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Chapter 9: Q14 E (page 506)

The pressure of a sample of gas is measured with an open-end manometer, partially shown to the right. The liquid in the manometer is mercury. Assuming atmospheric pressure is 29.92 in. Hg, determine the pressure of the gas in: (a) torr (b) Pa (c) bar.


Short Answer

Expert verified
  1. Pressure = 864.77 Torr
  2. Pressure = 112,893.06 Pa
  3. Pressure = 0.11287 bar

Step by step solution

01

Define pressure

The force applied perpendicular to an object's surface per unit area across which that force is spread is known as pressure.

02

Converting mm of Hg pressure into Torr

In the given scenario, we have an open- end manometer

Px = pressure of gas + h

Py = P0

Pgas + h = P0

Pgas = P0 - h

P0= Atmospheric pressure

Pgas = gas pressure


P0 = 29.92 inches of Hg

h = 6 inches of Hg

Pgas = (P0 - h)

= (29.92 - 6) inches of Hg

= 23. 92 inches of Hg

Converting inch into mm

1 inch = 25.4 mm

23.92 inches of Hg = (23.92) 脳(25.4) mm of Hg

= 846.768 mm of Hg

a) Converting mm of Hg pressure into Torr

1mm of Hg = 1 Torr

846.77 mm of Hg = (846.77) 脳 (1) Torr

= 846.77 Torr

Therefore, the Pressure is 846.77 Torr

03

Converting mm of Hg pressure into Pa

Converting mm of Hg pressure into Pa

1mm of Hg = 133.322 Pa

846.77 mm of Hg = (846.77) 脳(133.322) Pa

= 112,893.06Pa

Therefore, the Pressure is 112,893.06Pa

04

Converting mm of Hg pressure into bar

Converting mm of Hg pressure into the bar

1mm of Hg = 0.001333 bar

846.77 mm of Hg = (846.77) 脳(0.001333) bar

= 0.11287bar

Therefore, Pressure is 0.11287 bar

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