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Chapter 19: Q30E (page 1051)

Draw diagrams for any cis, trans, and optical isomers that could exist for the following (en is ethylenediamine):

\(\begin{aligned}{}(a){\left( {Co{{(en)}_2}\left( {N{O_2}} \right)Cl} \right)^ + }\\(b){\left( {Co{{(en)}_2}C{l_2}} \right)^ + }\\(c)\left( {Pt{{\left( {N{H_3}} \right)}_2}C{l_4}} \right)\\(d){\left( {Cr{{(en)}_3}} \right)^{3 + }}\\(e)\left( {Pt{{\left( {N{H_3}} \right)}_2}C{l_2}} \right)\end{aligned}\)

Short Answer

Expert verified

Isomers are the chemical species which have the same molecular formula but different arrangement of atoms or ligands in space. Space isomerism is of two type namely geometrical and optical isomerism.

Step by step solution

01

Explanation

(a)

  • In\({\left( {Co{{(en)}_2}\left( {N{O_2}} \right)Cl} \right)^ + }\), We can see that \(2\) bidentate ligands and \(2\)monodentate ligands are present inside the coordination sphere, which means the coordination number of\(6\) the central metal ion \(Co\) is 6 . Like that it will have \(2\) isomers: cis and trans.

(b)

  • In \({\left( {Co{{(en)}_2}C{l_2}} \right)^ + }\), We can see that \(2\) bidentate ligands and \(2\) monodentate ligands are present inside the coordination sphere, which leaves us a clue that the coordination number of the central metal ion \(Co\) is \(6\). Like that it will have \(2\)isomers: cis and trans.

(c)

  • In \(\left( {Pt{{\left( {N{H_3}} \right)}_2}C{l_4}} \right)\)We can see that \(6\) monodentate ligands are present inside the coordination sphere, which means the coordination number of the central metal ion \(Pt\)is \(6\) . Like that it will have \(2\) isomers: cis and trans.


(d)


  • In \({\left( {Cr{{(en)}_3}} \right)^{3 + }}\) We can see that \(3\) bidentate ligands are present inside the coordination sphere, which means the coordination number of the central metal ion \(Cr\) is \(6\) . Like that it will have \(2\) optical isomers.


(e)

  • In \(\left( {Pt{{\left( {N{H_3}} \right)}_2}C{l_2}} \right)\) We can see that \(4\)monodentate ligands are present inside the coordination sphere, which means the coordination number of the central metal ion \(Pt\)is \(4\). Like that it will have \(2\)isomers: cis and trans.

02

Result

a) It has \(2\) isomers: cis and trans.

b) It has \(2\) isomers: cis and trans.

c) It has \(2\) isomers: cis and trans.

d) It has \(2\)optical isomers.

e) It has \(2\)isomers: cis and trans.

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Most popular questions from this chapter

Draw the crystal field diagrams for \({\left( {Fe{{\left( {N{O_2}} \right)}_6}} \right)^{4 - }}\)and \({\left( {Fe{F_6}} \right)^{3 - }}.\)State whether each complex is high spin or low spin, paramagnetic or diamagnetic, and compare \({\Delta _{oct }}\)to \(P\)for each complex.

Predict the products of each of the following reactions and then balance the chemical equations.

(a) Fe is heated in an atmosphere of steam.

(b) NaOH is added to a solution of Fe(NO3)3.

(c) FeSO4 is added to an acidic solution of KMnO4.

(d) Fe is added to a dilute solution of H2SO4.

(e) A solution of Fe(NO3)2 and HNO3 is allowed to stand in air.

(f) FeCO3 is added to a solution of HClO4.

(g) Fe is heated in air.

Is it possible for a complex of a metal in the transition series to have six unpaired electrons? Explain.

Indicate the coordination number for the central metal atom in each of the following coordination compounds:

\(\begin{aligned}{}(a)\left( {Pt{{\left( {{H_2}O} \right)}_2}B{r_2}} \right)\\(b)\left( {Pt\left( {N{H_3}} \right)(py)(Cl)(Br)} \right)\left( {py = } \right.pyridine,\left. {{C_5}{H_5}\;N} \right)\\(c)\left( {Zn{{\left( {N{H_3}} \right)}_2}C{l_2}} \right)\\(d)\left( {Zn\left( {N{H_3}} \right)(py)(Cl)(Br)} \right)\\(e)\left( {Ni{{\left( {{H_2}O} \right)}_4}C{l_2}} \right)\\(f){\left( {Fe{{(en)}_2}{{(CN)}_2}} \right)^ + }\left( {en = } \right.ethylenediamine,\left. {{C_2}{H_8}\;{N_2}} \right)\end{aligned}\)

Give the oxidation state of the metal for each of the following oxides of the first transition series. (Hint: Oxides of formula M3O4 are examples of mixed valence compounds in which the metal ion is present in more than one oxidation state. It is possible to write these compound formulas in the equivalent format MO鈭橫2O3, to permitestimation of the metal鈥檚 two oxidation states.)

(a) Sc2O3

(b) TiO2

(c) V2O5

(d) CrO3

(e) MnO2

(f) Fe3O4

(g) Co3O4

(h) NiO

(i) Cu2O
See all solutions

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