it dissociates into one magnesium ion (Mg虏鈦) and two iodide ions (I鈦): \[\mathrm{MgI}_{2} \rightarrow \mathrm{Mg}^{2+} + 2\mathrm{I}^{-}\]
02

Ions Present in MgI鈧 Solution

In the case of a \(\mathrm{MgI}_{2}\) solution, we have magnesium ions (\(\mathrm{Mg}^{2+}\)) and iodide ions (I鈦). -----
03

(b) Dissociating Al(NO鈧)鈧

When aluminum nitrate (\(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\)) is dissolved in water, it dissociates into one aluminum ion (Al鲁鈦) and three nitrate ions (NO鈧冣伝): \[\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3} \rightarrow \mathrm{Al}^{3+} + 3\mathrm{NO}_{3}^{-}\]
04

Ions Present in Al(NO鈧)鈧 Solution

In the case of an \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\) solution, we have aluminum ions (\(\mathrm{Al}^{3+}\)) and nitrate ions (NO鈧冣伝). -----
05

(c) Dissociating HClO鈧

When perchloric acid (\(\mathrm{HClO}_{4}\)) is dissolved in water, it dissociates into one hydrogen ion (H鈦) and one perchlorate ion (ClO鈧勨伝): \[\mathrm{HClO}_{4} \rightarrow \mathrm{H}^{+} + \mathrm{ClO}_{4}^{-}\]
06

Ions Present in HClO鈧 Solution

In the case of an \(\mathrm{HClO}_{4}\) solution, we have hydrogen ions (\(\mathrm{H}^{+}\)) and perchlorate ions (ClO鈧勨伝). -----
07

(d) Dissociating NaCH鈧僀OO

When sodium acetate (\(\mathrm{NaCH}_{3} \mathrm{COO}\)) is dissolved in water, it dissociates into one sodium ion (Na鈦) and one acetate ion (CH鈧僀OO鈦): \[\mathrm{NaCH}_{3} \mathrm{COO} \rightarrow \mathrm{Na}^{+} + \mathrm{CH}_{3}\mathrm{COO}^{-}\]
08

Ions Present in NaCH鈧僀OO Solution

In the case of a \(\mathrm{NaCH}_{3} \mathrm{COO}\) solution, we have sodium ions (\(\mathrm{Na}^{+}\)) and acetate ions (CH鈧僀OO鈦).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dissociation
When ionic compounds dissolve in water, they undergo a process called dissociation. This means that the compound separates into its individual ions. For example, when magnesium iodide (\(\mathrm{MgI}_{2}\)) is placed in water, it breaks up into one magnesium ion (\(\mathrm{Mg}^{2+}\)) and two iodide ions (\(\mathrm{I}^{-}\)).
Dissociation happens because water molecules, which are polar, interact with the ions. The positive end of the water molecule attracts the negatively charged ion, and the negative end attracts the positively charged ion. This interaction helps to pull the ions apart from each other, allowing them to move freely in the solution.
Understanding dissociation is crucial because it explains why ionic compounds can conduct electricity when dissolved in water. **Solutions with dissociated ions are essential in many chemical processes and reactions.**
  • Initiates when ionic compounds are solvated by water molecules.
  • Increases the mobility of ions in a solution.
  • Essential for the electrical conductivity of solutions.
Aqueous Solutions
An aqueous solution is formed when a substance is dissolved in water. **Water is a universal solvent** and can dissolve a wide range of substances due to its polar nature. **This makes it an excellent medium for chemical reactions,** especially those involving ionic compounds.
In the context of ionic compounds, their dissociation in water results in an aqueous solution containing free-moving ions. For instance, aluminum nitrate (\(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\)) dissolves in water to produce aluminum ions (\(\mathrm{Al}^{3+}\)) and nitrate ions (\(\mathrm{NO}_{3}^{-}\)). This solution is termed 'aqueous' because the solvent is water.
Aqueous solutions are particularly important in daily life and industrial applications. They are used in **fields such as medicine, agriculture, and food processing.**
  • Solvent is typically water.
  • Allows ions to move freely, facilitating chemical reactions.
  • Used extensively in various industrial and laboratory processes.
Ions in Solution
Ions present in aqueous solutions are charged particles that result from the dissociation of ionic compounds. When sodium acetate (\(\mathrm{NaCH}_{3} \mathrm{COO}\)) dissolves, it breaks into sodium ions (\(\mathrm{Na}^{+}\)) and acetate ions (\(\mathrm{CH}_{3}\mathrm{COO}^{-}\)). These ions can move freely in the solution.
This characteristic of ions in solution is what allows the solution to conduct electricity. The movement of charged particles (ions) facilitates the flow of electric current. Thus, solutions with a higher concentration of ions have better conductivity.
Additionally, ions in solution participate in chemical reactions. They can recombine to form new compounds, interact with other ions or molecules, and play critical roles in biological systems such as nerve impulse transmission and muscle contraction.
  • Free-moving charged particles in a solution.
  • Enable electrical conductivity in solutions.
  • Participate in various chemical and biological processes.

