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Chapter 5: Q41 E (page 270)

Calculate the enthalpy of solution (鈭咹) for the dissolution) per mole of NH4NO3 under the conditions described in example 5.6.

Short Answer

Expert verified

The enthalpy of a solution (鈭咹 for dissolution) per mole of NH4NO3is 25 kJ/mol.

Step by step solution

01

Given data

  • The given mass of NH4NO3is 3.21g.
  • The heat of the reaction is q= +1.0 kJ (from example 5.6).
02

Calculation of enthalpy of the solution

The number of moles of NH4NO3 is calculated as:

\begin{aligned}Numberofmoles=\frac{{3.21g}}{{80.043g/mol}}\\=0.04mol\end{aligned}

Therefore, the enthalpy of the reaction can be determined by the formula:

Enthalpy = Heatofthereaction(q)/no.of moles

The known values are substituted:

\begin{aligned}enthalpy=\frac{{1.0kJ}}{{0.04mol}}\\=25kJ/mol\end{aligned}

Hence, 鈭咹 = 25 kJ/mol.

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