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Chapter 18: Q92 E (page 1047)

Which is the stronger acid,\({\rm{NaHS}}{{\rm{O}}_3}\)or\({\rm{NaHS}}{{\rm{O}}_4}\)?

Short Answer

Expert verified


\({\rm{NaHS}}{{\rm{O}}_4}\) is the stronger acid.

Step by step solution

01

To find the stronger acid.

\({\rm{NaHS}}{{\rm{O}}_4}\)is a salt of stronger acid and therefore a stronger acid.

Reasoning is the one double bonded oxygen atom more on the sulfur atom which in unprotonated state helps with delocalization of electron, making a\(SO_4^{2 - }\)ion more stable than the\(SO_3^{2 - }\)ion.
Dissolution of the salt:\({\rm{NaHS}}{{\rm{O}}_4}(s) \to {\rm{N}}{{\rm{a}}^ + }(aq) + {\rm{HSO}}_4^ - (aq)\).
Deprotonation of acidic ion: \({\rm{HSO}}_4^ - (aq) + {{\rm{H}}_2}{\rm{O}}({\rm{l}}) \to {\rm{SO}}_4^{2 - }(aq) + {{\rm{H}}_3}{{\rm{O}}^ + }(aq)\).

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Most popular questions from this chapter

Suppose you discovered a diamond completely encased in a silicate rock. How would you chemically free the diamond without harming it?

What volume of \(0.250{\rm{M }}{{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}\) solution is required to neutralize a solution that contains \(5.00\;{\rm{g}}\) of \({\rm{CaC}}{{\rm{O}}_3}\)?

Carbon forms the \({\rm{CO}}_{\rm{3}}^{{\rm{2 - }}}\)ion, yet silicon does not form an analogous \({\rm{SiO}}_{\rm{3}}^{{\rm{2 - }}}\)ion. Why?

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Write balanced chemical equations for the following reactions:

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(c) aluminum heated in hydrogen bromide gas

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