/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 96 The total concentration of \(\ma... [FREE SOLUTION] | 91影视

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The total concentration of \(\mathrm{Ca}^{2+}\) and \(\mathrm{Mg}^{2+}\) in a sample of hard water was determined by titrating a \(0.100-\mathrm{L}\) sample of the water with a solution of EDTA \(^{4-}\). The EDTA \(^{4-}\) chelates the two cations: $$ \begin{aligned} \mathrm{Mg}^{2+}+[\mathrm{EDTA}]^{4-} \longrightarrow &[\mathrm{Mg}(\mathrm{EDTA})]^{2-} \\ \mathrm{Ca}^{2+}+[\mathrm{EDTA}]^{4-} \longrightarrow &[\mathrm{Ca}(\mathrm{EDTA})]^{2-} \end{aligned} $$ It requires \(31.5 \mathrm{~mL}\) of \(0.0104 \mathrm{M}[\mathrm{EDTA}]^{4-}\) solution to reach the end point in the titration. A second \(0.100-\mathrm{L}\) sample was then treated with sulfate ion to precipitate \(\mathrm{Ca}^{2+}\) as calcium sulfate. The \(\mathrm{Mg}^{2+}\) was then titrated with \(18.7 \mathrm{~mL}\) of \(0.0104 \mathrm{M}\) \([\mathrm{EDTA}]^{4-},\) Calculate the concentrations of \(\mathrm{Mg}^{2+}\) and \(\mathrm{Ca}^{2+}\) in the hard water in \(\mathrm{mg} / \mathrm{L}\).

Short Answer

Expert verified
The concentrations of Ca虏鈦 and Mg虏鈦 in the hard water sample are 52.9 mg/L and 47.1 mg/L, respectively.

Step by step solution

01

Determine the total amount of moles reacted with EDTA in the first titration

In the first titration, 0.100 L of the sample was titrated with 31.5 mL of 0.0104 M EDTA鈦粹伝 solution. We will convert volume and concentration to moles by using the formula: Moles of EDTA鈦粹伝 = Volume of EDTA鈦粹伝 solution (L) 脳 Molarity of EDTA鈦粹伝 solution (mol/L) Moles of EDTA鈦粹伝 = 0.0315 L 脳 0.0104 mol/L = \(3.26 \times 10^{-4}\) mol Both Ca虏鈦 and Mg虏鈦 react with EDTA鈦粹伝 in a 1:1 molar ratio, so the total moles reacted with EDTA鈦粹伝 in the first titration will be \(3.26 \times 10^{-4}\) mol.
02

Determine the amount of moles of Mg虏鈦 left in the second titration

In the second titration, 0.100 L of the sample was titrated with 18.7 mL of 0.0104 M EDTA鈦粹伝 solution after precipitating Ca虏鈦 as calcium sulfate. We will similarly convert the volume and concentration to moles. Moles of EDTA鈦粹伝 = Volume of EDTA鈦粹伝 solution (L) 脳 Molarity of EDTA鈦粹伝 solution (mol/L) Moles of EDTA鈦粹伝 = 0.0187 L 脳 0.0104 mol/L = \(1.94 \times 10^{-4}\) mol Since Mg虏鈦 reacts with EDTA鈦粹伝 in a 1:1 molar ratio, the moles of Mg虏鈦 in the second titration will be \(1.94 \times 10^{-4}\) mol.
03

Calculate the moles and concentration of Ca虏鈦 and Mg虏鈦

From the information obtained in the previous steps, we can now calculate the moles of Ca虏鈦 and Mg虏鈦 separately. Moles of Ca虏鈦 = Total moles in the first titration - Moles of Mg虏鈦 in the second titration Moles of Ca虏鈦 = \(3.26 \times 10^{-4}\) mol - \(1.94 \times 10^{-4}\) mol = \(1.32 \times 10^{-4}\) mol Now we will calculate the molar concentrations of both ions in the sample: Concentration of Ca虏鈦 = Moles of Ca虏鈦 / Volume of sample (L) = \(\frac{1.32 \times 10^{-4}\, \text{mol}}{0.100 \, \text{L}}\) = \(1.32 \times 10^{-3}\) M Concentration of Mg虏鈦 = Moles of Mg虏鈦 / Volume of sample (L) = \(\frac{1.94 \times 10^{-4}\, \text{mol}}{0.100 \, \text{L}}\) = \(1.94 \times 10^{-3}\) M
04

