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Chapter 5: Q6E (page 268)

Question: How much heat, in joules and in calories, must be added to a 75.0鈥揼 iron block with a specific heat of 0.449 J/g 掳C to increase its temperature from 25 掳C to its melting temperature of 1535 掳C?

Short Answer

Expert verified

The heat required to raise the temperature in joules = 50,849 J

The heat required to raise the temperature in calories = 12,147 calories

Step by step solution

01

Step 1: Specific heat

The heat required (Q) to raise the temperature of a substance is given by the formula Q = C 脳 m 脳鈭� T,where 鈥淐鈥� is the specific heat of the substance, 鈥渕鈥� is the mass of the substance, and 鈥溾垎T鈥� is the change in the temperature of the substance.

02

Calculation of heat in Joules

We know from the given details that:

C = 0.449 J/g 掳C

m = 75 g

T = change in temperature =Tfinal - Tinitial = 15350C 鈥� 250C = 15100C

By putting the values above in the equation Q = C 脳 m 脳 鈭� T, we get:

Q = 75 脳 0.449 脳 1510 = 50,849 J.

The heat required to raise the temperature of 75 g of iron block = 50,849 J

03

Calculation of heat in calories

Also,

1 calorie = 4.184 J.

The heat required to raise the temperature in calories =\(\frac{{50,849}}{{4.186}} = 12147.39cal\)

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