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a) The temperature on a warm summer day is \(87^{\circ} \mathrm{F}\). What is the temperature in \({ }^{\circ} \mathrm{C} ?\) (b) Many scientific data are reported at \(25^{\circ} \mathrm{C}\). What is this temperature in kelvins and in degrees Fahrenheit? (c) Suppose that a recipe calls for an oven temperature of \(400{ }^{\circ} \mathrm{F}\). Convert this temperature to degrees Celsius and to kelvins. (d) Liquid nitrogen boils at \(77 \mathrm{~K}\). Convert this temperature to degrees Fahrenheit and to degrees Celsius.

Short Answer

Expert verified
a) \(30.56^{\circ} \textrm{C}\) b) \(298.15 \textrm{K}\), \(77^{\circ} \textrm{F}\) c) \(204.44^{\circ} \textrm{C}\), \(477.59 \textrm{K}\) d) \(-196.15^{\circ} \textrm{C}\), \(-321.07^{\circ} \textrm{F}\)

Step by step solution

01

Use the Fahrenheit to Celsius formula

Apply the formula: \(C = \dfrac{5}{9}(F - 32)\)
02

Substitute the given temperature

Substitute the given Fahrenheit temperature \(F = 87\) and solve for Celsius temperature: \[C = \dfrac{5}{9}(87 - 32)\]
03

Calculate

Perform the calculation: \[C \approx 30.56^{\circ} \textrm{C}\] The temperature in Celsius is approximately \(30.56^{\circ} \textrm{C}\). b) Convert \(25^{\circ} \textrm{C}\) to Kelvin and Fahrenheit
04

Convert Celsius to Kelvin

Use the formula \(K = C + 273.15\) to convert Celsius to Kelvin: \[K = 25 + 273.15\]
05

Calculate Kelvin temperature

Perform the calculation: \[K \approx 298.15 \textrm{K}\] The temperature in Kelvin is approximately \(298.15 \textrm{K}\).
06

Convert Celsius to Fahrenheit

Use the formula \(F = \dfrac{9}{5}C + 32\) to convert Celsius to Fahrenheit: \[F = \dfrac{9}{5}(25) + 32\]
07

Calculate Fahrenheit temperature

Perform the calculation: \[F \approx 77^{\circ} \textrm{F}\] The temperature in Fahrenheit is approximately \(77^{\circ} \textrm{F}\). c) Convert \(400{ }^{\circ} \textrm{F}\) to Celsius and Kelvin
08

Convert Fahrenheit to Celsius

Apply the formula: \(C = \dfrac{5}{9}(F - 32)\), and substitute the given Fahrenheit temperature \(F = 400\): \[C = \dfrac{5}{9}(400 - 32)\]
09

Calculate Celsius temperature

Perform the calculation: \[C \approx 204.44^{\circ} \textrm{C}\] The temperature in Celsius is approximately \(204.44^{\circ} \textrm{C}\).
10

Convert Celsius to Kelvin

Use the formula \(K = C + 273.15\) to convert Celsius to Kelvin: \[K = 204.44 + 273.15\]
11

Calculate Kelvin temperature

Perform the calculation: \[K \approx 477.59 \textrm{K}\] The temperature in Kelvin is approximately \(477.59 \textrm{K}\). d) Convert \(77 \textrm{K}\) to Fahrenheit and Celsius
12

Convert Kelvin to Celsius

Use the formula \(C = K - 273.15\) to convert Kelvin to Celsius: \[C = 77 - 273.15\]
13

Calculate Celsius temperature

Perform the calculation: \[C \approx -196.15^{\circ} \textrm{C}\] The temperature in Celsius is approximately \(-196.15^{\circ} \textrm{C}\).
14

Convert Celsius to Fahrenheit

Use the formula \(F = \dfrac{9}{5}C + 32\) to convert Celsius to Fahrenheit: \[F = \dfrac{9}{5}(-196.15) + 32\]
15

Calculate Fahrenheit temperature

Perform the calculation: \[F \approx -321.07^{\circ} \textrm{F}\] The temperature in Fahrenheit is approximately \(-321.07^{\circ} \textrm{F}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fahrenheit to Celsius
Understanding temperature conversion from Fahrenheit to Celsius is crucial in everyday life. The conversion is done using the formula:
  • \( C = \dfrac{5}{9}(F - 32) \)
This formula allows us to convert a temperature from Fahrenheit, often used in the United States, to Celsius, the standard in most other countries. To apply it, subtract 32 from the Fahrenheit value, multiply the result by 5, and then divide by 9.
For example, if the temperature is \(87^{\circ} \text{F}\), subtract 32 to get 55. Multiplying 55 by 5 gives 275. Finally, dividing 275 by 9 results in approximately \(30.56^{\circ} \text{C}\). This tells us that \(87^{\circ} \text{F}\) is about \(30.56^{\circ} \text{C}\).
Converting temperatures this way is helpful when comparing weather reports or cooking instructions across different regions.
Celsius to Kelvin
When working with scientific data, temperatures are often converted from Celsius to Kelvin. This conversion is straightforward:
  • \( K = C + 273.15 \)
The Kelvin scale is important in scientific fields because it begins at absolute zero, the coldest possible temperature.
This scale is often used in thermodynamics and other scientific studies because it simplifies equations and relationships. To convert, simply add 273.15 to the Celsius temperature.
For instance, to convert \(25^{\circ} \text{C}\) to Kelvin, you would add 273.15, resulting in \(298.15 \text{K}\).
This conversion is vital in laboratory settings and when comparing results across experiments documented worldwide.
Kelvin to Fahrenheit
Converting Kelvin to Fahrenheit involves two steps: converting Kelvin to Celsius, and then to Fahrenheit. Start by using:
  • \( C = K - 273.15 \)
Then, take the Celsius result and convert it to Fahrenheit using:
  • \( F = \dfrac{9}{5}C + 32 \)
These conversions are needed when using scientific or laboratory data in everyday settings like cooking or clothing care.For example, to convert \(77 \text{K}\) to Fahrenheit, first calculate the Celsius equivalent: \(77 - 273.15 = -196.15^{\circ} \text{C} \).
Then, convert Celsius to Fahrenheit: \(F = \dfrac{9}{5}(-196.15) + 32 \approx -321.07^{\circ} \text{F} \).
Knowing how to switch between these units is essential in environments where temperature precision is critical.
Thermodynamics
Thermodynamics is the study of energy, heat, and their transformations. It's fundamentally linked to temperature scales like Celsius, Kelvin, and Fahrenheit. Understanding these connections helps in interpreting energy changes in physics and chemistry.
In thermodynamics, the Kelvin scale is predominantly used due to its absolute zero starting point, which allows for accurate scientific calculations. This is particularly useful in experiments dealing with heat transfer, energy exchanges, and phase changes.
Thermodynamics explains phenomena like boiling points and freezing points, essential for diverse applications from industrial processes to meteorology. For instance, liquid nitrogen's boiling point at \(77 \text{K}\) or \(-196.15^{\circ} \text{C}\), illustrates extreme temperature conditions managed using thermodynamics principles.
Abstract concepts become more tangible when temperatures are quantified accurately through these conversions.

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Most popular questions from this chapter

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