Convert concentrations to mg/L

We will use molar mass to convert the concentrations of Ca虏鈦 and Mg虏鈦 to mg/L. Molar mass of Ca虏鈦 = 40.08 g/mol Molar mass of Mg虏鈦 = 24.30 g/mol Concentration of Ca虏鈦 (mg/L) = Concentration of Ca虏鈦 (M) 脳 Molar mass of Ca虏鈦 (g/mol) 脳 1000 (to convert g to mg) Concentration of Ca虏鈦 (mg/L) = \(1.32 \times 10^{-3} \frac{\text{mol}}{\text{L}}\) 脳 40.08 g/mol 脳 1000 = 52.9 mg/L Concentration of Mg虏鈦 (mg/L) = Concentration of Mg虏鈦 (M) 脳 Molar mass of Mg虏鈦 (g/mol) 脳 1000 (to convert g to mg) Concentration of Mg虏鈦 (mg/L) = \(1.94 \times 10^{-3} \frac{\text{mol}}{\text{L}}\) 脳 24.30 g/mol 脳 1000 = 47.1 mg/L The concentrations of Ca虏鈦 and Mg虏鈦 in the hard water sample are 52.9 mg/L and 47.1 mg/L, respectively.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hard Water Analysis
Analysis of hard water involves determining the presence and concentration of cations, primarily calcium (Ca2+) and magnesium (Mg2+), responsible for water hardness. Water is considered 'hard' when it has a high mineral content, which can lead to scaling in pipes and inefficiency in soaps and detergents. In our exercise, the total concentration of these cations was assessed using a titration method with a chelating agent, EDTA4-, which forms complexes with the cations.

To enhance understanding of water hardness, it's meaningful to discuss the source of these minerals; they generally enter the water supply by dissolving from minerals like limestone or dolomite as water percolates through the ground. The hardness can be temporary, caused by bicarbonate minerals that precipitate when heated, or permanent, from sulfate or chloride minerals that do not. The exercise focuses on the total hardness, which is a combined measure of both.

When evaluating the quality of water for domestic or industrial use, knowledge of water hardness is crucial. Softening of hard water is common, and understanding the precise levels of calcium and magnesium is essential for determining the appropriate treatment process.
Complexometric Titration
Complexometric titration, a key concept in our exercise, is a form of volumetric analysis where a solution (titrant) with a known concentration is used to determine the unknown concentration of a metal ion in a sample. This titration employs a complexing agent, such as EDTA4-, that forms a stable, water-soluble complex with metal ions.

In complexometric titration, the point at which the titrant has completely reacted with the ion of interest is known as the endpoint. This is often detected with the help of an indicator that changes color when the reaction is complete, or by instruments measuring changes in the solution's properties. In the context of our exercise, the color change might not be visible, hence students could understand that techniques such as a pH meter or conductivity meter might have been used to detect the endpoint.

Complexometric titrations are highly accurate and can selectively determine one type of ion in the presence of others. The technique is widely used in areas such as water hardness analysis, pharmaceutical and food industries for quality control, and in clinical laboratories for blood serum analyses.
Cation Concentration Calculation
The calculation of cation concentration following a titration process is critical for quantifying specific ions in a solution, as in our hard water example. The exercise demonstrates the determination of calcium and magnesium ion concentrations in a water sample using EDTA titration.

The calculation begins with the titration data to determine the moles of EDTA required to react with the cations in the water sample. With the assumption that EDTA reacts in a 1:1 molar ratio with both Ca2+ and Mg2+, we can ascertain the total moles of ions present. Following the titration steps, the concentration (in moles per liter) is calculated by dividing the moles of each ion by the volume of the water sample.

However, expressing these concentrations in mg/L is more practical for comparison to water quality standards. Thus, we convert molarity to mg/L using the molar mass of each ion, providing a clear view of the hardness level of the water. From a practical standpoint, students may benefit from knowing that these concentrations help in formulating water softening treatments and assessing compliance with environmental regulations.

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Most popular questions from this chapter

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