/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} QCYL We can determine the relative ac... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

We can determine the relative acid strengths of NH4+ and HCN by comparing their ionization constants. The ionization constant of HCN is given in Appendix H as 4.9 × 10−10. The ionization constant of NH4+ is not listed, but the ionization constant of its conjugate base, NH3, is listed as 1.8 × 10−5. Determine the ionization constant of NH4+, and decide which is the stronger acid, HCN or NH4+.

Short Answer

Expert verified

An acid dissociation constant can be explained as numerical measure of strength of acids in the solution. It is given by formulae.

\(\begin{aligned}{}HA \rightleftharpoons \;\;\;\;H\; + \;{A^ - }\\Ka\; = \;\frac{{\left[ {{A^ - }} \right]\;\left[ {{H^ + }} \right]\;}}{{\left[ {HA} \right]}}\end{aligned}\)

Step by step solution

01

calculating Ka

Ka value of ammonia is calculated as follows

\(\begin{array}{l}{K_a} of HCN = 4.9 \times 1{0^{ - 10}}\;\\{K_b}(N{H_3}) = 1.8 \times 1{0^{ - 5}}\\{K_a}(N{H_4}^ + ) = 5.6 \times 1{0^{ - 10}}\end{array}\)

As Ka of \(N{H_4}^ + \) is greater than \(HCN\). hence \(N{H_4}^ + \) is strong acid

02

Final answer

NH4+ is strong acid

Thus, ammonium ion is considered as strong acid

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.