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Choose from among the labels strongly acidic, weakly acidic, neutral, weakly basic, and strongly basic to estimate the \(\mathrm{pH}\) of the following solutions. (a) \(0.250 \mathrm{M} \mathrm{HBr}\) (b) \(0.50 \mathrm{MHF}\) (c) \(0.020 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_{2}\) (d) \(0.44 \mathrm{M} \mathrm{NH}_{3}\)

Short Answer

Expert verified
(a) Strongly acidic, (b) Weakly acidic, (c) Strongly basic, (d) Weakly basic.

Step by step solution

01

Determine the Nature of Each Substance

To classify the solutions, identify if the given substances are strong acids, weak acids, strong bases, weak bases, or neutral. This helps in estimating the \( \mathrm{pH} \) levels. \( \mathrm{HBr} \) is a strong acid, \( \mathrm{HF} \) is a weak acid, \( \mathrm{Ba(OH)}_2 \) is a strong base, and \( \mathrm{NH}_3 \) is a weak base.
02

Evaluate the \\( \mathrm{pH} \\) of Strong Acids and Bases

Strong acids fully dissociate in solution, leading to low \( \mathrm{pH} \) values. Strong bases fully dissociate, leading to high \( \mathrm{pH} \) values. \( 0.250 \, \mathrm{M} \, \mathrm{HBr} \) is strongly acidic. For \( 0.020 \, \mathrm{M} \, \mathrm{Ba(OH)}_2 \), note that each \( \mathrm{Ba(OH)}_2 \) produces 2 \( \mathrm{OH}^- \) ions, leading to a strongly basic solution.
03

Evaluate the \\( \mathrm{pH} \\) of Weak Acids

Weak acids, like \( \mathrm{HF} \), do not fully dissociate, so their \( \mathrm{pH} \) is higher than that of strong acids but still acidic. Thus, \( 0.50 \, \mathrm{M} \, \mathrm{HF} \) is weakly acidic.
04

Evaluate the \\( \mathrm{pH} \\) of Weak Bases

Weak bases, such as \( \mathrm{NH}_3 \), only partially accept protons from water, resulting in a slightly basic solution. Therefore, \( 0.44 \, \mathrm{M} \, \mathrm{NH}_3 \) is weakly basic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Strong Acids and Bases
Strong acids and bases are chemical compounds that completely dissociate in solution. This means that when you add a strong acid or base to water, it fully breaks apart into its constituent ions. For example, in the case of hydrochloric acid (HCl), a strong acid, it dissociates completely into hydrogen ions (H鈦) and chloride ions (Cl鈦). This full dissociation is why strong acids have very low pH values, often close to 0.

Examples of Strong Acids and Bases:
  • Strong acids: HCl, HBr, HI, and HClO鈧
  • Strong bases: NaOH, KOH, and Ba(OH)鈧
In the original problem, HBr is identified as a strong acid, meaning it completely dissociates, lowering the pH significantly. Similarly, Ba(OH)鈧 is a strong base, fully dissociating to produce two hydroxide ions per molecule, contributing to a very high pH.
Weak Acids and Bases
Unlike strong acids and bases, weak acids and bases do not completely dissociate in water. Instead, they partially break into ions and remain mostly undissociated as molecules in the solution.

Understanding Weak Acids:
  • With weak acids like HF, only a fraction of the acid molecules release H鈦 ions in water.
  • This partial dissociation means that weak acids have higher pH values than strong acids but are still under 7 and, therefore, acidic.
Understanding Weak Bases:
  • Weak bases, such as NH鈧, partially accept protons from water, forming only a small amount of hydroxide ions.
  • This results in a pH slightly above 7, indicating a basic nature, but not as high as strong bases.
In our exercise, HF is a weak acid that does not fully dissociate, leading to a weakly acidic solution. Likewise, NH鈧 is a weak base, resulting in a weakly basic solution.
Dissociation in Solutions
Dissociation refers to the process in chemical solutions where molecules split into smaller particles, such as ions. This behavior is significant because it affects the acidity or basicity of the solution.

