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Write the chemical equation and the \(K_{b}\) expression for the reaction of each of the following bases with water: (a) dimethylamine, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH} ;\) (b) carbonate ion, \(\mathrm{CO}_{3}^{2-} ;(\mathbf{c})\) formate ion, \(\mathrm{CHO}_{2}^{-}\).

Short Answer

Expert verified
(a) The chemical equation for the reaction of dimethylamine with water is: \[ (\mathrm{CH}_{3})_{2}\mathrm{NH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons (\mathrm{CH}_{3})_{2}\mathrm{NH}_2^+ + \mathrm{OH}^- \] The \(K_b\) expression for the reaction is: \[ K_b = \frac{[(\mathrm{CH}_{3})_{2}\mathrm{NH}_2^+][\mathrm{OH}^-]}{[(\mathrm{CH}_{3})_{2}\mathrm{NH}]} \] (b) The chemical equation for the reaction of carbonate ion with water is: \[ \mathrm{CO}_{3}^{2-} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{HCO}_{3}^- + \mathrm{OH}^- \] The \(K_b\) expression for the reaction is: \[ K_b = \frac{[\mathrm{HCO}_{3}^-][\mathrm{OH}^-]}{[\mathrm{CO}_{3}^{2-}]} \] (c) The chemical equation for the reaction of formate ion with water is: \[ \mathrm{CHO}_{2}^- + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{HCHO}_2 + \mathrm{OH}^- \] The \(K_b\) expression for the reaction is: \[ K_b = \frac{[\mathrm{HCHO}_2][\mathrm{OH}^-]}{[\mathrm{CHO}_{2}^{-}]} \]

Step by step solution

01

Write the chemical equation for dimethylamine with water

The reaction between dimethylamine and water is given by: \[ (\mathrm{CH}_{3})_{2}\mathrm{NH} + \mathrm{H}_2\mathrm{O} \rightleftharpoons (\mathrm{CH}_{3})_{2}\mathrm{NH}_2^+ + \mathrm{OH}^- \]
02

Write the \(K_b\) expression for dimethylamine reaction

The \(K_b\) expression is given by the ratio of the concentrations of the products to the concentration of the reactants after equilibrium: \[ K_b = \frac{[(\mathrm{CH}_{3})_{2}\mathrm{NH}_2^+][\mathrm{OH}^-]}{[(\mathrm{CH}_{3})_{2}\mathrm{NH}]} \] (b) Carbonate ion, \(\mathrm{CO}_{3}^{2-}\)
03

Write the chemical equation for carbonate ion with water

The reaction between carbonate ion and water is given by: \[ \mathrm{CO}_{3}^{2-} + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{HCO}_{3}^- + \mathrm{OH}^- \]
04

Write the \(K_b\) expression for carbonate ion reaction

The \(K_b\) expression is given by the ratio of the concentrations of the products to the concentration of the reactants after equilibrium: \[ K_b = \frac{[\mathrm{HCO}_{3}^-][\mathrm{OH}^-]}{[\mathrm{CO}_{3}^{2-}]} \] (c) Formate ion, \(\mathrm{CHO}_{2}^{-}\)
05

Write the chemical equation for formate ion with water

The reaction between formate ion and water is given by: \[ \mathrm{CHO}_{2}^- + \mathrm{H}_2\mathrm{O} \rightleftharpoons \mathrm{HCHO}_2 + \mathrm{OH}^- \]
06

Write the \(K_b\) expression for formate ion reaction

The \(K_b\) expression is given by the ratio of the concentrations of the products to the concentration of the reactants after equilibrium: \[ K_b = \frac{[\mathrm{HCHO}_2][\mathrm{OH}^-]}{[\mathrm{CHO}_{2}^{-}]} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
Understanding chemical equilibrium is critical for studying reactions like the ionization of bases in water. Equilibrium refers to the state when the rate of the forward reaction, where reactants are converted into products, is equal to the rate of the reverse reaction, in which products revert back to reactants. At this point, the concentrations of all reactants and products remain constant over time, creating what we call a dynamic balance.

For instance, when dimethylamine reacts with water, it reaches a point where the formation of its ionized products progresses at the same rate as their recombination into dimethylamine and water. Recognizing this balance is crucial for predicting how the reaction will behave under different conditions and for calculating the concentrations of the substances involved.
Equilibrium Constant Expression
Each chemical equilibrium has a numerical value associated with it known as the equilibrium constant. This number, represented by the symbols \(K_c\) for concentrations or \(K_p\) for partial pressures, depends only on the temperature of the reaction.

