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Calculate the molecular weight of the following compounds. (a) methane, \(\mathrm{CH}_{4}\) (b) glucose, \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) (c) diethyl ether, \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{2} \mathrm{O}\) (d) thioacetamide, \(\mathrm{CH}_{3} \mathrm{CSNH}_{2}\)

Short Answer

Expert verified
(a) 16.05 g/mol, (b) 180.18 g/mol, (c) 74.14 g/mol, (d) 75.14 g/mol.

Step by step solution

01

Understand the Atomic Weights

Before calculating molecular weights, familiarize yourself with the atomic weights: Carbon (C) = 12.01 g/mol, Hydrogen (H) = 1.01 g/mol, Oxygen (O) = 16.00 g/mol, Nitrogen (N) = 14.01 g/mol, and Sulfur (S) = 32.07 g/mol.
02

Calculate Molecular Weight of Methane

For methane, \(\mathrm{CH}_4\), calculate the molecular weight by adding the atomic weights of 1 carbon and 4 hydrogens: \(1 \times 12.01 + 4 \times 1.01 = 16.05\) g/mol.
03

Calculate Molecular Weight of Glucose

For glucose, \(\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6\), calculate by adding the atomic weights of 6 carbons, 12 hydrogens, and 6 oxygens: \(6 \times 12.01 + 12 \times 1.01 + 6 \times 16.00 = 180.18\) g/mol.
04

Calculate Molecular Weight of Diethyl Ether

For diethyl ether, \((\mathrm{CH}_3\mathrm{CH}_2)_2 \mathrm{O}\), first treat \(\mathrm{CH}_3\mathrm{CH}_2\) as a single unit, repeating twice: \(4 \times 12.01 + 10 \times 1.01 + 16.00 = 74.14\) g/mol.
05

Calculate Molecular Weight of Thioacetamide

For thioacetamide, \(\mathrm{CH}_3 \mathrm{CSNH}_2\), calculate by adding the atomic weights: \(2 \times 12.01 + 5 \times 1.01 + 32.07 + 14.01 = 75.14\) g/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Weights
Atomic weights are fundamental components in chemical calculations. They are the average mass of an atom of an element, expressed in atomic mass units (amu). These weights consider the natural distribution of isotopes of each element. Commonly used atomic weights include:
  • Carbon (C): 12.01 amu
  • Hydrogen (H): 1.01 amu
  • Oxygen (O): 16.00 amu
  • Nitrogen (N): 14.01 amu
  • Sulfur (S): 32.07 amu
These values are essential for students when they engage in chemical calculations. They allow us to determine the relative proportions of elements in compounds.
Chemical Compounds
Chemical compounds are formed when two or more elements are chemically bonded together. These compounds have distinct properties different from the elements they consist of. Understanding chemical compounds involves knowing how the elements combine and in what ratios. Compounds like methane (\( \mathrm{CH}_4 \) ), glucose (\( \mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6 \)), diethyl ether (\( \left( \mathrm{CH}_3 \mathrm{CH}_2 \right)_2 \mathrm{O} \)), and thioacetamide (\( \mathrm{CH}_3 \mathrm{CSNH}_2 \) ) serve as examples where different atoms join together. Each compound has unique properties, fundamentally influenced by its atomic composition.When studying these compounds, recognizing their molecular interaction is crucial. It helps in predicting the behavior and reactivity of the compound in various conditions.
Stoichiometry
Stoichiometry refers to the calculation of reactants and products in chemical reactions. It involves using balanced chemical equations to predict quantities, ensuring that the Law of Conservation of Mass is upheld. In stoichiometry, molecular weights calculated from atomic weights are a critical aspect. These calculations enable chemists to predict the amount of material needed for reactions or the expected yield, providing the basic understanding of the reaction's complete pathway. For instance, determining the molecular weight of compounds in reactions involving methane, glucose, or other compounds helps in calculating their quantities in given experiments. Understanding stoichiometry allows students to work through more complex chemistry problems effectively.
Molecular Formulas
Molecular formulas represent the actual number and type of atoms present in a molecule of a compound. They give insight into the compound's composition and can tell us much about the substance's potential behavior and reactivity.For example:
  • \( \mathrm{CH}_4 \) shows that methane consists of one carbon atom and four hydrogen atoms.
  • \( \mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_6 \) for glucose reveals its more complex structure with six carbon, twelve hydrogen, and six oxygen atoms.
These formulas act as a roadmap to understanding a compound's structure. They allow chemists to deduce how such molecules might interact in chemical reactions, guiding experimental design and analysis. Understanding molecular formulas is foundational for studying and predicting chemical behaviors.

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Most popular questions from this chapter

Calculate the concentration of the solution formed when \(15.0 \mathrm{~mL}\) of \(6.00 \mathrm{M} \mathrm{HCl}\) are diluted with \(25.0 \mathrm{~mL}\) of water.

Oxalic acid reacts with the chromate ion in acidic solu- tion as follows. $$ \begin{array}{l} 3 \mathrm{H}_{2} \mathrm{C}_{6} \mathrm{O}_{4}(a q)+2 \mathrm{CrO}_{4}^{2-}(a q)+10 \mathrm{H}^{+}(a q) \\ \quad \longrightarrow 6 \mathrm{CO}_{2}(g)+2 \mathrm{Cr}^{3+}(a q)+8 \mathrm{H}_{2} \mathrm{O}(l) \end{array} $$ Calculate the molarity of the oxalic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)\) solution if \(10.0 \mathrm{~mL}\) of the solution consume \(40.0 \mathrm{~mL}\) of $$ 0.0250 \mathrm{M} \mathrm{CrO}_{4}^{2-} $$

Calculate the molecular weight of the following compounds. (a) chromium hexacarbonyl, \(\mathrm{Cr}(\mathrm{CO})_{6}\) (b) iron(III) nitrate, \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) (c) potassium dichromate, \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) (d) calcium phosphate, \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)

Assume that you start with a glass of water, a glass of methanol, and a teaspoon. Exactly one teaspoon of water is removed from the glass of water and added to the glass of methanol. The resulting mixture of methanol is stirred until the two liquids are thoroughly mixed. Exactly one teaspoon of this mixture is then transferred back to the water. Which of the following statements is true? (a) The volume of water that ends up in the methanol is larger than the volume of methanol that ends up in the water. (b) The net volume of water transferred to the methanol is smaller than the net volume of methanol transferred to the water. (c) The net volume of water added to the methanol is exactly the same as the net volume of methanol added to the water.

Caffeine is a central nervous system stimulant found in coffee, tea, and cola nuts. Calculate the molecular formula of caffeine if the compound is \(49.48 \% \mathrm{C}, 5.19 \%\) \(\mathrm{H}, 28.85 \% \mathrm{~N},\) and \(16.48 \% \mathrm{O}\) by mass and has a molecular weight of 194.2 grams per mole.

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