Full Dissociation in Strong Acids and Bases:
  • When a strong acid or base dissociates fully, it releases a high concentration of H鈦 or OH鈦 ions, respectively.
  • This results in either a marked decrease (acids) or increase (bases) in pH levels.
Partial Dissociation in Weak Acids and Bases:
  • Weak acids and bases dissociate only to a limited extent, often reaching an equilibrium where both ions and molecules coexist.
  • This reinforcement of undissociated molecules leads to higher pH for acids and lower for bases, flattening the impact on pH compared to strong varieties.
In the examples given, HBr and Ba(OH)鈧 show strong and complete dissociation, whereas HF and NH鈧 demonstrate partial dissociation.
Chemical Equilibrium
Chemical equilibrium is a state in which the concentration of reactants and products remains constant over time. In the context of acids and bases at equilibrium, it is crucial for understanding the behavior of weak acids and bases.

Equilibrium in Weak Acids:
  • In a weak acid solution, such as HF, equilibrium is reached when the rates of dissociation and recombination of ions are equal.
  • This dynamic equilibrium means that even though not all acid molecules dissociate, the system remains stable with a constant concentration of ions in the solution.
Equilibrium in Weak Bases:
  • Similarly, for weak bases like NH鈧, the equilibrium occurs when the rate of accepting protons equals the rate of forming back ammonia molecules from cations and water.
  • This balance determines the solution's pH, stabilizing it just above neutral.
In chemical equilibrium, while weak acids and bases never fully dissociate, they maintain a steady concentration of ions, explaining why their pH remains constant and can be predicted with an understanding of equilibrium principles.

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Most popular questions from this chapter

A hypothetical weak base has \(K_{b}=5.0 \times 10^{-4}\). Calculate the equilibrium concentrations of the base, its conjugate acid, and \(\mathrm{OH}^{-}\) in a \(0.15 \mathrm{M}\) solution of the base.

Morphine, \(\mathrm{C}_{17} \mathrm{H}_{19} \mathrm{O}_{3} \mathrm{~N},\) is a weak base with \(K_{\mathrm{b}}=\) \(1.6 \times 10^{-6} .\) It is a prescription drug used to deaden pain; the average dose is \(10 \mathrm{mg}\). Calculate the \(\mathrm{pH}\) of a \(0.0010 M\) solution.

A solution is made by diluting \(25.0 \mathrm{~mL}\) of concentrated \(\mathrm{HCl}(37 \%\) by weight; density \(=1.19 \mathrm{~g} / \mathrm{mL})\) to exactly \(500 \mathrm{~mL}\). Calculate the \(\mathrm{pH}\) of the resulting solution.

Coniine ( 2 -propylpiperidine) is a weak base. It has the formula \(\mathrm{C}_{8} \mathrm{H}_{17} \mathrm{~N}\). Calculate the \(\mathrm{pH}\) of a \(0.500 \mathrm{M}\) solution of coniine \(\left(\mathrm{p} K_{\mathrm{b}}=3.1\right)\) Coniine is extracted from the plant Conium maculatum, also called hemlock. This harmless-looking relative of the carrot produces a deadly poison that killed the Greek philosopher Socrates in 399 ?.c. Socrates was a gadfly. He set about demonstrating that many prominent Athenians were more concerned with their own self-interest than with the needs of the society as a whole. He was charged with impiety, corrupting the youth, and disturbing the society. Socrates defended himself and was found guilty by the other Athenians. They asked him to recommend his own punishment; he recommended that he be compensated for his work with young people because he had no other source of income. This suggestion angered his peers, who sentenced him to death. Socrates was not well guarded, and the Athenians hoped he would escape. But he felt a moral obligation to follow the edict of the state. So he drank hemlock and died. Three of Plato's dialogues speak of the events surrounding the death of Socrates. Apology depicts the trial, Crito includes his reasons for choosing death, and Phaedro comprises his musings as the coniine took effect.

Determine the hydrogen ion or hydroxide ion concentration in each of the following solutions, as appropriate. (a) a solution in which \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=9.02 \times 10^{-10} M\) (b) a solution in which \(\left[\mathrm{OH}^{-}\right]=1.06 \times 10^{-11} M\)

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