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Explain the following observations: (a) \(\mathrm{HNO}_{3}\) is a stronger acid than \(\mathrm{HNO}_{2} ;\) (b) \(\mathrm{H}_{2} \mathrm{~S}\) is a stronger acid than \(\mathrm{H}_{2} \mathrm{O} ;(\mathrm{c})\) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) is a stronger acid than \(\mathrm{HSO}_{4}^{-} ;\) (d) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) is a stronger acid than \(\mathrm{H}_{2} \mathrm{SeO}_{4}\) (e) \(\mathrm{CCl}_{3} \mathrm{COOH}\) is a stronger acid than \(\mathrm{CH}_{3} \mathrm{COOH}\)

Short Answer

Expert verified
(a) HNO鈧 is a stronger acid than HNO鈧 because its conjugate base (NO鈧冣伝) is more stable due to the delocalization of the negative charge. (b) H鈧係 is a stronger acid than H鈧侽 because sulfur is less electronegative than oxygen, making the H-S bond weaker and easier to break. (c) H鈧係O鈧 is a stronger acid than HSO鈧勨伝 because the negative charge on HSO鈧勨伝 reduces its overall stability. (d) H鈧係O鈧 is a stronger acid than H鈧係eO鈧 due to sulfur being more electronegative than selenium, making the S-O bond more polar. (e) CCl鈧僀OOH is a stronger acid than CH鈧僀OOH since the CCl鈧 group is an electron-withdrawing group, increasing the stability of the conjugate base (CCl鈧僀OO鈦).

Step by step solution

01

Observation (a)

HNO鈧 is a stronger acid than HNO鈧: The acidity of an acid depends on the stability of the conjugate base that forms after losing a hydrogen ion. In this case, the conjugate bases are NO鈧冣伝 and NO鈧傗伝. The more stable the conjugate base, the stronger the acid. In case of HNO鈧, the negative charge is delocalized on the nitrate ion (NO鈧冣伝), which provides greater stability to the conjugate base. In the case of HNO鈧, the negative charge is localized on the nitrite ion (NO鈧傗伝), making it less stable. Therefore, HNO鈧 is a stronger acid than HNO鈧.
02

Observation (b)

H鈧係 is a stronger acid than H鈧侽: The acidic strength of a compound depends on the electronegativity of the central atom and the ease of breaking the H-X bond (X being the central atom). In both cases, the central atom is from group 16 (oxygen in H鈧侽 and sulfur in H鈧係). Sulfur is less electronegative than oxygen, making the H-S bond weaker and easier to break compared to the H-O bond in H鈧侽. As a result, H鈧係 is a stronger acid than H鈧侽.
03

Observation (c)

H鈧係O鈧 is a stronger acid than HSO鈧勨伝: In this case, we compare the acidic strength of a molecule and its conjugate base. When H鈧係O鈧 loses a proton, it forms HSO鈧勨伝. The acidic strength is directly related to the stability of the formed conjugate base after losing the proton. The negative charge on the HSO鈧勨伝 ion reduces the overall stability compared to H鈧係O鈧. Therefore, H鈧係O鈧 is a stronger acid than HSO鈧勨伝.
04

Observation (d)

H鈧係O鈧 is a stronger acid than H鈧係eO鈧: H鈧係O鈧 and H鈧係eO鈧 are both oxyacids, consisting of a central atom (sulfur in H鈧係O鈧, and selenium in H鈧係eO鈧) surrounded by oxygen atoms. The electronegativity difference between the central atom and oxygen determines the acidic strength. Sulfur is more electronegative than selenium, making the S-O bond more polar than the Se-O bond. Consequently, H鈧係O鈧 is a stronger acid than H鈧係eO鈧.
05

Observation (e)

