/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 76 What is the freezing point of an... [FREE SOLUTION] | 91Ó°ÊÓ

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What is the freezing point of an aqueous solution that boils at \(105.0^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
The freezing point of the aqueous solution that boils at \(105.0^{\circ}\mathrm{C}\) is approximately \(-18.17^{\circ}\mathrm{C}\).

Step by step solution

01

Determine the boiling point elevation of the solution.

The boiling point elevation, ΔTb, can be found by subtracting the normal boiling point of the solvent (water) from the boiling point of the solution: ΔTb = Tb - Tb,water In this case, the boiling point of water is \(100^{\circ}\mathrm{C}\). So: ΔTb = \(105.0^{\circ}\mathrm{C}\) - \(100^{\circ}\mathrm{C}\) = \(5^{\circ}\mathrm{C}\).
02

Find the molality of the solute in the solution.

The boiling point elevation formula is given by: ΔTb = Kb * molality Where Kb is the ebullioscopic constant, which for water is 0.512 \(^{\circ}\mathrm{C/m}\). Rearranging the equation and plugging in the values, we get: molality = ΔTb / Kb = \(\frac{5^{\circ}\mathrm{C}}{0.512^{\circ}\mathrm{C/m}}\) = 9.7656 m
03

Determine the freezing point depression of the solution.

The freezing point depression formula is given by: ΔTf = Kf * molality Where Kf is the cryoscopic constant, which for water is 1.86 \(^{\circ}\mathrm{C/m}\). Plugging in the values, we get: ΔTf = 1.86 \(^{\circ}\mathrm{C/m}\) * 9.7656 m = 18.1656 \(^{\circ}\mathrm{C}\)
04

Find the freezing point of the aqueous solution.

The freezing point of the solution can be found by subtracting the freezing point depression from the normal freezing point of the solvent (water). In this case, the freezing point of water is \(0^{\circ}\mathrm{C}\). So: Freezing point of the solution = Tf,water - ΔTf Freezing point of the solution = \(0^{\circ}\mathrm{C}\) - 18.1656 \(^{\circ}\mathrm{C}\) = \(-18.1656^{\circ}\mathrm{C}\) The freezing point of the aqueous solution that boils at \(105.0^{\circ}\mathrm{C}\) is approximately \(-18.17^{\circ}\mathrm{C}\).

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Most popular questions from this chapter

The maximum allowable concentration of lead in drinking water is \(9.0 \mathrm{ppb}\). (a) Calculate the molarity of lead in a 9.0-ppb solution. What assumption did you have to make in your calculation? (b) How many grams of lead are in a swimming pool containing 9.0 ppb lead in \(60 \mathrm{~m}^{3}\) of water?

The following table presents the solubilities of several gases in water at \(25^{\circ} \mathrm{C}\) under a total pressure of gas and water vapor of 1 atm. (a) What volume of \(\mathrm{CH}_{4}(g)\) under standard conditions of temperature and pressure is contained in \(4.0 \mathrm{~L}\) of a saturated solution at \(25^{\circ} \mathrm{C} ?\) (b) Explain the variation in solubility among the hydrocarbons listed (the first three compounds), based on their molecular structures and intermolecular forces. (c) Compare the solubilities of \(\mathrm{O}_{2}, \mathrm{~N}_{2}\), and \(\mathrm{NO},\) and account for the variations based on molecular structures and intermolecular forces. (d) Account for the much larger values observed for \(\mathrm{H}_{2} \mathrm{~S}\) and \(\mathrm{SO}_{2}\) as compared with the other gases listed. (e) Find several pairs of substances with the same or nearly the same molecular masses (for example, \(\mathrm{C}_{2} \mathrm{H}_{4}\) and \(\mathrm{N}_{2}\) ), and use intermolecular interactions to explain the differences in their solubilities. $$ \begin{array}{lc} \hline \text { Gas } & \text { Solubility }(\mathrm{m} M) \\ \hline \mathrm{CH}_{4}(\text { methane }) & 1.3 \\ \mathrm{C}_{2} \mathrm{H}_{6} \text { (ethane) } & 1.8 \\ \mathrm{C}_{2} \mathrm{H}_{4} \text { (ethylene) } & 4.7 \\ \mathrm{~N}_{2} & 0.6 \\ \mathrm{O}_{2} & 1.2 \\ \mathrm{NO} & 1.9 \\ \mathrm{H}_{2} \mathrm{~S} & 99 \\ \mathrm{SO}_{2} & 1476 \end{array} $$

(a) In Equation 13.1 which of the enthalpy terms for dissolving an ionic solid would correspond to the lattice energy? (b) Which energy term in this equation is always exothermic?

Commercial aqueous nitric acid has a density of \(1.42 \mathrm{~g} / \mathrm{mL}\) and is 16 M. Calculate the percent \(\mathrm{HNO}_{3}\) by mass in the solution.

At \(35^{\circ} \mathrm{C}\) the vapor pressure of acetone, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO},\) is 360 torr, and that of chloroform, \(\mathrm{CHCl}_{3}\), is 300 torr. Acetone and chloroform can form very weak hydrogen bonds between one another as follows: A solution composed of an equal number of moles of acetone and chloroform has a vapor pressure of 250 torr at \(35^{\circ} \mathrm{C}\). (a) What would be the vapor pressure of the solution if it exhibited ideal behavior? (b) Use the existence of hydrogen bonds between acetone and chloroform molecules to explain the deviation from ideal behavior. (c) Based on the behavior of the solution, predict whether the mixing of acetone and chloroform is an exothermic \(\left(\Delta H_{\text {soln }}<0\right)\) or endothermic \(\left(\Delta H_{\text {soln }}>0\right)\) process.

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