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Identify the Lewis acid and the Lewis base in each reaction. (a) \(\mathrm{I}_{2}(\mathrm{~s})+\mathrm{I}^{-}(\mathrm{aq}) \rightarrow \mathrm{I}_{3}^{-}(\mathrm{aq})\) (b) \(\mathrm{SO}_{2}(\mathrm{~g})+\mathrm{BF}_{3}(\mathrm{~g}) \rightarrow \mathrm{O}_{2} \mathrm{SBF}_{3}(\mathrm{~s})\) (c) \(\mathrm{Au}^{+}(\mathrm{aq})+2 \mathrm{CN}^{-}(\mathrm{aq}) \rightarrow\left[\mathrm{Au}(\mathrm{CN})_{2}\right]^{-}(\mathrm{aq})\) (d) \(\mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{H}_{2} \mathrm{CO}_{3}(\) aq \()\)

Short Answer

Expert verified
(a) Lewis acid: \(\mathrm{I}_{2}\), Lewis base: \(\mathrm{I}^{-}\). (b) Lewis acid: \(\mathrm{BF}_{3}\), Lewis base: \(\mathrm{SO}_{2}\). (c) Lewis acid: \(\mathrm{Au}^{+}\), Lewis base: \(\mathrm{CN}^{-}\). (d) Lewis acid: \(\mathrm{CO}_{2}\), Lewis base: \(\mathrm{H}_{2}\mathrm{O}\).

Step by step solution

01

Understanding Lewis Acids and Bases

A Lewis acid is a species that can accept an electron pair, while a Lewis base is a species that can donate an electron pair. In each reaction, identify which reactant acts as the electron pair donor and which acts as the acceptor.
02

Analyzing Reaction (a)

Reaction: \(\mathrm{I}_{2}(\mathrm{~s})+\mathrm{I}^{-}(\mathrm{aq}) \rightarrow\mathrm{I}_{3}^{-}(\mathrm{aq})\). Here, \(\mathrm{I}_{2}\) accepts a pair of electrons from \(\mathrm{I}^{-}\). Therefore, \(\mathrm{I}_{2}\) is the Lewis acid, and \(\mathrm{I}^{-}\) is the Lewis base.
03

Analyzing Reaction (b)

Reaction: \(\mathrm{SO}_{2}(\mathrm{~g})+\mathrm{BF}_{3}(\mathrm{~g}) \rightarrow \mathrm{O}_{2}\mathrm{SBF}_{3}(\mathrm{~s})\). In this case, \(\mathrm{BF}_{3}\) accepts an electron pair from \(\mathrm{SO}_{2}\). Therefore, \(\mathrm{BF}_{3}\) is the Lewis acid, and \(\mathrm{SO}_{2}\) is the Lewis base.
04

Analyzing Reaction (c)

Reaction: \(\mathrm{Au}^{+}(\mathrm{aq})+2 \mathrm{CN}^{-}(\mathrm{aq}) \rightarrow\left[\mathrm{Au}(\mathrm{CN})_{2}\right]^{-}(\mathrm{aq})\). Here, \(\mathrm{Au}^{+}\) accepts electron pairs from the \(\mathrm{CN}^{-}\) ions. Therefore, \(\mathrm{Au}^{+}\) is the Lewis acid, and \(\mathrm{CN}^{-}\) is the Lewis base.
05

Analyzing Reaction (d)

Reaction: \(\mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{H}_{2} \mathrm{CO}_{3}(\text{aq})\). In this reaction, \(\mathrm{CO}_{2}\) accepts a pair of electrons from \(\mathrm{H}_{2}\mathrm{O}\). Hence, \(\mathrm{CO}_{2}\) is the Lewis acid, and \(\mathrm{H}_{2}\mathrm{O}\) is the Lewis base.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Chemical reactions are processes where substances, called reactants, are transformed into new substances, called products. In the context of Lewis acids and bases, these reactions involve the transfer of electron pairs. Understanding the roles of different substances in these reactions helps to predict product formation and reaction mechanisms.

In exercise (a), iodine (\( \mathrm{I}_{2} \)) reacts with the iodide ion (\( \mathrm{I}^{-} \)) to form the triiodide ion (\( \mathrm{I}_{3}^{-} \)). Similarly, in each subsequent example, different substances react based on their ability to donate or accept electron pairs, indicating different chemical transformations.

Recognizing how electrons are shared or transferred among reactants offers insight into the nature and course of chemical reactions. Here, the key focus is on how these interactions identify certain molecules as Lewis acids or bases, elaborating on the electron transfer process behind chemical reactions.
Electron Pair Donor
An electron pair donor is a substance that provides an electron pair for a chemical bond. In the language of Lewis theory, this is known as a Lewis base. Electron pair donors are crucial in interactions, as they initiate the process of forming new bonds. This is essential to understand when studying chemical reactions involving acids and bases.