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Most popular questions from this chapter

Write balanced molecular and net ionic equations for the reactions of (a) hydrochloric acid with nickel, (b) dilute sulfuric acid with iron, (c) hydrobromic acid with magnesium, (d) acetic acid, \(\mathrm{CH}_{3} \mathrm{COOH},\) with zinc.

Federal regulations set an upper limit of 50 parts per million (ppm) of \(\mathrm{NH}_{3}\) in the air in a work environment [that is, 50 molecules of \(\mathrm{NH}_{3}(g)\) for every million molecules in the air]. Air from a manufacturing operation was drawn through a solution containing \(1.00 \times 10^{2} \mathrm{~mL}\) of \(0.0105 \mathrm{M} \mathrm{HCl}\). The \(\mathrm{NH}_{3}\) reacts with \(\mathrm{HCl}\) as follows: $$\mathrm{NH}_{3}(a q)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NH}_{4} \mathrm{Cl}(a q)$$ After drawing air through the acid solution for \(10.0 \mathrm{~min}\) at a rate of \(10.0 \mathrm{~L} / \mathrm{min},\) the acid was titrated. The remaining acid needed \(13.1 \mathrm{~mL}\) of \(0.0588 \mathrm{M} \mathrm{NaOH}\) to reach the equivalence point. (a) How many grams of \(\mathrm{NH}_{3}\) were drawn into the acid solution? (b) How many ppm of \(\mathrm{NH}_{3}\) were in the air? (Air has a density of \(1.20 \mathrm{~g} / \mathrm{L}\) and an average molar mass of \(29.0 \mathrm{~g} / \mathrm{mol}\) under the conditions of the experiment.) (c) Is this manufacturer in compliance with regulations?

A sample of \(5.53 \mathrm{~g}\) of \(\mathrm{Mg}(\mathrm{OH})_{2}\) is added to \(25.0 \mathrm{~mL}\) of 0.200 \(\mathrm{M} \mathrm{HNO}_{3}\) (a) Write the chemical equation for the reaction that occurs. (b) Which is the limiting reactant in the reaction? (c) How many moles of \(\mathrm{Mg}(\mathrm{OH})_{2}, \mathrm{HNO}_{3},\) and \(\mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}\) are present after the reaction is complete?

A \(3.455-\mathrm{g}\) sample of a mixture was analyzed for barium ion by adding a small excess of sulfuric acid to an aqueous solution of the sample. The resultant reaction produced a precipitate of barium sulfate, which was collected by filtration, washed, dried, and weighed. If \(0.2815 \mathrm{~g}\) of barium sulfate was obtained, what was the mass percentage of barium in the sample?

Write balanced molecular and net ionic equations for the reactions of (a) manganese with dilute sulfuric acid, (b) chromium with hydrobromic acid, (c) tin with hydrochloric acid, (d) aluminum with formic acid, HCOOH.

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