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Chapter 11: Question 60 E (page 649)

The osmotic pressure of a solution containing 7.0 g of insulin per litre is 23 torr at 25 °C. What is the molar mass of insulin?

Short Answer

Expert verified

The Molar Mass of Insulin

\({\rm{ = }}\;{\rm{5}}{\rm{.7 \times 1}}{{\rm{0}}^{\rm{3}}}{\rm{g mo}}{{\rm{l}}^{{\rm{-1}}}}\)

Step by step solution

01

Definition

Osmotic pressure can be defined as the minimum pressure that must be applied to a solution to halt the flow of solvent molecules through a semipermeable membrane (osmosis).

Molar Mass may be defined as the ratio of Mass and Molar Mass.

02

Explanation

First, since the ideal gas constant is in units of (L atm mol–1 ·°­â€“1), convert the osmotic pressure to atmospheres. For the same reason, convert the temperature from °C to kelvin.

\(\begin{aligned}{\rm{1}}\;{\rm{atm}} &= \;{\rm{760}}\;{\rm{torr}}\\\dfrac{{{\rm{23}}\;{\rm{torr}}\;{\rm{ \times 1}}\;{\rm{atm}}}}{{{\rm{760}}}} &= \;{\rm{0}}{\rm{.030}}\;{\rm{atm}}\end{aligned}\)

\(\begin{aligned}{\rm{M}} &= \;\dfrac{{\rm{\Pi }}}{{{\rm{RT}}}}\\{\rm{M}} &= \;\dfrac{{{\rm{0}}{\rm{.030}}\;{\rm{atm}}}}{{\left( {{\rm{0}}{\rm{.08206}}\;{\rm{L}}\;{\rm{atm}}\;{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}\;{{\rm{K}}^{{\rm{ - 1}}}}} \right){\rm{ \times }}\left( {{\rm{298}}{\rm{.15}}\;{\rm{K}}} \right)}}\\{\rm{M}} &= \;{\rm{1}}{\rm{.23 \times 1}}{{\rm{0}}^{{\rm{ - 3}}}}\;{\rm{M}}\end{aligned}\)

\(\begin{aligned}{\rm{Number}}\;{\rm{of}}\;{\rm{moles}} &= \;{\rm{mass \times volume}}\;{\rm{(in}}\;{\rm{liters)}}\\{\rm{Number}}\;{\rm{of}}\;{\rm{moles}} &= \;\left( {{\rm{1}}{\rm{.23 \times 1}}{{\rm{0}}^{{\rm{ - 3}}}}\;{\rm{M}}} \right)\left( {{\rm{1L}}} \right)\\{\rm{Number}}\;{\rm{of}}\;{\rm{moles}} &= \;{\rm{1}}{\rm{.23 \times 1}}{{\rm{0}}^{{\rm{ - 3}}}}\;{\rm{M}}\end{aligned}\)

\(\begin{aligned}{\rm{Number}}\;{\rm{of}}\;{\rm{moles}} &= \;\dfrac{{{\rm{Mass}}}}{{{\rm{Molar}}\;{\rm{Mass}}}}\\{\rm{1}}{\rm{.23 \times 1}}{{\rm{0}}^{{\rm{ - 3}}}}\;{\rm{M}} &= \;\dfrac{{{\rm{7}}\;{\rm{g}}}}{{{\rm{Molar}}\;{\rm{Mass}}}}\\{\rm{Molar}}\;{\rm{mass}} &= \;{\rm{5}}{\rm{.7 \times 1}}{{\rm{0}}^{\rm{3}}}\;{\rm{g}}\;{\rm{mol}}{{\rm{e}}^{{\rm{ - 1}}}}\end{aligned}\)

The Molar Mass of Insulin \({\rm{ = }}\;{\rm{5}}{\rm{.7 \times 1}}{{\rm{0}}^{\rm{3}}}{\rm{g mo}}{{\rm{l}}^{{\rm{-1}}}}\) .

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Most popular questions from this chapter

Question: The vapor pressure of methanol, \({\bf{C}}{{\bf{H}}_{\bf{3}}}{\bf{OH}}\) , is 94 tor at 20 °C. The vapor pressure of ethanol,\({{\bf{C}}_{\bf{2}}}{{\bf{H}}_{\bf{5}}}{\bf{OH}}\) , is 44 tor at the same temperature.

(a) Calculate the mole fraction of methanol and of ethanol in a solution of 50.0 g of methanol and 50.0 g of ethanol.

(b) Ethanol and methanol form a solution that behaves like an ideal solution. Calculate the vapor pressure of methanol and of ethanol above the solution at 20 °C.

(c) Calculate the mole fraction of methanol and of ethanol in the vapor above the solution.

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