- In reaction (a), \( \mathrm{I}^{-} \), an iodine ion, donates an electron pair to \( \mathrm{I}_{2} \), making it the Lewis base.- For reaction (b), \( \mathrm{SO}_{2} \) acts as the electron pair donor, interacting with \( \mathrm{BF}_{3} \).- In reaction (c), \( \mathrm{CN}^{-} \) ions each provide an electron pair to \( \mathrm{Au}^{+} \), serving as the base.- Lastly, in reaction (d), water (\( \mathrm{H}_{2} \mathrm{O} \)) donates an electron pair to carbon dioxide (\( \mathrm{CO}_{2} \)), classifying it as the Lewis base.Identifying the electron pair donor in a reaction helps in understanding the formation of new chemical bonds and transformations.
Electron Pair Acceptor
An electron pair acceptor is a molecule or ion that can receive an electron pair, under Lewis theory, making it a Lewis acid. These substances are essential players in forming new chemical bonds and stabilizing the molecular structure through the acceptance of electrons.

- In reaction (a), \( \mathrm{I}_{2} \) acts as the electron pair acceptor, taking electrons from \( \mathrm{I}^{-} \).- In reaction (b), \( \mathrm{BF}_{3} \) accepts an electron pair from \( \mathrm{SO}_{2} \).- During reaction (c), \( \mathrm{Au}^{+} \) is identified as the acceptor of electron pairs from the \( \mathrm{CN}^{-} \) ions.- In reaction (d), \( \mathrm{CO}_{2} \) receives an electron pair from \( \mathrm{H}_{2} \mathrm{O} \).The roles of electron pair acceptors in chemical reactions are crucial for the progression of reactions and the formation of stable products, acting as a key element in molecular interactions.
Lewis Structures
Lewis structures are diagrams that show the bonding between atoms and the lone pairs of electrons in a molecule. They provide a simple way to visualize the component parts of molecules and how atoms are connected.

By utilizing Lewis structures, one can clearly see which species will likely donate or accept electron pairs in reactions. They are particularly useful for understanding which atoms or molecules act as Lewis acids and bases.

For example, when looking at the molecule \( \mathrm{SO}_{2} \) in reaction (b), the Lewis structure reveals available electron pairs that might engage with \( \mathrm{BF}_{3} \). Similarly, the Lewis structure of water in reaction (d) illustrates its potential as an electron pair donor.
  • Visualizing molecules enhances our comprehension of their chemical properties and behavioral tendencies in reactions.
  • Helps in predicting the electron donor or acceptor status of species in a reaction.
Lewis structures serve as an invaluable tool for both understanding and predicting chemical reactivity and interactions.

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Most popular questions from this chapter

Write an equation to describe the proton transfer that occurs when each of these acids is added to water. (a) \(\mathrm{HCO}_{3}^{-}\) (b) \(\mathrm{HCl}\) (c) \(\mathrm{CH}_{3} \mathrm{COOH}\) (d) \(\mathrm{HCN}\)

A solution is made by dissolving \(15.0 \mathrm{~g}\) sodium hydroxide in approximately \(450 \mathrm{~mL}\) water. The solution becomes quite warm, but after it is allowed to return to room temperature, water is added to bring the volume to \(500.0 \mathrm{~mL}\) of solution. (a) Calculate the \(\mathrm{pH}\) and \(\mathrm{pOH}\) in the final solution. (b) Why would we wait for it to return to room temperature? (c) If the mass of the water used to initially dissolve the sodium hydroxide were exactly \(450 \mathrm{~g}\) and the temperature of the water increased by \(8.865^{\circ} \mathrm{C}\), how much heat was given off by the dissolution of \(15.0 \mathrm{~g}\) of solute? Assume the specific heat of the solution is \(4.184 \mathrm{~J} / \mathrm{g} \cdot \mathrm{K}\). What is the molar heat change for the dissolution of sodium hydroxide (known as the enthalpy of solution, \(\left.\Delta H_{\mathrm{sol}}\right) ?\)

Choose from among the labels strongly acidic, weakly acidic, neutral, weakly basic, and strongly basic to estimate the \(\mathrm{pH}\) of the following solutions. (a) \(0.250 \mathrm{M} \mathrm{HBr}\) (b) \(0.50 \mathrm{MHF}\) (c) \(0.020 \mathrm{M} \mathrm{Ba}(\mathrm{OH})_{2}\) (d) \(0.44 \mathrm{M} \mathrm{NH}_{3}\)

Propose an experiment to determine whether a coordinate covalent bond is different from other covalent bonds. Use $$ : \mathrm{NH}_{3}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{NH}_{4}^{+}+\mathrm{OH}^{-} $$ for a concrete example.

Define a weak acid.

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