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How would the graph in Figure \({\rm{9}}{\rm{.13}}\) change if the number of moles of gas in the sample used to determine the curve were doubled?

Short Answer

Expert verified

The curve would have the same shape as before, but it would be higher up and to the right.

Step by step solution

01

Defining amole

A mole is used to describe amounts that cannot be quantified in gramsor milligrams. As a result, a mole is a unit of measurement for a number of atoms, ions, or molecules.

02

Explanation

If the temperature and numberof gas molecules remain constant, Boyle's law asserts that the pressure and volume of the gas are inversely proportional. This can be written as

\({{\rm{p}}_{\rm{1}}}{{\rm{V}}_{\rm{1}}}{\rm{ = }}{{\rm{p}}_{\rm{2}}}{{\rm{V}}_{\rm{2}}}\).

The beauty of this connection (Avogadro's law) is that if we double the number of molecules, our initial volume will be greater.

\({\rm{n = }}\frac{{\rm{V}}}{{{{\rm{V}}_{\rm{m}}}}}\).

Here,\({{\rm{V}}_{\rm{m}}}\)is the molar volume determined at a given pressure and temperature. This means that we will have a larger beginning volume, but according to Boyle's rule, the change in volume is still inversely proportional to the change in pressure.

Therefore, the curve would have the same shape as before, but it would be relocated to the right and higher up.

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Most popular questions from this chapter

Question: For which of the following gases should the correction for the molecular volume be largest: \({\rm{CO, C}}{{\rm{O}}_{\rm{2}}}{\rm{, }}{{\rm{H}}_{\rm{2}}}{\rm{, He, N}}{{\rm{H}}_{\rm{3}}}{\rm{, S}}{{\rm{F}}_{\rm{6}}}\)?

Question: A gas of unknown identity diffuses at a rate of 83.3 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate of 102 mL/s. Calculate the molecular mass of the unknown gas.

Ethanol, C2H5OH,is produced industrially from ethylene, C2H4, by the following sequence of reactions:

\begin{aligned}{\rm{3}}{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}{\rm{+2}}{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}\to{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{HS}}{{\rm{O}}_{\rm{4}}}{\rm{+(}}{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{{\rm{)}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}\\{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{HS}}{{\rm{O}}_{\rm{4}}}{\rm{ +(}}{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{{\rm{)}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}{\rm{+3}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\to{\rm{3}}{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{5}}}{\rm{OH + 2}}{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}} \end{aligned}

What volume of ethylene at STP is required to produce 1000 metric tons (1000kg) of ethanol if the overall yield of ethanol is 90.1%?

While resting, the average\({\rm{70 - kg}}\)human male consumes \(14\;{\rm{L}}\) of pure \({{\rm{O}}_2}\) per hour at \({25^\circ }{\rm{C}}\)and \({\rm{100 kPa}}\). How many moles of \({{\rm{O}}_2}\)are consumed by a \({\rm{70\;kg}}\)man while resting for \({\rm{1}}{\rm{.0\;h}}\)?

Question: The distribution of molecular velocities in a sample of helium is shown in Figure \({\rm{9}}{\rm{.34}}\). If the sample is cooled, will the distribution of velocities look more like that of \({{\rm{H}}_{\rm{2}}}\) or of \({{\rm{H}}_{\rm{2}}}{\rm{O}}\)? Explain your answer.

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