/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 A cell has a standard cell poten... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A cell has a standard cell potential of \(+0.177 \mathrm{~V}\) at \(298 \mathrm{~K}\). What is the value of the equilibrium constant for the reaction (a) if \(n=1 ?(\mathbf{b})\) if \(n=2 ?(\mathbf{c})\) if \(n=3 ?\)

Short Answer

Expert verified
For a cell with a standard cell potential of \(+0.177 V\) at \(298 K\), the equilibrium constants for different values of the number of electrons transferred (n) are: a) n=1: \(K \approx 1871\) b) n=2: \(K \approx 3.494\times10^6\) c) n=3: \(K \approx 6.532\times10^{9}\)

Step by step solution

01

Rearrange the Nernst Equation

We need to isolate K in the Nernst equation, so first rearrange it as: \( K = e^\frac{nFE_\text{cell}}{RT} \) Now we can plug in the given values and constants to find K for each case.
02

Case a (n=1)

Insert the given values and constants with n=1: \( K = e^\frac{(1)(96485 C/mol)(0.177 V)}{(8.314 J/mol K)(298 K)} \) Calculate the equilibrium constant (K) for n=1: \(K = e^{7.529}\) \(K \approx 1871\)
03

Case b (n=2)

Insert the given values and constants with n=2: \( K = e^\frac{(2)(96485 C/mol)(0.177 V)}{(8.314 J/mol K)(298 K)} \) Calculate the equilibrium constant (K) for n=2: \(K = e^{15.058}\) \(K \approx 3.494\times10^6 \)
04

Case c (n=3)

Insert the given values and constants with n=3: \( K = e^\frac{(3)(96485 C/mol)(0.177 V)}{(8.314 J/mol K)(298 K)} \) Calculate the equilibrium constant (K) for n=3: \(K = e^{22.587}\) \(K \approx 6.532\times10^{9}\) In summary, the equilibrium constants for the different values of n are: a) n=1: \(K \approx 1871\) b) n=2: \(K \approx 3.494\times10^6\) c) n=3: \(K \approx 6.532\times10^{9}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nernst Equation
The Nernst equation is a fundamental formula in electrochemistry that relates the reduction potential of a chemical reaction to the concentration of the reactants and products. Understanding the Nernst equation is crucial when dealing with electrochemical cells and predicting the direction in which a reaction will proceed.

At its core, the equation gives us a way to calculate the potential of an electrochemical cell under non-standard conditions. It is expressed as:
\[ E = E^\circ - \frac{RT}{nF} \ln(Q) \]
Where:
  • \(E\) is the cell potential at non-standard conditions,
  • \(E^\circ\) is the standard cell potential,
  • \(R\) is the universal gas constant,
  • \(T\) is the temperature in Kelvin,
  • \(n\) is the number of moles of electrons exchanged,
  • \(F\) is the Faraday's constant,
  • \(Q\) is the reaction quotient.
The equation becomes particularly simple when conditions are at equilibrium, as the cell potential (\(E\)) becomes zero, and \(Q\) is replaced with the equilibrium constant (\(K\)). Thus, the equation is modified to calculate \(K\), relating the standard cell potential directly to the equilibrium constant of the reaction.
Standard Cell Potential
Standard cell potential (\(E^\circ\)) is a measure of how forcefully an electrochemical cell can push electrons through a circuit under standard conditions. These standard conditions usually involve all solutes being at 1 M concentration and gases at 1 bar pressure, with the temperature typically at 298 K (25°C).

The value of \(E^\circ\) is significant in determining the natural tendency for a reaction to occur. A positive standard cell potential indicates a spontaneous reaction under standard conditions, while a negative value implies a non-spontaneous reaction.

In the given exercise, the standard cell potential is marked as positive (+0.177 V), making it a crucial factor in predicting the spontaneity of the reaction and, therefore, its equilibrium constant, as we can see in the Nernst equation.
Chemical Equilibrium
Chemical equilibrium represents the state in a chemical reaction where the rates of the forward and reverse reactions are equal, resulting in no net change in the concentration of the reactants and products. The position of the equilibrium, reflected in the equilibrium constant (\(K\)), tells us the extent to which a reaction will occur before reaching this state.

The equilibrium constant is calculated from the concentrations of the reactants and products at equilibrium. For a generic reaction \(aA + bB ⇌ cC + dD\), the equilibrium constant expression is written as:
\[ K = \frac{[C]^c[D]^d}{[A]^a[B]^b} \]
Where the square brackets denote the concentration of each species. In the context of electrochemistry, when considering a redox reaction, the standard cell potential gives us insight into the equilibrium constant without needing the concentration of individual species. The higher the value of \(K\), the more products are favored, as seen above where \(K\) increases with the number of moles of electrons exchanged.
Electrochemistry
Electrochemistry is a branch of chemistry that deals with the interrelation of electrical currents and chemical reactions. Two primary devices used in this field are electrochemical cells, which convert chemical energy into electrical energy, and electrolytic cells, which do the opposite. Within an electrochemical context, the standard cell potential and the equilibrium constant play pivotal roles in determining the feasibility and extent of chemical reactions.

An understanding of electrochemistry is not complete without a grasp of how the Nernst equation and the standard cell potential relate to the equilibrium of chemical reactions. By using our knowledge of these concepts, we can control and predict the outcomes of a myriad of processes, from the simple batteries that power our everyday devices to the complex reactions that occur in biological systems.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Calculate the mass of Li formed by electrolysis of molten LiCl by a current of \(7.5 \times 10^{4}\) A flowing for a period of \(24 \mathrm{~h}\). Assume the electrolytic cell is \(85 \%\) efficient. (b) What is the minimum voltage required to drive the reaction?

The capacity of batteries such as the typical AA alkaline battery is expressed in units of milliamp-hours (mAh). An AA alkaline battery yields a nominal capacity of \(2850 \mathrm{mAh}\). (a) What quantity of interest to the consumer is being expressed by the units of \(\mathrm{mAh} ?\) (b) The starting voltage of a fresh alkaline battery is \(1.55 \mathrm{~V}\). The voltage decreases during discharge and is \(0.80 \mathrm{~V}\) when the battery has delivered its rated capacity. If we assume that the voltage declines linearly as current is withdrawn, estimate the total maximum electrical work the battery could perform during discharge.

The Haber process is the principal industrial route for converting nitrogen into ammonia: $$\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)$$ (a) What is being oxidized, and what is being reduced? (b) Using the thermodynamic data in Appendix \(\mathrm{C}\), calculate the equilibrium constant for the process at room temperature. (c) Calculate the standard emf of the Haber process at room temperature.

A voltaic cell consists of a strip of cadmium metal in a solution of \(\mathrm{Cd}\left(\mathrm{NO}_{3}\right)_{2}\) in one beaker, and in the other beaker a platinum electrode is immersed in a \(\mathrm{NaCl}\) solution, with \(\mathrm{Cl}_{2}\) gas bubbled around the electrode. A salt bridge connects the two beakers. (a) Which electrode serves as the anode and which as the cathode? (b) Does the Cd electrode gain or lose mass as the cell reaction proceeds? (c) Write the equation for the overall cell reaction. (d) What is the emf generated by the cell under standard conditions?

(a) What happens to the emf of a battery as it is used? Why does this happen? (b) The AA-size and D-size alkaline batteries are both \(1.5-\mathrm{V}\) batteries that are based on the same electrode reactions. What is the major difference between the two batteries? What performance feature is most affected by this difference?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.