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A 15.0-L tank is filled with helium gas at a pressure of \(1.00 \times 10^{2}\) atm. How many balloons (each \(2.00 \mathrm{~L}\) ) can be inflated to a pressure of 1.00 atm, assuming that the temperature remains constant and that the tank cannot be emptied below 1.00 atm?

Short Answer

Expert verified
The number of balloons that can be inflated with the given helium tank and constraints is 0.

Step by step solution

01

Identify the given information

We are given the following information: - Tank volume: V鈧 = 15.0 L - Initial tank pressure: P鈧 = 1.00 脳 10虏 atm - Final tank pressure: P鈧 = 1.00 atm (as it cannot be emptied below this pressure) - Balloon volume: V鈧 = 2.00 L - Balloon pressure: P鈧 = 1.00 atm
02

Calculate the initial moles of helium

We can use the Ideal Gas Law, PV=nRT, to calculate n, which is the number of moles in the tank. However, we don't have the temperature or gas constant R. We can rearrange the Ideal Gas Law to determine the initial moles: n鈧 = P鈧乂鈧/RT Since the temperature is constant, the ratio P鈧乂鈧/RT remains constant. Therefore, we can rewrite the equation as: n鈧/n鈧 = P鈧乂鈧/P鈧僔鈧 We have the values for P鈧, V鈧, and P鈧; however, we do not have V鈧. To find this, we will first find the volume of gas that remains in the tank at 1.00 atm pressure, which can be found using the Boyle's Law (P鈧乂鈧 = P鈧俈鈧): V鈧 = P鈧乂鈧/P鈧 = (1.00 脳 10虏 atm 脳 15.0 L) / 1.00 atm = 1500 L Now we can find the initial moles, n鈧: n鈧/n鈧 = (1.00 脳 10虏 atm 脳 15.0 L) / (1.00 atm 脳 1500 L) n鈧 = n鈧 This means that the moles of helium gas in the tank do not change as the pressure changes from 1.00 x 10虏 atm to 1.00 atm.
03

Calculate the moles available for inflating balloons

Now that we know the initial moles are equal to the remaining moles, we can calculate the moles available for inflating balloons: n鈧 = n鈧 - n鈧 Since n鈧 = n鈧, the equation can be simplified to: n鈧 = n鈧 - n鈧 = 0 This means that there are no additional moles of gas available for inflating balloons beyond maintaining the 1.00 atm pressure in the tank.
04

Determine the number of balloons that can be inflated

Since there are no additional moles of gas available for inflating balloons, the number of balloons that can be inflated is 0. Thus, the answer is 0 balloons can be inflated with the given constraints.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boyle's Law
Boyle's Law is fundamental in understanding how gas pressures and volumes affect one another under a constant temperature. Essentially, this law implies that if a gas's temperature remains consistent, then its pressure and volume have an inverse relationship; as one increases, the other decreases. The law is mathematically expressed as:
\( P_1V_1 = P_2V_2 \).
The connection between these variables enables us to solve various problems, like determining how many balloons can be filled from a gas tank without changing the temperature. The calculation in the problem assumes that the pressure inside the tank cannot fall below a certain threshold (1.00 atm) which is crucial in maintaining the gas's volume. When applying Boyle's Law, one must cautiously track the volume and pressure to resolve the actual usable gas鈥攁n essential aspect for students to keep tabs on while they navigate through homework problems related to gas laws.
Pressure-Volume Relationship
Exploring the pressure-volume relationship of gases leads us to an intuitive understanding of how they behave under different scenarios. This movement towards understanding is not only about Boyle's Law but also about visualizing gases in a real-world context.
In the given exercise, the pressure-volume relationship is at the core of determining the capability of a helium tank to inflate a certain number of balloons. We see that if the pressure within the tank is reduced, more volume becomes available for use鈥攈owever, the tank's minimal pressure creates a constraint. It's critical to acknowledge that these relationships don't occur in isolation; they can be affected by factors such as the surrounding temperature and the amount (in moles) of the gas. Proper application combined with careful calculation allows students to grasp how precisely these variables interact, particularly when dealing with labs or practical gas usage situations.
Calculating Moles of Gas
Moles are a key unit in chemistry, specifically when it comes to gauging amounts of substances. Regarding gases, calculating the number of moles can provide insightful information about the quantity of gas present. It is a central part of applying the Ideal Gas Law which is represented as:
\( PV = nRT \)
where 'P' stands for pressure, 'V' for volume, 'n' for the number of moles, 'R' for the gas constant, and 'T' for temperature. In practice, if you know the pressure, volume, and temperature of a gas, you can calculate the number of moles. For students tackling gas law problems, it is paramount to recognize that while the number of moles might remain unchanged in a reactive process, available moles for work such as inflating balloons may differ. This aspect was crucial in the textbook exercise鈥攄espite the initial and remaining moles being identical due to Boyle's Law, they could not be used to inflate balloons. Understanding how to calculate moles in different pressures and volumes firmly roots a student's competence in solving gas law exercises.

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Most popular questions from this chapter

A set of bookshelves rests on a hard floor surface on four legs, each having a cross-sectional dimension of \(3.0 \times 4.1 \mathrm{~cm}\) in contact with the floor. The total mass of the shelves plus the books stacked on them is \(262 \mathrm{~kg} .\) Calculate the pressure in pascals exerted by the shelf footings on the surface.

At an underwater depth of \(250 \mathrm{ft}\), the pressure is 8.38 atm. What should the mole percent of oxygen be in the diving gas for the partial pressure of oxygen in the mixture to be 0.21 atm, the same as in air at 1 atm?

Consider a mixture of two gases, \(A\) and \(B\), confined in a closed vessel. A quantity of a third gas, \(C,\) is added to the same vessel at the same temperature. How does the addition of gas \(\mathrm{C}\) affect the following: (a) the partial pressure of gas \(A,\) (b) the total pressure in the vessel, \((\mathbf{c})\) the mole fraction of gas \(\mathrm{B} ?\)

A scuba diver's tank contains \(0.29 \mathrm{~kg}\) of \(\mathrm{O}_{2}\) compressed into a volume of 2.3 L. (a) Calculate the gas pressure inside the tank at \(9^{\circ} \mathrm{C} .\) (b) What volume would this oxygen occupy at \(26^{\circ} \mathrm{C}\) and 0.95 atm?

In Sample Exercise 10.16 , we found that one mole of \(\mathrm{Cl}_{2}\) confined to \(22.41 \mathrm{~L}\) at \(0{ }^{\circ} \mathrm{C}\) deviated slightly from ideal behavior. Calculate the pressure exerted by \(1.00 \mathrm{~mol} \mathrm{Cl}_{2}\) confined to a smaller volume, \(5.00 \mathrm{~L}\), at \(25^{\circ} \mathrm{C} .\) (a) First use the ideal-gas equation and (b) then use the van der Waals equation for your calculation. (Values for the van der Waals constants are given in Table \(10.3 .)\) (c) Why is the difference between the result for an ideal gas and that calculated using the van der Waals equation greater when the gas is confined to \(5.00 \mathrm{~L}\) compared to \(22.4 \mathrm{~L} ?\)

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