Chapter 2: Problem 36
Calculate the molecular weight of the following compounds. (a) chromium hexacarbonyl, \(\mathrm{Cr}(\mathrm{CO})_{6}\) (b) iron(III) nitrate, \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) (c) potassium dichromate, \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) (d) calcium phosphate, \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)
Short Answer
Step by step solution
Understanding Atomic Weights
Chromium Hexacarbonyl Calculation
Iron(III) Nitrate Calculation
Potassium Dichromate Calculation
Calcium Phosphate Calculation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Atomic Weights
An element like carbon (C) has an atomic weight of 12.01 g/mol. Oxygen (O), which is another common element in many compounds, has an atomic weight of 16.00 g/mol. Other important atomic weights include chromium (Cr) at 51.996 g/mol and calcium (Ca) at 40.078 g/mol. These values remain constant and are used universally in chemical calculations.
- Carbon (C): 12.01 g/mol
- Oxygen (O): 16.00 g/mol
- Chromium (Cr): 51.996 g/mol
- Iron (Fe): 55.845 g/mol
- Potassium (K): 39.098 g/mol
- Calcium (Ca): 40.078 g/mol
Chemical Compounds
Let's consider some examples of compounds as given in the original exercise:
- Chromium hexacarbonyl, \({\rm Cr(CO)_6}\), which consists of 1 chromium atom and 6 carbonyl (CO) groups.
- Iron(III) nitrate, \({\rm Fe(NO_3)_3}\), which is composed of 1 iron atom and 3 nitrate (NO_3) groups.
- Potassium dichromate, \({\rm K_2Cr_2O_7}\), made up of 2 potassium, 2 chromium, and 7 oxygen atoms.
- Calcium phosphate, \({\rm Ca_3(PO_4)_2}\), with 3 calcium, 2 phosphorous, and 8 oxygen atoms.
Step-by-Step Solution
Step 2: Chromium Hexacarbonyl Calculation
The molecular weight is derived from 1 chromium and 6 carbonyl, \( {\rm CO} \), groups. Each CO group is a combination of one carbon and one oxygen. By adding up these atomic weights, the molecular weight of Cr(CO)₆ becomes:\[molecular\ weight = 1 \times 51.996 + 6 \times (12.01 + 16.00) = 220.06 \, {\rm g/mol}\]
Step 3: Iron(III) Nitrate Calculation
This compound has 1 iron and 3 nitrate, \({\rm NO}_3\), groups. The calculation follows:\[molecular\ weight = 1 \times 55.845 + 3 \times (14.007 + 3 \times 16.00) = 241.86 \, {\rm g/mol}\]
Step 4: Potassium Dichromate Calculation
It consists of 2 potassium, 2 chromium, and 7 oxygen atoms, leading to:\[molecular\ weight = 2 \times 39.098 + 2 \times 51.996 + 7 \times 16.00 = 294.18 \, {\rm g/mol}\]
Step 5: Calcium Phosphate Calculation
This involves 3 calcium, 2 phosphorus, and 8 oxygen atoms:\[molecular\ weight = 3 \times 40.078 + 2 \times 30.974 + 8 \times 16.00 = 310.18 \, {\rm g/mol}\]Following these clear steps helps ensure accuracy and strengthen understanding of molecular weight computation.