CCl鈧僀OOH is a stronger acid than CH鈧僀OOH: The acidity of carboxylic acids depends on the inductive effect of the substituent atoms/groups. The inductive effect is the electron-withdrawing or electron-donating property of a substituent group that influences the acidity of the carboxylic acid. The CCl鈧 group in CCl鈧僀OOH is an electron-withdrawing group due to the high electronegativity of Cl atoms, releasing the negative charge on the conjugate base (CCl鈧僀OO鈦) and increasing the stability. In CH鈧僀OOH, the methyl group (CH鈧) has a weaker electron-withdrawing effect, which leads to a less stable conjugate base (CH鈧僀OO鈦). Therefore, CCl鈧僀OOH is a stronger acid than CH鈧僀OOH.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conjugate base stability
Acidity is closely connected to the stability of the conjugate base formed after an acid donates a proton. The more stable the conjugate base, the stronger the acid tends to be. For example, when comparing \( \mathrm{HNO}_3 \) and \( \mathrm{HNO}_2 \), we look at their respective conjugate bases, \( \mathrm{NO}_3^- \) and \( \mathrm{NO}_2^- \). In \( \mathrm{HNO}_3 \), the conjugal base is \( \mathrm{NO}_3^- \), which can evenly share the negative charge between the atoms, making it highly stable. In contrast, \( \mathrm{NO}_2^- \) has localized charge, making it less stable. Therefore, \( \mathrm{HNO}_3 \) is a stronger acid. In summary, if the conjugate base can delocalize or spread the negative charge, it contributes to the acid's strength.
Electronegativity
Electronegativity is the ability of an atom to attract electrons toward itself. This factor plays a crucial role in determining the acidity of a compound. For instance, consider \( \mathrm{H}_2 \mathrm{S} \) and \( \mathrm{H}_2 \mathrm{O} \). Both have central atoms from group 16鈥攕ulfur and oxygen. Electronegativity affects the bond strength between hydrogen and the central atom. Sulfur has a lower electronegativity compared to oxygen, leading to a weaker \( \mathrm{H}-\mathrm{S} \) bond. A weaker bond means that hydrogen ions can be released easily, making \( \mathrm{H}_2 \mathrm{S} \) a stronger acid than \( \mathrm{H}_2 \mathrm{O} \). Thus, the central atom's electronegativity influences how readily an acid releases protons.
Inductive effect
The inductive effect is an essential concept in understanding acidity, especially in organic molecules. It refers to the ability of an atom or group to either withdraw or donate electron density through sigma bonds.The inductive effect impacts the stability of the conjugate base. Let's examine \( \mathrm{CCl}_3 \mathrm{COOH} \) and \( \mathrm{CH}_3 \mathrm{COOH} \). The \( \mathrm{CCl}_3 \) group is highly electron-withdrawing due to the electronegative chlorine atoms, stabilizing the resulting conjugate base \( \mathrm{CCl}_3 \mathrm{COO}^- \) by dispersing the negative charge. Conversely, the \( \mathrm{CH}_3 \) group in \( \mathrm{CH}_3 \mathrm{COOH} \) is electron-donating, leading to a less stable conjugate base \( \mathrm{CH}_3 \mathrm{COO}^- \).Hence, the inductive effect can help predict and explain the relative strengths of different acids.
Oxyacids
Oxyacids are a class of acids that contain a central atom bonded to oxygen. The acidity of oxyacids often depends on the central atom's electronegativity and the number of oxygen atoms connected to it. For example, consider \( \mathrm{H}_2 \mathrm{SO}_4 \) and \( \mathrm{H}_2 \mathrm{SeO}_4 \). Sulfur is more electronegative than selenium, making the \( \mathrm{S}-\mathrm{O} \) bonds in sulfuric acid more polar. More polar bonds potentially release protons more easily, enhancing the acid's strength. Additionally, more oxygen atoms can delocalize the negative charge over a larger volume, increasing conjugate base stability. Thus, \( \mathrm{H}_2 \mathrm{SO}_4 \) is a stronger acid than \( \mathrm{H}_2 \mathrm{SeO}_4 \). When analyzing oxyacids, consider these factors to evaluate and compare their acidity.

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Most popular questions from this chapter

Phenylacetic acid \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{COOH}\right)\) is one of the substances that accumulates in the blood of people with phenylketonuria, an inherited disorder that can cause mental retardation or even death. A \(0.085 \mathrm{M}\) solution of \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{COOH}\) has a \(\mathrm{pH}\) of \(2.68 .\) Calculate the \(K_{a}\) value for this acid.

Based on their compositions and structures and on conjugate acid-base relationships, select the stronger base in each of the following pairs: (a) \(\mathrm{BrO}^{-}\) or \(\mathrm{ClO}^{-},\) (b) \(\mathrm{BrO}^{-}\) or \(\mathrm{BrO}_{2}^{-},(\mathbf{c})\) \(\mathrm{HPO}_{4}^{2-}\) or \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\)

Codeine \(\left(\mathrm{C}_{18} \mathrm{H}_{21} \mathrm{NO}_{3}\right)\) is a weak organic base. A \(5.0 \times 10^{-3} \mathrm{M}\) solution of codeine has a \(\mathrm{pH}\) of \(9.95 .\) Calculate the value of \(K_{b}\) for this substance. What is the \(\mathrm{p} K_{b}\) for this base?

(a) What is the difference between the Arrhenius and the Bronsted-Lowry definitions of an acid? (b) \(\mathrm{NH}_{3}(g)\) and \(\mathrm{HCl}(g)\) react to form the ionic solid \(\mathrm{NH}_{4} \mathrm{Cl}(s) .\) Which substance is the Bronsted-Lowry acid in this reaction? Which is the Bronsted-Lowry base?

The odor of fish is due primarily to amines, especially methylamine \(\left(\mathrm{CH}_{3} \mathrm{NH}_{2}\right)\). Fish is often served with a wedge of lemon, which contains citric acid. The amine and the acid react forming a product with no odor, thereby making the lessthan-fresh fish more appetizing. Using data from Appendix \(D\), calculate the equilibrium constant for the reaction of citric acid with methylamine, if only the first proton of the citric acid \(\left(K_{a 1}\right)\) is important in the neutralization reaction.

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