The base ionization constant (\(K_b\)) is a special type of equilibrium constant that applies to the reaction of bases with water. It reflects the extent of ionization, a vital concept when dealing with weak bases such as dimethylamine, carbonate ion, and formate ion. The expression for \(K_b\) is derived from the general equilibrium constant expression, where the concentration of each product is multiplied together and then divided by the product of the concentrations of each reactant, with each raised to the power of their stoichiometric coefficient. In each case from the exercise, the concentrations of ionized products and the original base are used in the \(K_b\) expression to gauge the base's strength in water.
Acid-Base Reactions
Acid-base reactions are pivotal in chemistry, often involving the transfer of a proton (\(H^+\)) from an acid to a base. In the context of base ionization in water, we refer to the reaction between a base and water to produce hydroxide ions (\(\text{OH}^-\)) and the conjugate acid of the base.

For example, when dimethylamine reacts with water, it accepts a proton from water, forming its conjugate acid and releasing hydroxide ions into the solution. This process of accepting a proton is characteristic of a base. Each of the substances in the exercise (dimethylamine, carbonate ion, and formate ion) behaves as a base, taking a proton from water and contributing to the pH of the solution through the production of hydroxide ions.
Hydrolysis of Ions
The hydrolysis of ions refers to the reaction of ions with water to form new ions and sometimes neutral molecules. It is a type of acid-base reaction where ions can act as acids or bases. Anions (negatively charged ions) often undergo hydrolysis to form a base, as seen with the carbonate (\(\text{CO}_3^{2-}\)) and formate (\(\text{CHO}_2^-\)) ions in our exercise.

In the case of the carbonate ion, it reacts with water to produce bicarbonate (\(\text{HCO}_3^-\)) and \(\text{OH}^-\), demonstrating its basic nature by increasing the concentration of hydroxide ions in the solution. This behavior influences the pH of the solution and the overall reactivity of the ions in different chemical contexts. Thus, understanding hydrolysis is essential when predicting the outcome of reactions in aqueous solutions and interpreting changes in the pH of the environment.

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Most popular questions from this chapter

(a) Write a chemical equation that illustrates the autoionization of water. (b) Write the expression for the ion-product constant for water, \(K_{w}\). Why is \(\left[\mathrm{H}_{2} \mathrm{O}\right]\) absent from this expression? (c) A solution is described as basic. What does this statement mean?

Predict which member of each pair produces the more acidic aqueous solution: (a) \(\mathrm{K}^{+}\) or \(\mathrm{Cu}^{2+},(\mathrm{b}) \mathrm{Fe}^{2+}\) or \(\mathrm{Fe}^{3+},(\mathrm{c}) \mathrm{Al}^{3+}\) or \(\mathrm{Ga}^{3+} .\) Explain.

Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the equation: (a) \(\mathrm{NH}_{4}{ }^{+}(a q)+\mathrm{OH}^{-}(a q) \rightleftharpoons\) (b) \(\mathrm{CH}_{3} \mathrm{COO}^{-}(a q)+\mathrm{H}_{3} \mathrm{O}^{+}(a q) \rightleftharpoons\) (c) \(\mathrm{HCO}_{3}^{-}(a q)+\mathrm{F}^{-}(a q) \rightleftharpoons\)

The structural formula for acetic acid is shown in Table 16.2 . Replacing hydrogen atoms on the carbon with chlorine atoms causes an increase in acidity, as follows: $$ \begin{array}{lll} \hline \text { Acid } & \text { Formula } & \boldsymbol{K}_{\boldsymbol{a}}\left(\mathbf{2 5}^{\circ} \mathbf{C}\right) \\\ \hline \text { Acetic } & \mathrm{CH}_{3} \mathrm{COOH} & 1.8 \times 10^{-5} \\\ \text {Chloroacetic } & \mathrm{CH}_{2} \mathrm{ClCOOH} & 1.4 \times 10^{-3} \\\ \text {Dichloroacetic } & \mathrm{CHCl}_{2} \mathrm{COOH} & 3.3 \times 10^{-2} \\\ \text {Trichloroacetic } & \mathrm{CCl}_{3} \mathrm{COOH} & 2 \times 10^{-1} \\\ \hline \end{array} $$ Using Lewis structures as the basis of your discussion, explain the observed trend in acidities in the series. Calculate the \(\mathrm{pH}\) of a \(0.010 \mathrm{M}\) solution of each acid.

The hypochlorite ion, \(\mathrm{ClO}^{-},\) acts as a weak base. (a) Is \(\mathrm{ClO}^{-}\) a stronger or weaker base than hydroxylamine? (b) When ClO \(^{-}\) acts as a base, which atom, Cl or \(\mathrm{O}\), acts as the proton acceptor? (c) Can you use formal charges to rationalize your answer to part (b)?

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